2019 Challenger Eckental – Doubles
Kevin Krawietz and Andreas Mies were the defending champions[1] but chose not to defend their title.
Doubles | |
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2019 Challenger Eckental | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 7–6(7–2), 6–4 |
Ken Skupski and John-Patrick Smith won the title after defeating Sander Arends and Roman Jebavý 7–6(7–2), 6–4 in the final.
Seeds
Sander Arends / Roman Jebavý (Final) Ken Skupski / John-Patrick Smith (Champions) Romain Arneodo / Andrei Vasilevski (First round) Jonathan Erlich / Denys Molchanov (Quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 7 | 6 | ||||||||||||||||||||||||
WC | ![]() ![]() | 5 | 3 | 1 | ![]() ![]() | 6 | 78 | ||||||||||||||||||||
![]() ![]() | 3 | 77 | [9] | ![]() ![]() | 2 | 66 | |||||||||||||||||||||
![]() ![]() | 6 | 65 | [11] | 1 | ![]() ![]() | 6 | 3 | [10] | |||||||||||||||||||
4 | ![]() ![]() | 711 | 77 | WC | ![]() ![]() | 4 | 6 | [7] | |||||||||||||||||||
PR | ![]() ![]() | 69 | 64 | 4 | ![]() ![]() | 2 | 4 | ||||||||||||||||||||
![]() ![]() | 4 | 68 | WC | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
WC | ![]() ![]() | 6 | 710 | 1 | ![]() ![]() | 62 | 4 | ||||||||||||||||||||
Alt | ![]() ![]() | 7 | 77 | 2 | ![]() ![]() | 77 | 6 | ||||||||||||||||||||
![]() ![]() | 5 | 65 | Alt | ![]() ![]() | 2 | 5 | |||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 6 | 7 | ||||||||||||||||||||||
3 | ![]() ![]() | 3 | 4 | ![]() ![]() | 64 | 6 | [7] | ||||||||||||||||||||
![]() ![]() | 6 | 6 | 2 | ![]() ![]() | 77 | 4 | [10] | ||||||||||||||||||||
![]() ![]() | 4 | 4 | ![]() ![]() | 2 | 77 | [3] | |||||||||||||||||||||
WC | ![]() ![]() | 1 | 2 | 2 | ![]() ![]() | 6 | 64 | [10] | |||||||||||||||||||
2 | ![]() ![]() | 6 | 6 |
gollark: If it was, we would have to deploy Fourier transforms or something.
gollark: But light isn't actually continuous in reality due to things.
gollark: Oh, those are already using optical phased arrays to track photon count in an arbitrary number of discrete frequency buckets.
gollark: I mean, a Fourier transform would allow bees to incurse into the frequency domain instead of the time domain.
gollark: Alternatively, something something Fourier transform of inbound light signal?
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