John Harties Brown

Captain John Harties Brown (1834 to January 30, 1905[1]) was a Canadian soldier who fought in the American Civil War. Brown received the United States' highest award for bravery during combat, the Medal of Honor, for his action during the Second Battle of Franklin in Tennessee on 30 November 1864. He was honored with the award on 13 February 1865.[1][2][3][4][5]

John Harties Brown
Born1834
New Brunswick, Canada
DiedJanuary 30, 1905
Buried
AllegianceUnited States of America
Service/branchUnited States Army
Years of service1861, 1862 - 1865
RankCaptain
Unit 12th Regiment Kentucky Volunteer Infantry
Battles/warsSecond Battle of Franklin
American Civil War
Awards Medal of Honor

Biography

John Brown was born in New Brunswick in 1834. He initially joined the 5th Massachusetts Infantry from Charlestown, Massachusetts in April 1861, mustering out the following July.[6] He joined the 36th Massachusetts Infantry as a sergeant in July 1862.[7] In August 1863, he was commissioned as a Captain with the 12th Kentucky Infantry, and mustered out with this regiment in July 1865.[8] John Brown was buried in Arlington National Cemetery.[1]

Medal of Honor citation

Capture of flag.[1][2][3]

gollark: The resistor behaves ohmically and the current through both things is the same.
gollark: IIRC, if we assume the LED is an ideal diode, it'll just always have a 2V potential difference across it (if there's more than 2V in the circuit and also it is the right way round oops).
gollark: Well, that would actually have been right if you used the right units then added 2, possibly.
gollark: Not just... multiply... them?
gollark: I'm pretty sure you'd have to work out what voltage across the resistor would give you 20mA through it, then add 2 to it for the LED.

See also

References

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