Radôstka
Radôstka is a village and municipality in Čadca District in the Žilina Region of northern Slovakia.
Location of Čadca District in the Žilina Region
History
In historical records the village was first mentioned in 1662.
Geography
The municipality lies at an altitude of 487 metres and covers an area of 13.172 km². It has a population of about 886 people.
gollark: Want another?
gollark: See, this is perfect and without flaw except that the time requirement to make the regex seems to increase exponentially due to greenery.
gollark: Here you go, `b(d(e(e(io|oi)|i(eo|oe)|o(ei|ie))|i(e(eo|oe)|oe{2})|o(e(ei|ie)|ie{2}))|e(d(e(io|oi)|i(eo|oe)|o(ei|ie))|e(d(io|oi)|i(do|od)|o(di|id))|i(d(eo|oe)|e(do|od)|o(de|ed))|o(d(ei|ie)|e(di|id)|i(de|ed)))|i(d(e(eo|oe)|oe{2})|e(d(eo|oe)|e(do|od)|o(de|ed))|o(de{2}|e(de|ed)))|o(d(e(ei|ie)|ie{2})|e(d(ei|ie)|e(di|id)|i(de|ed))|i(de{2}|e(de|ed))))|d(b(e(e(io|oi)|i(eo|oe)|o(ei|ie))|i(e(eo|oe)|oe{2})|o(e(ei|ie)|ie{2}))|e(b(e(io|oi)|i(eo|oe)|o(ei|ie))|e(b(io|oi)|i(bo|ob)|o(bi|ib))|i(b(eo|oe)|e(bo|ob)|o(be|eb))|o(b(ei|ie)|e(bi|ib)|i(be|eb)))|i(b(e(eo|oe)|oe{2})|e(b(eo|oe)|e(bo|ob)|o(be|eb))|o(be{2}|e(be|eb)))|o(b(e(ei|ie)|ie{2})|e(b(ei|ie)|e(bi|ib)|i(be|eb))|i(be{2}|e(be|eb))))|e(b(d(e(io|oi)|i(eo|oe)|o(ei|ie))|e(d(io|oi)|i(do|od)|o(di|id))|i(d(eo|oe)|e(do|od)|o(de|ed))|o(d(ei|ie)|e(di|id)|i(de|ed)))|d(b(e(io|oi)|i(eo|oe)|o(ei|ie))|e(b(io|oi)|i(bo|ob)|o(bi|ib))|i(b(eo|oe)|e(bo|ob)|o(be|eb))|o(b(ei|ie)|e(bi|ib)|i(be|eb)))|e(b(d(io|oi)|i(do|od)|o(di|id))|d(b(io|oi)|i(bo|ob)|o(bi|ib))|i(b(do|od)|d(bo|ob)|o(bd|db))|o(b(di|id)|d(bi|ib)|i(bd|db)))|i(b(d(eo|oe)|e(do|od)|o(de|ed))|d(b(eo|oe)|e(bo|ob)|o(be|eb))|e(b(do|od)|d(bo|ob)|o(bd|db))|o(b(de|ed)|d(be|eb)|e(bd|db)))|o(b(d(ei|ie)|e(di|id)|i(de|ed))|d(b(ei|ie)|e(bi|ib)|i(be|eb))|e(b(di|id)|d(bi|ib)|i(bd|db))|i(b(de|ed)|d(be|eb)|e(bd|db))))|i(b(d(e(eo|oe)|oe{2})|e(d(eo|oe)|e(do|od)|o(de|ed))|o(de{2}|e(de|ed)))|d(b(e(eo|oe)|oe{2})|e(b(eo|oe)|e(bo|ob)|o(be|eb))|o(be{2}|e(be|eb)))|e(b(d(eo|oe)|e(do|od)|o(de|ed))|d(b(eo|oe)|e(bo|ob)|o(be|eb))|e(b(do|od)|d(bo|ob)|o(bd|db))|o(b(de|ed)|d(be|eb)|e(bd|db)))|o(b(de{2}|e(de|ed))|d(be{2}|e(be|eb))|e(b(de|ed)|d(be|eb)|e(bd|db))))|o(b(d(e(ei|ie)|ie{2})|e(d(ei|ie)|e(di|id)|i(de|ed))|i(de{2}|e(de|ed)))|d(b(e(ei|ie)|ie{2})|e(b(ei|ie)|e(bi|ib)|i(be|eb))|i(be{2}|e(be|eb)))|e(b(d(ei|ie)|e(di|id)|i(de|ed))|d(b(ei|ie)|e(bi|ib)|i(be|eb))|e(b(di|id)|d(bi|ib)|i(bd|db))|i(b(de|ed)|d(be|eb)|e(bd|db)))|i(b(de{2}|e(de|ed))|d(be{2}|e(be|eb))|e(b(de|ed)|d(be|eb)|e(bd|db))))` matches all anagrams of `beeoid`.
gollark: I'll run that test later™, I have to test my new `beeoid` anagram regex.
gollark: I don't think it's an optimal regex, but it's generated from the FSM.
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