2019 Fukuoka International Women's Cup – Singles

Katie Boulter was the defending champion, but chose not to participate.[1]

Singles
2019 Fukuoka International Women's Cup
Champion	Heather Watson
Runner-up	Zarina Diyas
Final score	7–6^(7–1), 7–6^(7–4)

Heather Watson won the title, defeating Zarina Diyas in the final, 7–6^(7–1), 7–6^(7–4).

Seeds

Zarina Diyas (Final)
Heather Watson (Champion)
Ayano Shimizu (Quarterfinals)
Kristie Ahn (Semifinals, retired)
Liang En-shuo (Quarterfinals)
Rebecca Marino (Semifinals)
Momoko Kobori (Second round)
Jamie Loeb (First round)

Draw

Key

Finals

	Semifinals							Final


	1	Zarina Diyas	6	6

	6	Rebecca Marino	2	3
								1	Zarina Diyas	6¹	6⁴

								2	Heather Watson	7⁷	7⁷
	4	Kristie Ahn	3	2^r

	2	Heather Watson	6	2

Top half

	First Round							Second Round							Quarterfinals							Semifinals

	1	Z Diyas	5	6	6
		A Bai	7	3	2			1	Z Diyas	6	6
	WC	M Ayukawa	6	3	6			WC	M Ayukawa	1	0
		H Kaji	4	6	2										1	Z Diyas	6	6
	WC	M Uchijima	4	2												R Ozaki	0	2
		B Cengiz	6	6					B Cengiz	3	3
		R Ozaki	6	6⁷	6				R Ozaki	6	6
	8	J Loeb	1	7⁹	2																	1	Z Diyas	6	6
	3	A Shimizu	4	7⁷	6																	6	R Marino	2	3
	WC	Y Naito	6	6⁵	3			3	A Shimizu	2	7	6
		M Inglis	4						M Inglis	6	5	4
		K Dunne	3^r												3	A Shimizu	3	4
	Q	S Akita	6	2	6										6	R Marino	6	6
		S-j Jang	4	6	3			Q	S Akita	5	6³
	Q	M Hontama	1	1				6	R Marino	7	7⁷
	6	R Marino	6	6

Bottom half

	First Round							Second Round							Quarterfinals							Semifinals

	7	M Kobori	6	3	6
		K McPhee	4	6	3			7	M Kobori	6⁶	1
	Q	E Shibahara	4	3				Q	E Bektas	7⁸	6
	Q	E Bektas	6	6											Q	E Bektas	4	6	0
	WC	K Morisaki	2	5											4	K Ahn	6	3	6
		J Jakšić	6	7					J Jakšić	3	4
		E Hozumi	1	5				4	K Ahn	6	6
	4	K Ahn	6	7																		4	K Ahn	3	2^r
	5	E-s Liang	6⁵	7	6																	2	H Watson	6	2
		M Imanishi	7⁷	5	2			5	E-s Liang	6	6
		N Broady	6	7⁸					N Broady	3	3
		J Namigata	3	6⁶											5	E-s Liang	2	2
	Q	L Küng	6	6											2	H Watson	6	6
		H Kuwata	3	2				Q	L Küng	2	4
	Q	H Sakatsume	2	1				2	H Watson	6	6
	2	H Watson	6	6

gollark: e.g.```data Thing = Foo String | Bar Int```

gollark: Algebraic Data Type.

gollark: You could have an ADT as in functional languages, though.

gollark: Why would you need 2 variables per token in a static language?

gollark: y e s g o w i t h t h a t.

References

"W60 Fukuoka". www.itftennis.com.

Main Draw

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