2017 Pekao Szczecin Open – Singles

Alessandro Giannessi was the defending champion but lost in the first round to Artem Smirnov.

Singles
2017 Pekao Szczecin Open
Champion Richard Gasquet
Runner-up Florian Mayer
Final score7–6(7–3), 7–6(7–4)

Richard Gasquet won the title after defeating Florian Mayer 7–6(7–3), 7–6(7–4) in the final.

Seeds

  1. Richard Gasquet (Champion)
  2. Florian Mayer (Final)
  3. Alessandro Giannessi (First round)
  4. Carlos Berlocq (First round)
  5. Marco Cecchinato (First round)
  6. Jerzy Janowicz (Quarterfinals)
  7. Casper Ruud (First round)
  8. Renzo Olivo (Second round)

Draw

Key

Finals

Semifinals Final
          
1/WC Richard Gasquet 6 6
Taro Daniel 4 4
1/WC Richard Gasquet 77 77
2 Florian Mayer 63 64
SE Jürgen Zopp 7 3 4
2 Florian Mayer 5 6 6

Top half

First Round Second Round Quarterfinals Semifinals
1/WC R Gasquet 6 6
WC M Gawron 3 0 1/WC R Gasquet 6 6
B Zapata Miralles 6 6 B Zapata Miralles 3 2
Q Robin Staněk 2 3 1/WC R Gasquet 4 77 6
G Andreozzi 77 6 G Andreozzi 6 62 4
WC K Drzewiecki 63 2 G Andreozzi 6 6
Í Cervantes 3 6 6 Í Cervantes 3 3
5 M Cecchinato 6 4 4 1/WC R Gasquet 6 6
4 C Berlocq 4 62 T Daniel 4 4
B Fratangelo 6 77 B Fratangelo 3 6 6
SE J Cagnina 4 6 6 SE J Cagnina 6 2 3
Q Maxime Tabatruong 6 3 2 B Fratangelo 3 2
T Daniel 6 6 T Daniel 6 6
WC Adrian Andrzejczuk 2 4 T Daniel 7 7
S Caruso 6 4 3 8 R Olivo 5 5
8 R Olivo 3 6 6

Bottom half

First Round Second Round Quarterfinals Semifinals
7 C Ruud 5 77 2
SE J Zopp 7 64 6 SE J Zopp 7 6
LL Marek Jaloviec 4 1 Y Maden 5 4
Y Maden 6 6 SE J Zopp 6 4 6
LL A Bury 3 4 D Brown 2 6 4
D Brown 6 6 D Brown 77 4 77
Q A Smirnov 77 6 Q A Smirnov 64 6 65
3 A Giannessi 64 1 SE J Zopp 7 3 4
6 J Janowicz 6 6 2 F Mayer 5 6 6
Q G Durán 4 1 6 J Janowicz 6 77
K de Schepper 7 6 K de Schepper 1 62
O Otte 5 2 6 J Janowicz 2 63
G Oliveira 3 6 6 2 F Mayer 6 77
LL C Lestienne 6 2 3 G Oliveira 4 4
G Sakharov 7 1 2 2 F Mayer 6 6
2 F Mayer 5 6 6
gollark: If you multiply the `(x-1)` by `(ax^3+bx^2+cx+d)` it should expand out into having an x^4 term.
gollark: I'm probably explaining this badly, hmmm.
gollark: Then set the x^4/x^3/x^2/x^1 coefficients and constant terms on each side to be equal and work out a/b/c/d.
gollark: Set it equal to `(x-1)(ax^3+bx^2+cx+d)` (the thing you know it's divisible by times the generalized cubic thingy), and expand that out/simplify.
gollark: It would be annoying and inconsistent if it was 0. It's 1.

References

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