2019 Challenger La Manche – Doubles
Romain Arneodo and Tristan-Samuel Weissborn were the defending champions but chose not to defend their title.
Doubles | |
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2019 Challenger La Manche | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 4–6, 7–6(7–4), [10–8] |
Robert Galloway and Nathaniel Lammons won the title after defeating Javier Barranco Cosano and Raúl Brancaccio 4–6, 7–6(7–4), [10–8] in the final.
Seeds
Jeevan Nedunchezhiyan / Purav Raja (Semifinals) Robert Galloway / Nathaniel Lammons (Champions) Luca Margaroli / David Vega Hernández (Quarterfinals) Andreas Siljeström / Szymon Walków (Quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
![]() ![]() | 3 | 2 | 1 | ![]() ![]() | w/o | ||||||||||||||||||||||
![]() ![]() | 7 | 6 | ![]() ![]() | ||||||||||||||||||||||||
WC | ![]() ![]() | 5 | 2 | 1 | ![]() ![]() | 4 | 6 | [6] | |||||||||||||||||||
4 | ![]() ![]() | 64 | 6 | [10] | ITF | ![]() ![]() | 6 | 3 | [10] | ||||||||||||||||||
![]() ![]() | 77 | 1 | [4] | 4 | ![]() ![]() | 4 | 64 | ||||||||||||||||||||
ITF | ![]() ![]() | 2 | 6 | [10] | ITF | ![]() ![]() | 6 | 77 | |||||||||||||||||||
ITF | ![]() ![]() | 6 | 4 | [7] | ITF | ![]() ![]() | 6 | 64 | [8] | ||||||||||||||||||
![]() ![]() | 6 | 4 | 2 | ![]() ![]() | 4 | 77 | [10] | ||||||||||||||||||||
WC | ![]() ![]() | 1 | 1r | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
3 | ![]() ![]() | 1 | 1 | ||||||||||||||||||||||||
![]() ![]() | 4 | 4 | |||||||||||||||||||||||||
2 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
Alt | ![]() ![]() | 4 | 1 | ||||||||||||||||||||||||
![]() ![]() | 77 | 3 | [8] | 2 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
2 | ![]() ![]() | 63 | 6 | [10] |
gollark: It's just "Lua".
gollark: Lua isn't an acronym by the way.
gollark: It's kind of unintuitive.
gollark: `a` is just one value, so the second return is discarded, so it works sensibly.
gollark: `gsub` actually returns multiple values. Because Lua, since it's the last thing passed to that function, `table.insert` is passed the string it returns and a number from it. `table.insert` has an overload where it takes `(table, position, value)` or something instead of `(table, value)`.
References
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