Petra Cabrera (footballer)
Petra del Carmen Cabrera Díaz (born 19 May 1990) is a Venezuelan footballer who plays as a centre back for Brazilian club AE 3B da Amazônia and the Venezuela women's national team.
| Personal information | |||
|---|---|---|---|
| Full name | Petra del Carmen Cabrera Díaz[1] | ||
| Date of birth | 19 May 1990[1] | ||
| Place of birth | Carora, Venezuela[1] | ||
| Height | 1.68 m (5 ft 6 in)[1] | ||
| Playing position(s) | Centre back | ||
| Club information | |||
Current team | 3B da Amazônia | ||
| Senior career* | |||
| Years | Team | Apps | (Gls) |
| 2013–2015 | Trujillanos | ||
| 2016 | Flor de Patria | ||
| 2017 | La Equidad | ||
| 2018–2019 | Flor de Patria | ||
| 2020– | 3B da Amazônia | ||
| National team‡ | |||
| 2014– | Venezuela | 12 | (0) |
|
* Senior club appearances and goals counted for the domestic league only ‡ National team caps and goals correct as of 30 July 2018 | |||
International career
Cabrera played for Venezuela at senior level in two Copa América Femenina editions (2014 and 2018) and the 2018 Central American and Caribbean Games.[1]
gollark: Of course.
gollark: I'm not entirely sure how, but it seems to construct a tree/maybe deterministic finite automaton/finite state machine/I don't know theoretical CS which matches anagrams and unmatches unanagrams.
gollark: ```pythonimport collectionsdef do_thing(s): if len(s) == 1: return { s[0]: True } out = {} for i, c in enumerate(s): without = s[:i] + s[i + 1:] things = do_thing(without) out[c] = things return outdef match(r, s): print(r) c = r for i, x in enumerate(s): print(x) try: c = c[x] if c == True: if i + 1 == len(s): return True # full match else: return False # characters remain except KeyError: return False # no match return False # incomplete matchentry = lambda a, b: match(do_thing(a.lower().replace(" ", "")), b.lower().replace(" ", ""))```Here is my entry (pending a port to osmarkslisp™️). This is definitely my entry.
gollark: I wish to use Mathematica in my code. Please install it. DO NOT READ, ubq.
gollark: I have a "great" way to do this which I think takes O(n²) space-time-beeite.
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