2019 Surbiton Trophy – Women's Doubles

Jessica Moore and Ellen Perez were the defending champions, but chose to participate with different partners. Moore partnered alongside Monique Adamczak but lost in the first round to Viktorija Golubic and Ingrid Neel. Perez partnered alongside Arina Rodionova but lost in the first round to Naiktha Bains and Naomi Broady.[1]

Women's Doubles
2019 Surbiton Trophy
Champions Jennifer Brady
Caroline Dolehide
Runners-up Heather Watson
Yanina Wickmayer
Final score6–3, 6–4

Jennifer Brady and Caroline Dolehide won the title, defeating Heather Watson and Yanina Wickmayer in the final, 6–3, 6–4.

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 A Muhammad
G Olmos
3 77 [10]
  S Santamaria
L Stefani
6 65 [6] 1 A Muhammad
G Olmos
63 3
  J Brady
C Dolehide
6 6 J Brady
C Dolehide
77 6
WC SB Grey
E Silva
4 4 J Brady
C Dolehide
6 6
3 A Blinkova
O Kalashnikova
3 63 M Brengle
S Vickery
2 2
  M Brengle
S Vickery
6 77 M Brengle
S Vickery
w/o
  A Guarachi
E Routliffe
64 6 [4] WC K Dunne
E Webley-Smith
WC K Dunne
E Webley-Smith
77 2 [10] J Brady
C Dolehide
6 6
  H Watson
Y Wickmayer
6 5 [10] H Watson
Y Wickmayer
3 4
  Q Gleason
M Sanchez
3 7 [5] H Watson
Y Wickmayer
6 3 [10]
WC N Bains
N Broady
6 6 WC N Bains
N Broady
4 6 [8]
4 E Perez
Ar Rodionova
4 1 H Watson
Y Wickmayer
4 6 [11]
  M Kato
L Zhu
2 3 I Jorović
T Smitková
6 3 [9]
  I Jorović
T Smitková
6 6 I Jorović
T Smitková
77 6
  V Golubic
I Neel
2 6 [10] V Golubic
I Neel
65 4
2 M Adamczak
J Moore
6 3 [7]
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References

  1. "W100 Surbiton". www.itftennis.com.
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