2019 Manchester Trophy – Singles
Ons Jabeur was the defending champion, but chose to participate in Rosmalen instead.[1]
Singles | |
---|---|
2019 Manchester Trophy | |
Champion | ![]() |
Runner-up | ![]() |
Final score | 7–6(7–1), 2–6, 6–3 |
Magda Linette won the title, defeating Zarina Diyas in the final, 7–6(7–1), 2–6, 6–3.
Seeds
Magda Linette (Champion) Madison Brengle (Semifinals) Zarina Diyas (Final) Zhu Lin (First round) Misaki Doi (Second round) Anna Blinkova (Second round) Marie Bouzková (Second round) Whitney Osuigwe (Second round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Finals
Semifinals | Final | ||||||||||||
1 | ![]() | 6 | 6 | ||||||||||
Q | ![]() | 3 | 0 | ||||||||||
1 | ![]() | 77 | 2 | 6 | |||||||||
3 | ![]() | 61 | 6 | 3 | |||||||||
3 | ![]() | 6 | 7 | ||||||||||
2 | ![]() | 1 | 5 | ||||||||||
Top half
First Round | Second Round | Quarterfinals | Semifinals | ||||||||||||||||||||||||
1 | ![]() | 6 | 6 | ||||||||||||||||||||||||
![]() | 3 | 3 | 1 | ![]() | 77 | 4 | |||||||||||||||||||||
Q | ![]() | 6 | 3 | 5 | ![]() | 65 | 2r | ||||||||||||||||||||
![]() | 4 | 6 | 7 | 1 | ![]() | 6 | 7 | ||||||||||||||||||||
Q | ![]() | 6 | 5 | 3 | ![]() | 2 | 5 | ||||||||||||||||||||
![]() | 0 | 7 | 6 | ![]() | 6 | 6 | |||||||||||||||||||||
![]() | 1r | 8 | ![]() | 4 | 4 | ||||||||||||||||||||||
8 | ![]() | 2 | 1 | ![]() | 6 | 6 | |||||||||||||||||||||
4 | ![]() | 3 | 3 | Q | ![]() | 3 | 0 | ||||||||||||||||||||
WC | ![]() | 6 | 6 | WC | ![]() | 6 | 6 | ||||||||||||||||||||
WC | ![]() | 0 | 6 | 77 | WC | ![]() | 2 | 4 | |||||||||||||||||||
![]() | 6 | 4 | 64 | WC | ![]() | 64 | 2 | ||||||||||||||||||||
Q | ![]() | 6 | 77 | Q | ![]() | 77 | 6 | ||||||||||||||||||||
![]() | 3 | 61 | Q | ![]() | 7 | 6 | |||||||||||||||||||||
WC | ![]() | 3 | 1 | 7 | ![]() | 5 | 4 | ||||||||||||||||||||
7 | ![]() | 6 | 6 |
Bottom half
First Round | Second Round | Quarterfinals | Semifinals | ||||||||||||||||||||||||
5 | ![]() | 6 | 6 | ||||||||||||||||||||||||
![]() | 2 | 4 | 5 | ![]() | 2 | 6 | 3 | ||||||||||||||||||||
Q | ![]() | 3 | 2 | ![]() | 6 | 4 | 6 | ||||||||||||||||||||
![]() | 6 | 6 | ![]() | 61 | 2 | ||||||||||||||||||||||
![]() | 69 | 1 | 3 | ![]() | 77 | 6 | |||||||||||||||||||||
![]() | 711 | 6 | ![]() | 0 | 1 | ||||||||||||||||||||||
![]() | 3 | 4 | 3 | ![]() | 6 | 6 | |||||||||||||||||||||
3 | ![]() | 6 | 6 | 3 | ![]() | 6 | 7 | ||||||||||||||||||||
6 | ![]() | 6 | 6 | 2 | ![]() | 1 | 5 | ||||||||||||||||||||
![]() | 3 | 3 | 6 | ![]() | 6 | 4 | 4 | ||||||||||||||||||||
WC | ![]() | 1 | 3 | ![]() | 2 | 6 | 6 | ||||||||||||||||||||
![]() | 6 | 6 | ![]() | 1 | 1 | ||||||||||||||||||||||
Q | ![]() | 5 | 3 | 2 | ![]() | 6 | 6 | ||||||||||||||||||||
![]() | 7 | 6 | ![]() | 4 | 6 | 3 | |||||||||||||||||||||
Q | ![]() | 5 | 3 | 2 | ![]() | 6 | 4 | 6 | |||||||||||||||||||
2 | ![]() | 7 | 6 |
gollark: I am somewhat interested in doing so at this point.
gollark: Clearly the solution is to use rational numbers everywhere all the time instead?
gollark: Floating points do that all the time.
gollark: `is` is weird object equality, it doesn't really count.
gollark: It has integers as a distinct thing from floats, and they're bigints.
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