2019 Open Sud de France – Doubles

Ken and Neal Skupski were the defending champions,[1] but lost in the quarterfinals to Benjamin Bonzi and Antoine Hoang.

Doubles
2019 Open Sud de France
Champions	Ivan Dodig Édouard Roger-Vasselin
Runners-up	Benjamin Bonzi Antoine Hoang
Final score	6–4, 6–3

Main article: 2019 Open Sud de France

Ivan Dodig and Édouard Roger-Vasselin won the title, defeating Bonzi and Hoang in the final, 6–4, 6–3.

Seeds

1. Ivan Dodig / Édouard Roger-Vasselin (Champions)
2. Austin Krajicek / Artem Sitak (First round)
3. Ken Skupski / Neal Skupski (Quarterfinals)
4. Radu Albot / Marcel Granollers (Quarterfinals)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

Draw

	First Round							Quarterfinals							Semifinals							Final
	1	I Dodig É Roger-Vasselin	6	7
		D Kudla A Mies	1	5				1	I Dodig É Roger-Vasselin	6^6	6	[10]
		M Matkowski P Oswald	2	6	[10]				M Matkowski P Oswald	7^8	1	[7]
	PR	S Darcis D Goffin	6	1	[2]										1	I Dodig É Roger-Vasselin	6	7^7
	4	R Albot M Granollers	6	7^7												L Paes B Paire	3	6^3
		U Humbert N Mahut	4	6^3				4	R Albot M Granollers	1	4
		L Paes B Paire	6	6					L Paes B Paire	6	6
		J Eysseric G Simon	4	2																		1	I Dodig É Roger-Vasselin	6	6
	WC	C Lestienne L Pouille	4	3																		WC	B Bonzi A Hoang	4	3
	WC	B Bonzi A Hoang	6	6				WC	B Bonzi A Hoang	6	7
		R Lindstedt T Pütz	3	4				3	K Skupski N Skupski	2	5
	3	K Skupski N Skupski	6	6											WC	B Bonzi A Hoang	6	6
		H Nys D Shapovalov	6	6^5	[10]											L Bambridge J O'Mara	4	4
		J Chardy F Martin	4	7^7	[7]				H Nys D Shapovalov	6	5	[8]
		L Bambridge J O'Mara	6	6					L Bambridge J O'Mara	3	7	[10]
	2	A Krajicek A Sitak	4	2

References

1. "British brothers Ken and Neal Skupski win first ATP World Tour title together". BBC. 12 February 2018. Retrieved 2 February 2019.

• Main Draw