2012 Barcelona Open Banco Sabadell – Doubles

Santiago González and Scott Lipsky were the defending champions but decided not to participate together.
González partnered up with Christopher Kas but lost in the Quarterfinals, while Lipsky played alongside Rajeev Ram but lost in the first round.
Mariusz Fyrstenberg and Marcin Matkowski won the tournament defeating Marcel Granollers and Marc López in the final.

Doubles
2012 Barcelona Open Banco Sabadell
Champions Mariusz Fyrstenberg
Marcin Matkowski
Runners-up Marcel Granollers
Marc López
Final score2–6, 7–6(9–7), [10–8]

Seeds

  1. Bob Bryan / Mike Bryan (Quarterfinals, withdrew due to Bob Bryan's virus)
  2. Max Mirnyi / Daniel Nestor (Semifinals)
  3. Mahesh Bhupati / Nenad Zimonjić (Quarterfinals)
  4. Mariusz Fyrstenberg / Marcin Matkowski (Champion)
  5. František Čermák / Filip Polášek (Second round)
  6. Santiago González / Christopher Kas (Quarterfinals)
  7. Aisam-ul-Haq Qureshi / Jean-Julien Rojer (Quarterfinals)
  8. Oliver Marach / Alexander Peya (Semifinals)

Draw

Key

Finals

Semifinals Final
          
8 Oliver Marach
Alexander Peya
64 1  
  Marcel Granollers
Marc López
77 6  
  Marcel Granollers
Marc López
6 67 [8]
4 Mariusz Fyrstenberg
Marcin Matkowski
2 79 [10]
4 Mariusz Fyrstenberg
Marcin Matkowski
6 0 [10]
2 Max Mirnyi
Daniel Nestor
3 6 [6]

Top Half

First Round Second Round Quarterfinals Semifinals
1 B Bryan
M Bryan
5 6 [10]
  P Andújar
G García-López
61 1     D Marrero
F Verdasco
7 2 [7]
  D Marrero
F Verdasco
77 6   1 B Bryan
M Bryan
     
  M Elgin
D Istomin
65 6 [10] 8 O Marach
A Peya
w/o    
WC I Cervantes Huegun
G Granollers
77 3 [8]   M Elgin
D Istomin
1 6 [7]
8 O Marach
A Peya
6 4 [10]
8 O Marach
A Peya
64 1  
  M Granollers
M López
77 6  
3 M Bhupathi
N Zimonjić
77 4 [10]
  R Ramírez Hidalgo
E Schwank
65 64     J Erlich
A Ram
64 6 [6]
  J Erlich
A Ram
77 77   3 M Bhupathi
N Zimonjić
5 6 [5]
  A Falla
S Giraldo
62 4     M Granollers
M López
7 3 [10]
  M Granollers
M López
77 6     M Granollers
M López
77 6  
5 F Čermák
F Polášek
64 3  

