1999 Open 13 – Singles

Fabrice Santoro defeated Arnaud Clément 6–3, 4–6, 6–4 to win the 1999 Open 13 singles competition. Thomas Enqvist was the champion but did not defend his title.

Singles
1999 Open 13
Champion Fabrice Santoro
Runner-up Arnaud Clément
Final score6–3, 4–6, 6–4
Main article: 1999 Open 13

Seeds
  1. Carlos Moyà (First Round)
  2. Yevgeny Kafelnikov (Second Round)
  3. Cédric Pioline (Semifinals)
  4. Marc Rosset (Semifinals)
  5. Magnus Gustafsson (First Round)
  6. Nicolas Escudé (Quarterfinals)
  7. Daniel Vacek (First Round)
  8. Marat Safin (First Round)

Draw

Key

Finals
Semifinals Final
          
WC Arnaud Clément 6 6
3 Cédric Pioline 4 1
WC Arnaud Clément 3 6 4
  Fabrice Santoro 6 4 6
4 Marc Rosset 4 4
  Fabrice Santoro 6 6

Top Half
First Round Second Round Quarterfinals Semifinals
1 C Moyà 61 6 3
WC R Federer 77 3 6 WC R Federer 66 77 77
  A Voinea 2 2     J Golmard 78 65 65
  J Golmard 6 6   WC R Federer 3 3  
WC A Clément 6 6   WC A Clément 6 6  
  F Vicente 3 1   WC A Clément 6 6  
Q J Boutter 6 77   Q J Boutter 2 3  
8 M Safin 4 62   WC A Clément 6 6  
3 C Pioline 6 6   3 C Pioline 4 1  
  J Tarango 4 2   3 C Pioline 7 7  
Q F Jonsson 65 63     A Medvedev 5 5  
  A Medvedev 77 77   3 C Pioline 79 77  
  A Pavel 6 7   6 N Escudé 67 65  
  G Blanco 4 5     A Pavel 6 62 5
  K Alami 1 77 62 6 N Escudé 0 77 7
6 N Escudé 6 62 77

Bottom Half
First Round Second Round Quarterfinals Semifinals
5 M Gustafsson 3 4  
  G Raoux 6 6     G Raoux 6 4 4
  G Pozzi 7 6     G Pozzi 4 6 6
  L Roux 5 0     G Pozzi 2 1  
  D Prinosil 64 6 3 4 M Rosset 6 6  
  K Carlsen 77 4 6   K Carlsen 3 2  
Q C Saulnier 2 6 1 4 M Rosset 6 6  
4 M Rosset 6 3 6 4 M Rosset 4 4  
7 D Vacek 2 3     F Santoro 6 6  
  F Santoro 6 6     F Santoro 6 6  
  J Gimelstob 6 1 4   A di Pasquale 1 3  
  A di Pasquale 4 6 6   F Santoro 6 6  
  J A Marín 2 1   Q D Hrbatý 4 3  
Q D Hrbatý 6 6   Q D Hrbatý 64 6 6
  S Schalken 3 2   WC/2 Y Kafelnikov 77 4 2
WC/2 Y Kafelnikov 6 6  
gollark: Although that might make sense, so C probably does something else.
gollark: I would assume the value of `m[4]` after addition.
gollark: More seriously, though, probably `m[4]` plus 8 times `m[3]` plus 40.
gollark: it evaluates toYOUR DOOM
gollark: and you probably could.
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