2014 Astana Challenger – Doubles
Riccardo Ghedin and Claudio Grassi were the defending champions, but not to compete.
Doubles | |
---|---|
2014 Astana Challenger | |
Champions | |
Runners-up | |
Final score | 6–1, 6–4 |
Second seeds Sergey Betov and Alexander Bury won the title over the local team of Andrey Golubev and Evgeny Korolev, 6–1, 6–4 in the final.
Seeds
Konstantin Kravchuk / Denys Molchanov (Quarterfinals) Sergey Betov / Alexander Bury (Champions) Farrukh Dustov / Matteo Volante (Quarterfinals) Jan Mertl / Jaroslav Pospíšil (Quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 6 | |||||||||||||||||||||||||
1 | 3 | 1 | 6 | 5 | [6] | ||||||||||||||||||||||
1 | 3 | 3 | 7 | [10] | |||||||||||||||||||||||
6 | 6 | 6 | 6 | ||||||||||||||||||||||||
3 | 77 | 6 | 4 | 2 | |||||||||||||||||||||||
64 | 2 | 3 | 5 | 77 | [7] | ||||||||||||||||||||||
WC | 1 | 1 | 7 | 65 | [10] | ||||||||||||||||||||||
6 | 6 | 1 | 4 | ||||||||||||||||||||||||
77 | 77 | 2 | 6 | 6 | |||||||||||||||||||||||
63 | 65 | 7 | 7 | ||||||||||||||||||||||||
WC | 3 | 3 | 4 | 5 | 5 | ||||||||||||||||||||||
4 | 6 | 6 | 3 | 6 | 2 | ||||||||||||||||||||||
WC | 3 | 6 | [10] | 2 | 6 | 1 | [10] | ||||||||||||||||||||
6 | 1 | [8] | WC | 3 | 2 | ||||||||||||||||||||||
3 | 3 | 2 | 6 | 6 | |||||||||||||||||||||||
2 | 6 | 6 |
gollark: They will, however, not panic.
gollark: They are defined as working two's-complement-ly or something, there's an RFC on it.
gollark: In release mode, integer overflows are still DEFINED.
gollark: We should just use bigints literally everywhere.
gollark: Great, so C compilers can add safety™ things too.
References
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