2016 Torneo Internacional Challenger León – Singles

Austin Krajicek was the defending champion, but lost in the first round to Adrián Menéndez-Maceiras.

Singles
2016 Torneo Internacional Challenger León
Champion Michael Berrer
Runner-up João Souza
Final score6–3, 6–2

Michael Berrer won the title, defeating João Souza 6–3, 6–2 in the final.

Seeds

  1. Sam Groth (First round)
  2. Taylor Fritz (First round)
  3. Malek Jaziri (Quarterfinals, retired)
  4. Yūichi Sugita (First round)
  5. Austin Krajicek (First round)
  6. Michael Berrer (Champion)
  7. Stéphane Robert (First round)
  8. Tatsuma Ito (First round)

Draw

Key

Finals

Semifinals Final
          
6 Michael Berrer 6 5 6
Alt Daniel Nguyen 3 7 2
6 Michael Berrer 6 6
Alt João Souza 3 2
Alt João Souza 77 6
Q Caio Zampieri 63 4

Top Half

First Round Second Round Quarterfinals Semifinals
1 S Groth 63 6 4
A Ghem 77 2 6 A Ghem 7 6
A Falla 6 4 78 A Falla 5 4
SE M Arévalo 3 6 66 A Ghem 3 6 3
WC L Gómez 6 6 6 M Berrer 6 2 6
WC Alejandro Moreno 1 1 WC L Gómez 1 7 2
A Sarkissian 63 5 6 M Berrer 6 5 6
6 M Berrer 77 7 6 M Berrer 6 5 6
4 Y Sugita 5 1 Alt D Nguyen 3 7 2
SE P Krstin 7 6 SE P Krstin 1 2
Alt P Cachín 3 77 3 Alt D Nguyen 6 6
Alt D Nguyen 6 65 6 Alt D Nguyen 6 6
Q Robin Staněk 2 6 77 A González 2 1
Q E Gómez 6 4 63 Q R Staněk 3 1
A González 6 7 A González 6 6
8 T Ito 4 5

Bottom Half

First Round Second Round Quarterfinals Semifinals
7 S Robert 6 4 2
D Popko 4 6 6 D Popko 4 4
Alt J Jung 1 63 Alt J Souza 6 6
Alt J Souza 6 77 Alt J Souza 4 77 5
N Milojević 6 4 67 3 M Jaziri 6 61 0r
Alt M Safwat 3 6 79 Alt M Safwat 6 4 5
WC H Hach Verdugo 2 3 3 M Jaziri 3 6 7
3 M Jaziri 6 6 Alt J Souza 77 6
5 A Krajicek 4 4 Q C Zampieri 63 4
A Menéndez-Maceiras 6 6 A Menéndez-Maceiras 6 6
H Laaksonen 7 6 H Laaksonen 3 0
WC T Hank 5 3 A Menéndez-Maceiras 6 4 4
Q C Zampieri 6 6 Q C Zampieri 2 6 6
J McGee 4 4 Q C Zampieri 6 6
Q A Velotti 64 6 7 Q A Velotti 3 2
2 T Fritz 77 3 5
gollark: In JS's case, probably IEEEWHATEVER.
gollark: Yes, indeed, so they picked infinity.
gollark: `3/0=Infinity` is kind of valid, given that I think algebraically x/0 can be any real number.
gollark: It is important to note that it is evil.
gollark: The `error` function. It is evil.

References

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.