2015 Engie Open Nantes Atlantique – Singles

Kateřina Siniaková was the defending champion, but lost to Mathilde Johansson in the semifinals.

Singles
2015 Engie Open Nantes Atlantique
Champion Mathilde Johansson
Runner-up Andreea Mitu
Final score6–3, 6–4

Johansson won the title, defeating Andreea Mitu in the final, 6–3, 6–4.

Seeds

  1. Anna-Lena Friedsam (Quarterfinals)
  2. Kateřina Siniaková (Semifinals)
  3. Andreea Mitu (Final)
  4. Anastasija Sevastova (Second round)
  5. Kristýna Plíšková (First round)
  6. Louisa Chirico (Semifinals)
  7. Pauline Parmentier (Second round)
  8. Alexandra Panova (First round)

Main draw

Key

Finals

Semifinals Final
          
6 Louisa Chirico 6 0 4
3 Andreea Mitu 2 6 6
3 Andreea Mitu 3 4
  Mathilde Johansson 6 6
  Mathilde Johansson 6 4 6
2 Kateřina Siniaková 4 6 2

Top half

First round Second round Quarterfinals Semifinals
1 A-L Friedsam 7 6
  İ Soylu 5 4 1 A-L Friedsam 6 6
WC F Ferro 5 4 Q S Shapatava 4 3
Q S Shapatava 7 6 1 A-L Friedsam 6 3 2
WC T Andrianjafitrimo 5 77 6 6 L Chirico 2 6 6
JE J Teichmann 7 64 2 WC T Andrianjafitrimo 2 3
LL C Feuerstein 1 3 6 L Chirico 6 6
6 L Chirico 6 6 6 L Chirico 6 0 4
3 A Mitu 6 6 3 A Mitu 2 6 6
  O Dodin 3 2 3 A Mitu 6 6
  A Vrljić 6 6 A Vrljić 3 4
WC I Ramialison 4 4 3 A Mitu 6 713
  T Paszek 6 6 T Paszek 2 611
Q K Stuchlá 4 3 T Paszek 6 6
  M Georges 66 6 6 M Georges 4 2
8 A Panova 78 1 1

Bottom half

First round Second round Quarterfinals Semifinals
7 P Parmentier 6 1 6
  S Foretz 1 6 2 7 P Parmentier 2 4
  M Johansson 77 6 M Johansson 6 6
  N Abduraimova 65 1 M Johansson 6 77
  S Soler Espinosa 0 3 A Kalinina 1 63
  A Kalinina 6 6 A Kalinina 6 6
  R Voráčová 2 3 4 A Sevastova 4 2
4 A Sevastova 6 6 M Johansson 6 4 6
5 Kr Plíšková 4 5 2 K Siniaková 4 6 2
  Y Beygelzimer 6 7 Y Beygelzimer 5 2
Q X Knoll 6 6 Q X Knoll 7 6
Q C Paquet 4 3 Q X Knoll 66 4
WC J Ponchet 1 1 2 K Siniaková 78 6
  T Martincová 6 6 T Martincová 5 6 68
  P Leykina 65 1 2 K Siniaková 7 4 710
2 K Siniaková 77 6
gollark: Down with newtypes! `data` is the one true way to declare types!
gollark: I'll work on this when I'm not on a phone.
gollark: Wait, no, this is index in *line* not string.
gollark: Well, this is roughly what you wanted, anyway.
gollark: Horribly messy version:```haskellwithIndices :: [a] -> [(Int, a)]withIndices = zip [1..]doStuff :: String -> [(Int, Int, Char)]doStuff s = (\(lineIx, l) -> fmap (\(charIx, char) -> (lineIx, charIx, char)) $ withIndices l) `concatMap` withIndices (lines s)main = print . doStuff $ "abcd"```

References

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