Aneta Lédlová
Aneta Lédlová (born 31 December 1996) is a Czech ice hockey player for AIK IF and the Czech national team.[1]
Aneta Lédlová | |||
---|---|---|---|
Born |
Kadaň, Czech Republic | 31 December 1996||
Height | 1.70 m (5 ft 7 in) | ||
Weight | 77 kg (170 lb; 12 st 2 lb) | ||
Position | Forward | ||
Shoots | Left | ||
SWHL team Former teams |
AIK IF HC Litvinov HC Slavia Praha Robert Morris Colonials | ||
National team |
| ||
Playing career | 2012–present |
She participated at the 2016,2017 and 2019 IIHF Women's World Championships.[2][3]
Career
Note: Does not include current in-progress season per Wikipedia statistics policy.
Season | Team | League | GP | G | A | Pts | PIM |
2011–2012 | Czech Republic U18 | World Junior Classic-18 | 5 | 0 | 2 | 2 | 2 |
2012–2013 | Czech Republic U18 | World Junior Classic-18 | 6 | 1 | 2 | 3 | 10 |
Czech Republic | Olympic Qualifiers | 3 | 3 | 0 | 3 | 0 | |
Czech Republic | World Cup | 5 | 0 | 2 | 2 | 0 | |
2013–2014 | Czech Republic U18 | World Junior Classic-18 | 6 | 2 | 0 | 2 | 8 |
Czech Republic | World Cup | 5 | 1 | 0 | 1 | 2 | |
2014–2015 | Czech Republic | World Cup Qualifying | 3 | 0 | 0 | 0 | 0 |
Czech Republic | World Cup | 5 | 2 | 2 | 4 | 2 | |
2015–2016 | Czech Republic | World Cup | 5 | 1 | 0 | 1 | 4 |
2016–2017 | Robert Morris | NCAA College Hockey America | 31 | 5 | 4 | 9 | 20 |
Czech Republic | Olympic Qualifiers | 3 | 2 | 1 | 3 | 0 | |
Czech Republic | World Cup | 6 | 3 | 3 | 6 | 12 | |
2017–2018 | Robert Morris | NCAA College Hockey America | 23 | 2 | 7 | 9 | 10 |
2018–2019 | AIK | SDHL | 39 | 11 | 8 | 19 | 51 |
Czech Republic | World Cup | 5 | 1 | 0 | 1 | 2 | |
Czech Republic (National Team) Total | 57 | 16 | 12 | 28 | 42 | ||
Robert Morris University Total | 54 | 7 | 11 | 18 | 30 | ||
AIK Total | 39 | 11 | 8 | 19 | 51 | ||
Career Total | 150 | 34 | 31 | 65 | 123 |
gollark: It wants something in terms of p and q, so just simplify it a bit.
gollark: Although I don't know why you can't long-divide it, p and q are just constants for the purposes of that.
gollark: That lets you work out a/b/c/d, which you can substitute back into (x-1)(ax^3+bx^2+cx+d).
gollark: So:2 = a (x^4 terms)p = b - a (x^3 terms)-6 = c - b (x^2 terms)q = d - c (x terms)6 = -d (constant terms)
gollark: So you can do `2x^4+ px^3 - 6x^2 + qx + 6 = ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d`, and you know the coefficients on x^4 and so on should be equal.
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