2010 Weil Tennis Academy Challenger – Singles

Bobby Reynolds won in the final, 3-6, 7-5, 7-5 against Marinko Matosevic.

Singles
2010 Weil Tennis Academy Challenger
Champion Bobby Reynolds
Runner-up Marinko Matosevic
Final score3–6, 7–5, 7–5
Main article: 2010 Weil Tennis Academy Challenger

Seeds
  1. Ryan Sweeting (Second Round)
  2. Brian Dabul (Semifinals, retired)
  3. Kevin Kim (First Round)
  4. Donald Young (Semifinals)
  5. Michael Yani (withdrew due to elbow injury)
  6. Robert Kendrick (First Round)
  7. Conor Niland (First Round)
  8. Alex Kuznetsov (Second Round)

Draw

Key

Finals
Semifinals Final
          
WC Bobby Reynolds 6 6  
4/WC Donald Young 3 2  
WC Bobby Reynolds 3 7 7
  Marinko Matosevic 6 5 5
  Marinko Matosevic 4    
2 Brian Dabul 3 r  

Top Half
First Round Second Round Quarterfinals Semifinals
1 R Sweeting 6 6  
  V Estrella 3 1   1 R Sweeting 3 64  
Q Greg Ouellette 1 7 1   P Capdeville 6 7  
  P Capdeville 6 65 6   P Capdeville 6 4 5
WC B Reynolds 6 6   WC B Reynolds 2 6 7
WC S Bangoura 2 1   WC B Reynolds 6 6  
  A Sitak 4 62   8 A Kuznetsov 4 2  
8 A Kuznetsov 6 7   WC B Reynolds 6 6  
4/WC D Young 6 6   4/WC D Young 3 2  
  L Tavares 3 2   4/WC D Young 7 2 7
  M Ryderstedt 4 63   LL D Kelly 5 6 5
LL Dayne Kelly 6 7   4/WC D Young 2 6 6
  M Raonic 6 6     L Gregorc 6 1 4
  T Suzuki 3 3     M Raonic 3 6 1
  L Gregorc 6 6     L Gregorc 6 3 6
7 C Niland 4 4  

Bottom Half
First Round Second Round Quarterfinals Semifinals
6 R Kendrick 6 3 62
Q P Bester 2 6 7 Q P Bester 3 1  
Q N Monroe 64 3     T Smyczek 6 6  
  T Smyczek 7 6     T Smyczek 2 2  
ALT P-L Duclos 5 0     M Matosevic 6 6  
  P Polansky 7 6     P Polansky 5 4  
  M Matosevic 6 6     M Matosevic 7 6  
3 K Kim 1 0     M Matosevic 4    
LL M Reid 6 4 2 2 B Dabul 3 r  
  L Cook 4 6 6   L Cook 6 6  
  I van der Merwe 7 66 6   I van der Merwe 4 4  
WC S Johnson 5 7 3   L Cook 3 4  
Q C Mamiit 1 7 62 2 B Dabul 6 6  
  S Groth 6 5 7   S Groth 4 1 r
  J Statham 6 66 65 2 B Dabul 6 1  
2 B Dabul 2 7 7
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gollark: Rust would be easier but it has 128-bit ints at most.
gollark: Anyway, I can probably define bigger numbers, but... not in 32 bytes?
gollark: It's exponentiation, not tetration.
gollark: This *may* actually be optimal.

References
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