2011 Singapore ATP Challenger – Doubles

1st seeds Scott Lipsky and David Martin won in the final 5–7, 6–1, [10–8], against Sanchai and Sonchat Ratiwatana.

Doubles
2011 Singapore ATP Challenger
Champions Scott Lipsky
David Martin
Runners-up Sanchai Ratiwatana
Sonchat Ratiwatana
Final score5–7, 6–1, [10–8]

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 S Lipsky
D Martin
6 6  
  F Škugor
L Zovko
1 2   1 S Lipsky
D Martin
6 6  
  A Sitak
M Viola
4 3     P Polansky
G Soeda
3 1  
  P Polansky
G Soeda
6 6   1 S Lipsky
D Martin
7 3 [10]
3 J Brunström
F Nielsen
7 7   3 J Brunström
F Nielsen
66 6 [5]
  A Kudryavtsev
L Rosol
65 5   3 J Brunström
F Nielsen
     
  D Lojda
I Minář
4 64     T Alves
P Lorenzi
w/o    
  T Alves
P Lorenzi
6 7   1 S Lipsky
D Martin
5 6 [10]
WC D Tursunov
Y-t Wang
6 7   2 Sa Ratiwatana
So Ratiwatana
7 1 [8]
WC Roy Hobbs
T-h Yang
0 5   WC D Tursunov
Y-t Wang
4 6 [7]
  R de Voest
S Devvarman
6 6     R de Voest
S Devvarman
6 3 [10]
4 F Cipolla
S Vagnozzi
4 3     R de Voest
S Devvarman
4 7 [7]
  M Gong
Z Li
2 1   2 Sa Ratiwatana
So Ratiwatana
6 62 [10]
  TC Huey
P Raja
6 6     TC Huey
P Raja
65 6 [5]
WC K Rastogi
C Rungkat
4 1   2 Sa Ratiwatana
So Ratiwatana
7 2 [10]
2 Sa Ratiwatana
So Ratiwatana
6 6  
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gollark: `>>` is a special case of `>>=`, which encapsulates all the real-world-passing stuff in a way which also happens to generalize nicely to everything else, thus monads.
gollark: Maybe *your* Haskell compiler can't.
gollark: And this can be statically verified.
gollark: `macron` has type `!` because Macron will never actually happen.

References

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