2011 Singapore ATP Challenger – Doubles
1st seeds Scott Lipsky and David Martin won in the final 5–7, 6–1, [10–8], against Sanchai and Sonchat Ratiwatana.
Doubles | |
---|---|
2011 Singapore ATP Challenger | |
Champions | |
Runners-up | |
Final score | 5–7, 6–1, [10–8] |
Seeds
Scott Lipsky / David Martin (Champions) Sanchai Ratiwatana / Sonchat Ratiwatana (Final) Johan Brunström / Frederik Nielsen (Semifinals) Flavio Cipolla / Simone Vagnozzi (First Round)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | 6 | 6 | |||||||||||||||||||||||||
1 | 2 | 1 | 6 | 6 | |||||||||||||||||||||||
4 | 3 | 3 | 1 | ||||||||||||||||||||||||
6 | 6 | 1 | 7 | 3 | [10] | ||||||||||||||||||||||
3 | 7 | 7 | 3 | 66 | 6 | [5] | |||||||||||||||||||||
65 | 5 | 3 | |||||||||||||||||||||||||
4 | 64 | w/o | |||||||||||||||||||||||||
6 | 7 | 1 | 5 | 6 | [10] | ||||||||||||||||||||||
WC | 6 | 7 | 2 | 7 | 1 | [8] | |||||||||||||||||||||
WC | 0 | 5 | WC | 4 | 6 | [7] | |||||||||||||||||||||
6 | 6 | 6 | 3 | [10] | |||||||||||||||||||||||
4 | 4 | 3 | 4 | 7 | [7] | ||||||||||||||||||||||
2 | 1 | 2 | 6 | 62 | [10] | ||||||||||||||||||||||
6 | 6 | 65 | 6 | [5] | |||||||||||||||||||||||
WC | 4 | 1 | 2 | 7 | 2 | [10] | |||||||||||||||||||||
2 | 6 | 6 |
gollark: Yes, you're "firecubez"; this is true and not false, entirely.
gollark: `>>` is a special case of `>>=`, which encapsulates all the real-world-passing stuff in a way which also happens to generalize nicely to everything else, thus monads.
gollark: Maybe *your* Haskell compiler can't.
gollark: And this can be statically verified.
gollark: `macron` has type `!` because Macron will never actually happen.
References
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