1997 Qatar Open – Singles
Petr Korda was the defending champion but lost in the quarterfinals to Sergi Bruguera.
Singles | |
---|---|
1997 Qatar Open | |
Champion | ![]() |
Runner-up | ![]() |
Final score | 7–5, 6–7(5–7), 6–2 |
Jim Courier won in the final 7–5, 6–7(5–7), 6–2 against Tim Henman.
Seeds
Thomas Muster (Quarterfinals) Thomas Enqvist (First Round) Jan Siemerink (First Round) Michael Stich (First Round) Magnus Gustafsson (Quarterfinals) Petr Korda (Quarterfinals) Paul Haarhuis (First Round) Jim Courier (Champion)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- Alt = Alternate
- SE = Special Exempt
- PR = Protected Ranking
- ITF = ITF entry
- JE = Junior Exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
Finals
Semifinals | Final | ||||||||||||
8 | ![]() | 6 | 6 | ||||||||||
![]() | 4 | 2 | |||||||||||
8 | ![]() | 7 | 65 | 6 | |||||||||
![]() | 5 | 77 | 2 | ||||||||||
![]() | 6 | 2 | 6 | ||||||||||
![]() | 3 | 6 | 2 | ||||||||||
Top Half
First Round | Second Round | Quarterfinals | Semifinals | ||||||||||||||||||||||||
1 | ![]() | 7 | 6 | ||||||||||||||||||||||||
![]() | 5 | 4 | 1 | ![]() | 6 | 3 | 7 | ||||||||||||||||||||
![]() | 6 | 6 | ![]() | 2 | 6 | 5 | |||||||||||||||||||||
WC | ![]() | 2 | 0 | 1 | ![]() | 3 | 5 | ||||||||||||||||||||
Q | ![]() | 6 | 3 | 77 | 8 | ![]() | 6 | 7 | |||||||||||||||||||
![]() | 3 | 6 | 61 | Q | ![]() | 3 | 4 | ||||||||||||||||||||
![]() | 610 | 5 | 8 | ![]() | 6 | 6 | |||||||||||||||||||||
8 | ![]() | 712 | 7 | 8 | ![]() | 6 | 6 | ||||||||||||||||||||
4 | ![]() | 3 | 1 | ![]() | 4 | 2 | |||||||||||||||||||||
![]() | 6 | 6 | ![]() | 6 | 6 | ||||||||||||||||||||||
![]() | 6 | 4 | 6 | ![]() | 0 | 1 | |||||||||||||||||||||
![]() | 3 | 6 | 4 | ![]() | 6 | 2 | 6 | ||||||||||||||||||||
![]() | 3 | 0 | 6 | ![]() | 1 | 6 | 3 | ||||||||||||||||||||
![]() | 6 | 6 | ![]() | 77 | 4 | 2 | |||||||||||||||||||||
![]() | 1 | 2 | 6 | ![]() | 63 | 6 | 6 | ||||||||||||||||||||
6 | ![]() | 6 | 6 |
Bottom Half
First Round | Second Round | Quarterfinals | Semifinals | ||||||||||||||||||||||||
5 | ![]() | 4 | 6 | 6 | |||||||||||||||||||||||
![]() | 6 | 1 | 4 | 5 | ![]() | 6 | 2 | 6 | |||||||||||||||||||
Q | ![]() | 77 | 5 | 2 | ![]() | 2 | 6 | 4 | |||||||||||||||||||
![]() | 64 | 7 | 6 | 5 | ![]() | 3 | 63 | ||||||||||||||||||||
![]() | 6 | 6 | ![]() | 6 | 77 | ||||||||||||||||||||||
Q | ![]() | 3 | 2 | ![]() | 6 | 6 | |||||||||||||||||||||
Q | ![]() | 6 | 62 | 77 | Q | ![]() | 3 | 2 | |||||||||||||||||||
3 | ![]() | 3 | 77 | 65 | ![]() | 6 | 2 | 6 | |||||||||||||||||||
7 | ![]() | 4 | 6 | 2 | ![]() | 3 | 6 | 2 | |||||||||||||||||||
WC | ![]() | 6 | 1 | 6 | WC | ![]() | 6 | 5 | 5 | ||||||||||||||||||
WC | ![]() | 2 | 3 | ![]() | 2 | 7 | 7 | ||||||||||||||||||||
![]() | 6 | 6 | ![]() | 77 | 77 | ||||||||||||||||||||||
![]() | 6 | 6 | ![]() | 63 | 62 | ||||||||||||||||||||||
![]() | 2 | 2 | ![]() | 4 | 64 | ||||||||||||||||||||||
![]() | 6 | 7 | ![]() | 6 | 77 | ||||||||||||||||||||||
2 | ![]() | 4 | 5 |
gollark: No.
gollark: |ℝ| = |ℝ²| because a bijection between them exists so there are as many squares as rectangles so all rectangles are squares, QED.
gollark: There are |ℝ| squares, right, and |ℝ²| rectangles?
gollark: Since I don't know measure theory, though, this sounds dubious.
gollark: Actually, this might be answerable with measure theory somehow.
References
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