2009 Manchester Trophy – Doubles
Adam Feeney and Robert Smeets were the defending champions. Feeney chose to not participate and Smeets played with Brydan Klein. They were eliminated by Prakash Amritraj and Dustin Brown in the first round.
Joshua Goodall and Jonathan Marray won the final 6–7(1), 6–3, [11–9], against Colin Fleming and Ken Skupski.
Doubles | |
---|---|
2009 Manchester Trophy | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Final score | 6–7(1), 6–3, [11–9] |
Seeds
Sergei Bubka/Sergiy Stakhovsky(First Round, withdrew) Colin Fleming / Ken Skupski (Final) George Bastl / Nicolas Mahut (Quarterfinals) Joshua Goodall / Jonathan Marray (Champions)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
First Round | Quarterfinals | Semifinals | Finals | ||||||||||||||||||||||||
1 | ![]() ![]() | w/o | |||||||||||||||||||||||||
![]() ![]() | ![]() ![]() | 64 | 6 | [10] | |||||||||||||||||||||||
WC | ![]() ![]() | 6 | 5 | [17] | WC | ![]() ![]() | 7 | 1 | [5] | ||||||||||||||||||
![]() ![]() | 3 | 7 | [15] | ![]() ![]() | 5 | 4 | |||||||||||||||||||||
4 | ![]() ![]() | 6 | 6 | 4 | ![]() ![]() | 7 | 6 | ||||||||||||||||||||
![]() ![]() | 3 | 4 | 4 | ![]() ![]() | 6 | 7 | |||||||||||||||||||||
![]() ![]() | 2 | 7 | [4] | ![]() ![]() | 3 | 5 | |||||||||||||||||||||
![]() ![]() | 6 | 5 | [10] | 4 | ![]() ![]() | 61 | 6 | [11] | |||||||||||||||||||
![]() ![]() | 6 | 3 | [3] | 2 | ![]() ![]() | 7 | 3 | [9] | |||||||||||||||||||
![]() ![]() | 3 | 6 | [10] | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
![]() ![]() | 4 | 2 | 3 | ![]() ![]() | 2 | 4 | |||||||||||||||||||||
3 | ![]() ![]() | 6 | 6 | ![]() ![]() | 62 | 2 | |||||||||||||||||||||
Q | ![]() ![]() | 2 | 6 | [7] | 2 | ![]() ![]() | 7 | 6 | |||||||||||||||||||
![]() ![]() | 6 | 1 | [10] | ![]() ![]() | 3 | 7 | [6] | ||||||||||||||||||||
![]() ![]() | 3 | 6 | [5] | 2 | ![]() ![]() | 6 | 63 | [10] | |||||||||||||||||||
2 | ![]() ![]() | 6 | 1 | [10] |
gollark: Oh, you said apioize, not apionize, those are different operations.
gollark: What? No.
gollark: Oh bees my clipboard is somehow broken?
gollark: This is actually not part of the ABR apionization code.
gollark: Imagine the sheer ease of parsing.
References
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