2011 Banja Luka Challenger – Singles

Marsel İlhan was the defending champion but decided not to participate.

Singles
2011 Banja Luka Challenger
Champion Blaž Kavčič
Runner-up Pere Riba
Final score6–4, 6–1
Main article: 2011 Banja Luka Challenger

2nd seed Blaž Kavčič claimed the title, defeating 1st seed Pere Riba 6–4, 6–1 in the final.

Seeds
  1. Pere Riba (Final)
  2. Blaž Kavčič (Champion)
  3. Daniel Gimeno-Traver (Semifinals)
  4. Flavio Cipolla (Second Round)
  5. Grega Žemlja (First Round)
  6. Jaroslav Pospíšil (First Round)
  7. Rubén Ramírez Hidalgo (Second Round)
  8. Pablo Carreño-Busta (Quarterfinals)

Draw

Key

Finals
Semifinals Final
          
1 Pere Riba 77 6  
3 Daniel Gimeno-Traver 64 0  
1 Pere Riba 4 1  
2 Blaž Kavčič 6 6  
  Simone Vagnozzi 4 5  
2 Blaž Kavčič 6 7  

Top Half
First Round Second Round Quarterfinals Semifinals
1 P Riba 6 4  
  D Lojda 4 0r   1 P Riba 6 6  
  I Klec 7 1 6   I Klec 2 2  
  F Romboli 5 6 4 1 P Riba 6 6  
  J Dasnières de Veigy 1 1   WC M Bašić 1 3  
WC M Bašić 6 6   WC M Bašić 4 6 6
Q N Čačić 6 6   Q N Čačić 6 3 3
6 J Pospíšil 4 1   1 P Riba 77 6  
3 D Gimeno-Traver 6 6   3 D Gimeno-Traver 64 0  
Q T Androić 4 2   3 D Gimeno-Traver 7 6  
  J Mertl 6 6     J Mertl 5 2  
WC G Tošić 4 0   3 D Gimeno-Traver 4 6 6
  M Teixeira 3 0   8 P Carreño-Busta 6 3 4
Q D Marcan 6 6   Q D Marcan 1 2  
  F Dancevic 3 64   8 P Carreño-Busta 6 6  
8 P Carreño-Busta 6 77  

Bottom Half
First Round Second Round Quarterfinals Semifinals
5 G Žemlja 6 4 64
  I Navarro 3 6 77   I Navarro 2 3  
  S Vagnozzi 6 6     S Vagnozzi 6 6  
  K Čapkovič 3 2     S Vagnozzi 6 6  
  G Alcaide 6 4 1 Q A Pavić 3 1  
Q Ante Pavić 4 6 6 Q A Pavić 6 3 7
  B Pašanski 3 2   4 F Cipolla 4 6 5
4 F Cipolla 6 6     S Vagnozzi 4 5  
7 R Ramírez Hidalgo 6 6   2 B Kavčič 6 7  
  M Crugnola 3 0   7 R Ramírez Hidalgo 6 61 3
WC Ivan Bjelica 1 1     A Bedene 1 77 6
  A Bedene 6 6     A Bedene 4 64  
  M Viola 3 1   2 B Kavčič 6 77  
  M Middelkoop 6 6     M Middelkoop 78 1 4
WC T Brkić 77 4 1 2 B Kavčič 66 6 6
2 B Kavčič 63 6 6
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gollark: This poses an interesting philosophical question: if you take a laser pointer, replace all the components, then build a new laser pointer from the removed components, which (if any) is the original laser pointer?
gollark: I see. Kind of confusing to equate them when you're talking about them going up/down, is all.
gollark: Frequency is inversely proportional to wavelength.
gollark: Your phone could probably charge off just 5V/1A fine, but slower.

References
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