Bottom Half

First Round Second Round Quarterfinals Semifinals
7 A-u-H Qureshi
J-J Rojer
6 5 [10]
  A Murray
J Murray
6 6     A Murray
J Murray
2 7 [8]
  K Anderson
F Moser
4 4   7 A-u-H Qureshi
J-J Rojer
3 710 [7]
  E Butorac
B Soares
6 6   4 M Fyrstenberg
M Matkowski
6 68 [10]
  S Lipsky
R Ram
3 3     E Butorac
B Soares
6 63 [10]
4 M Fyrstenberg
M Matkowski
3 77 [12]
4 M Fyrstenberg
M Matkowski
6 0 [10]
2 M Mirnyi
D Nestor
3 6 [6]
6 S González
C Kas
3 77 [10]
  JS Cabal
R Farah
6 4 [6]   N Almagro
A Ramos
6 63 [8]
  N Almagro
A Ramos
2 6 [10] 6 S González
C Kas
5 4  
  R Haase
J Nieminen
5 6 [10] 2 M Mirnyi
D Nestor
7 6  
WC D Gimeno-Traver
A Montañés
7 3 [4]   R Haase
J Nieminen
6 4 [12]
2 M Mirnyi
D Nestor
4 6 [14]
gollark: Oops, sorry, code error, it's (x - 2) * -1 / 1.8144e+5 * (x - 3) * (x - 4) * (x - 5) * (x - 6) * (x - 7) * (x - 8) * (x - 9) * (x - 10) + (x - 1) / 13440 * (x - 3) * (x - 4) * (x - 5) * (x - 6) * (x - 7) * (x - 8) * (x - 9) * (x - 10) + (x - 1) * -1 / 2016 * (x - 2) * (x - 4) * (x - 5) * (x - 6) * (x - 7) * (x - 8) * (x - 9) * (x - 10) + (x - 1) * 7 / 4320 * (x - 2) * (x - 3) * (x - 5) * (x - 6) * (x - 7) * (x - 8) * (x - 9) * (x - 10) + (x - 1) * -11 / 2880 * (x - 2) * (x - 3) * (x - 4) * (x - 6) * (x - 7) * (x - 8) * (x - 9) * (x - 10) + (x - 1) * 13 / 2880 * (x - 2) * (x - 3) * (x - 4) * (x - 5) * (x - 7) * (x - 8) * (x - 9) * (x - 10) + (x - 1) * -17 / 4320 * (x - 2) * (x - 3) * (x - 4) * (x - 5) * (x - 6) * (x - 8) * (x - 9) * (x - 10) + (x - 1) * 19 / 10080 * (x - 2) * (x - 3) * (x - 4) * (x - 5) * (x - 6) * (x - 7) * (x - 9) * (x - 10) + (x - 1) * -23 / 40320 * (x - 2) * (x - 3) * (x - 4) * (x - 5) * (x - 6) * (x - 7) * (x - 8) * (x - 10) + (x - 1) * 29 / 3.6288e+5 * (x - 2) * (x - 3) * (x - 4) * (x - 5) * (x - 6) * (x - 7) * (x - 8) * (x - 9).
gollark: This is such an elegant, clear and useful™ formula.
gollark: y = (x - 3) * -1 / 2.14708725e+8 * (x - 5) * (x - 7) * (x - 11) * (x - 13) * (x - 17) * (x - 19) * (x - 23) * (x - 29) + (x - 2) / 3.72736e+7 * (x - 5) * (x - 7) * (x - 11) * (x - 13) * (x - 17) * (x - 19) * (x - 23) * (x - 29) + (x - 2) * -1 / 1.3934592e+7 * (x - 3) * (x - 7) * (x - 11) * (x - 13) * (x - 17) * (x - 19) * (x - 23) * (x - 29) + (x - 2) / 1.01376e+7 * (x - 3) * (x - 5) * (x - 11) * (x - 13) * (x - 17) * (x - 19) * (x - 23) * (x - 29) + (x - 2) * -5 / 3.5831808e+7 * (x - 3) * (x - 5) * (x - 7) * (x - 13) * (x - 17) * (x - 19) * (x - 23) * (x - 29) + (x - 2) / 6.7584e+6 * (x - 3) * (x - 5) * (x - 7) * (x - 11) * (x - 17) * (x - 19) * (x - 23) * (x - 29) + (x - 2) * -1 / 1.24416e+7 * (x - 3) * (x - 5) * (x - 7) * (x - 11) * (x - 13) * (x - 19) * (x - 23) * (x - 29) + (x - 2) / 2.193408e+7 * (x - 3) * (x - 5) * (x - 7) * (x - 11) * (x - 13) * (x - 17) * (x - 23) * (x - 29) + (x - 2) * -1 / 2.322432e+8 * (x - 3) * (x - 5) * (x - 7) * (x - 11) * (x - 13) * (x - 17) * (x - 19) * (x - 29) + (x - 2) / 7.685922816e+9 * (x - 3) * (x - 5) * (x - 7) * (x - 11) * (x - 13) * (x - 17) * (x - 19) * (x - 23)for instance.
gollark: > Factorials can be defined with an integral, so you could theoretically add x! to your y?My thing can EVEN make a formula for prime numbers! Specifically a small set of ones you supply beforehand!
gollark: What's a smooth? What's a R^n? What's a limit epsilon something something?

References

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