2019 Thoreau Tennis Open – Doubles

Angela Kulikov and Rianna Valdes won the title, defeating Elizabeth Halbauer and Ingrid Neel in the final, 7–6^(7–3), 4–6, [17–15].

Doubles
2019 Thoreau Tennis Open
Champions	Angela Kulikov Rianna Valdes
Runners-up	Elizabeth Halbauer Ingrid Neel
Final score	7–6^(7–3), 4–6, [17–15]

Main article: 2019 Thoreau Tennis Open

This was the first edition of the tournament.[1]

Seeds

1. Danka Kovinić / Nina Stojanović (Quarterfinals)
2. Bibiane Schoofs / Yanina Wickmayer (Quarterfinals)
3. Chen Pei-hsuan / Hsieh Yu-chieh (Semifinals)
4. Olga Govortsova / Valeria Savinykh (Semifinals)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

Draw

	First Round							Quarterfinals							Semifinals							Final
	1	D Kovinić N Stojanović	6	6
		M Mateas P Udvardy	2	4				1	D Kovinić N Stojanović	3	3
		E Halbauer I Neel	6	6					E Halbauer I Neel	6	6
		K Fahey M Westby	1	4												E Halbauer I Neel	7^7	7^7
	4	O Govortsova V Savinykh	6^8	7	[10]										4	O Govortsova V Savinykh	6^3	6^4
		A Bondár P Ormaechea	7^10	5	[1]			4	O Govortsova V Savinykh	5	6	[10]
		Z Hives B Woolcock	6	2	[5]				S Marand C Whoriskey	7	4	[6]
		S Marand C Whoriskey	3	6	[10]																		E Halbauer I Neel	6^3	6	[15]
	WC	B Collens N Semenovski	2	1																		WC	A Kulikov R Valdes	7^7	4	[17]
		S Xu X You	6	6					S Xu X You	1	2
		M Bolkvadze E Gorgodze	7^7	5	[4]			3	P-h Chen Y-c Hsieh	6	6
	3	P-h Chen Y-c Hsieh	6^4	7	[10]										3	P-h Chen Y-c Hsieh	2	4
		S Chang A Mueller	3	2											WC	A Kulikov R Valdes	6	6
	WC	A Kulikov R Valdes	6	6				WC	A Kulikov R Valdes	7	4	[10]
	WC	E Campbell A Robins	2	0				2	B Schoofs Y Wickmayer	5	6	[7]
	2	B Schoofs Y Wickmayer	6	6

References

• Main Draw

1. "W60 Concord". www.itftennis.com.