2019 San Benedetto Tennis Cup – Doubles
Julian Ocleppo and Andrea Vavassori were the defending champions but only Vavassori chose to defend his title, partnering Andrea Pellegrino.[1] Vavassori lost in the semifinals to Ivan and Matej Sabanov.
Doubles | |
---|---|
2019 San Benedetto Tennis Cup | |
Champions | |
Runners-up | |
Final score | 6–4, 4–6, [10–5] |
Sabanov and Sabanov won the title after defeating Sergio Galdós and Juan Pablo Varillas 6–4, 4–6, [10–5] in the final.
Seeds
Andrea Pellegrino / Andrea Vavassori (Semifinals) Andreas Siljeström / Szymon Walków (Semifinals) Emilio Gómez / Luis David Martínez (First round, withdrew) Sergio Galdós / Juan Pablo Varillas (Final)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 6 | |||||||||||||||||||||||||
w/o | 4 | 2 | |||||||||||||||||||||||||
1 | 6 | 4 | [10] | ||||||||||||||||||||||||
3 | 3 | 6 | [12] | ||||||||||||||||||||||||
w/o | 6 | 6 | |||||||||||||||||||||||||
WC | 3 | 6 | [8] | 1 | 2 | ||||||||||||||||||||||
6 | 4 | [10] | 6 | 4 | [10] | ||||||||||||||||||||||
6 | 3 | [9] | 4 | 4 | 6 | [5] | |||||||||||||||||||||
ITF | 1 | 6 | [4]r | 0 | 4 | ||||||||||||||||||||||
ITF | 6 | 3 | [7] | 4 | 6 | 6 | |||||||||||||||||||||
4 | 1 | 6 | [10] | 4 | 4 | 6 | [10] | ||||||||||||||||||||
7 | 7 | 2 | 6 | 1 | [6] | ||||||||||||||||||||||
5 | 5 | 5 | 3 | ||||||||||||||||||||||||
WC | 4 | 4 | 2 | 7 | 6 | ||||||||||||||||||||||
2 | 6 | 6 |
gollark: ```c#define let int#define var char#include <stdlib.h>#include <stdio.h>let main() { for (let i = 0; i < 10000; i++) { var* j = malloc(i); j = "bees"; free(j); } var* lyricLy_bad = malloc(3); printf("%s", lyricLy_bad);}```
gollark: It's only 1e5 times.
gollark: tio!debug
gollark: ```c#define let int#define var char#include <stdlib.h>#include <stdio.h>let main() { for (let i = 0; i < 10000; i++) { var* j = malloc(i); *j = "bees"; free(j); } var* lyricLy_bad = malloc(3); printf("%s", lyricLy_bad);}```
gollark: ah yes.
References
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