Graig-y-Rhacca
Graig-y-Rhacca is a housing estate bordering Trethomas, Bedwas and Machen in the borough of Caerphilly, southeastern Wales. The town is about 8 miles to the west of Newport and 4 miles to the east of Caerphilly. The town mainly consists of local authority tenancies and privately owned estates.
Graig-y-Rhacca | |
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![]() Road to Graig-y-Rhacca | |
Population | 1,263 |
Principal area |
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Ceremonial county | |
Country | Wales |
Sovereign state | United Kingdom |
Post town | CAERPHILLY |
Postcode district | CF83 |
Dialling code | 029 |
Police | Gwent |
Fire | South Wales |
Ambulance | Welsh |
UK Parliament | |
Population
The median age of the town is 40 as of the 2011 census. The biggest age group in the town is 49-59 year old's with 20% of the population. 96.7% of the population are from the United Kingdom with only 1.2% from outside of the EU; compared to 3.3% in Wales.
gollark: `b(e(sä|äs)|s(eä|äe)|ä(es|se))|e(b(sä|äs)|s(bä|äb)|ä(bs|sb))|s(b(eä|äe)|e(bä|äb)|ä(be|eb))|ä(b(es|se)|e(bs|sb)|s(be|eb))`
gollark: Want another?
gollark: See, this is perfect and without flaw except that the time requirement to make the regex seems to increase exponentially due to greenery.
gollark: Here you go, `b(d(e(e(io|oi)|i(eo|oe)|o(ei|ie))|i(e(eo|oe)|oe{2})|o(e(ei|ie)|ie{2}))|e(d(e(io|oi)|i(eo|oe)|o(ei|ie))|e(d(io|oi)|i(do|od)|o(di|id))|i(d(eo|oe)|e(do|od)|o(de|ed))|o(d(ei|ie)|e(di|id)|i(de|ed)))|i(d(e(eo|oe)|oe{2})|e(d(eo|oe)|e(do|od)|o(de|ed))|o(de{2}|e(de|ed)))|o(d(e(ei|ie)|ie{2})|e(d(ei|ie)|e(di|id)|i(de|ed))|i(de{2}|e(de|ed))))|d(b(e(e(io|oi)|i(eo|oe)|o(ei|ie))|i(e(eo|oe)|oe{2})|o(e(ei|ie)|ie{2}))|e(b(e(io|oi)|i(eo|oe)|o(ei|ie))|e(b(io|oi)|i(bo|ob)|o(bi|ib))|i(b(eo|oe)|e(bo|ob)|o(be|eb))|o(b(ei|ie)|e(bi|ib)|i(be|eb)))|i(b(e(eo|oe)|oe{2})|e(b(eo|oe)|e(bo|ob)|o(be|eb))|o(be{2}|e(be|eb)))|o(b(e(ei|ie)|ie{2})|e(b(ei|ie)|e(bi|ib)|i(be|eb))|i(be{2}|e(be|eb))))|e(b(d(e(io|oi)|i(eo|oe)|o(ei|ie))|e(d(io|oi)|i(do|od)|o(di|id))|i(d(eo|oe)|e(do|od)|o(de|ed))|o(d(ei|ie)|e(di|id)|i(de|ed)))|d(b(e(io|oi)|i(eo|oe)|o(ei|ie))|e(b(io|oi)|i(bo|ob)|o(bi|ib))|i(b(eo|oe)|e(bo|ob)|o(be|eb))|o(b(ei|ie)|e(bi|ib)|i(be|eb)))|e(b(d(io|oi)|i(do|od)|o(di|id))|d(b(io|oi)|i(bo|ob)|o(bi|ib))|i(b(do|od)|d(bo|ob)|o(bd|db))|o(b(di|id)|d(bi|ib)|i(bd|db)))|i(b(d(eo|oe)|e(do|od)|o(de|ed))|d(b(eo|oe)|e(bo|ob)|o(be|eb))|e(b(do|od)|d(bo|ob)|o(bd|db))|o(b(de|ed)|d(be|eb)|e(bd|db)))|o(b(d(ei|ie)|e(di|id)|i(de|ed))|d(b(ei|ie)|e(bi|ib)|i(be|eb))|e(b(di|id)|d(bi|ib)|i(bd|db))|i(b(de|ed)|d(be|eb)|e(bd|db))))|i(b(d(e(eo|oe)|oe{2})|e(d(eo|oe)|e(do|od)|o(de|ed))|o(de{2}|e(de|ed)))|d(b(e(eo|oe)|oe{2})|e(b(eo|oe)|e(bo|ob)|o(be|eb))|o(be{2}|e(be|eb)))|e(b(d(eo|oe)|e(do|od)|o(de|ed))|d(b(eo|oe)|e(bo|ob)|o(be|eb))|e(b(do|od)|d(bo|ob)|o(bd|db))|o(b(de|ed)|d(be|eb)|e(bd|db)))|o(b(de{2}|e(de|ed))|d(be{2}|e(be|eb))|e(b(de|ed)|d(be|eb)|e(bd|db))))|o(b(d(e(ei|ie)|ie{2})|e(d(ei|ie)|e(di|id)|i(de|ed))|i(de{2}|e(de|ed)))|d(b(e(ei|ie)|ie{2})|e(b(ei|ie)|e(bi|ib)|i(be|eb))|i(be{2}|e(be|eb)))|e(b(d(ei|ie)|e(di|id)|i(de|ed))|d(b(ei|ie)|e(bi|ib)|i(be|eb))|e(b(di|id)|d(bi|ib)|i(bd|db))|i(b(de|ed)|d(be|eb)|e(bd|db)))|i(b(de{2}|e(de|ed))|d(be{2}|e(be|eb))|e(b(de|ed)|d(be|eb)|e(bd|db))))` matches all anagrams of `beeoid`.
gollark: I'll run that test later™, I have to test my new `beeoid` anagram regex.
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