1988 Virginia Slims of Houston – Doubles

Kathy Jordan and Martina Navratilova were the defending champions but only Navratilova competed that year with Lori McNeil.

Doubles
1988 Virginia Slims of Houston
1987 Champions Kathy Jordan
Martina Navratilova
Champions Katrina Adams
Zina Garrison
Runners-up Lori McNeil
Martina Navratilova
Final score6–7, 6–2, 6–4

McNeil and Navratilova lost in the final 6–7, 6–2, 6–4 against Katrina Adams and Zina Garrison.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Lori McNeil / Martina Navratilova (Final)
  2. Katrina Adams / Zina Garrison (Champions)
  3. Rosalyn Fairbank / Candy Reynolds (Quarterfinals)
  4. Penny Barg / Mercedes Paz (Semifinals)

Draw

Key
First Round Quarterfinals Semifinals Final
1 L McNeil
M Navratilova 		2 6 6
  K Schimper
W Wood 		6 2 4 1 L McNeil
M Navratilova 		6 6  
  H Crowe
K Steinmetz 		3 5     J Jonerup
J Smoller 		1 3  
  J Jonerup
J Smoller 		6 7   1 L McNeil
M Navratilova 		7 6  
3 R Fairbank
C Reynolds 		6 6     G Magers
W White 		6 2  
  M Gurney
P Jung 		1 3   3 R Fairbank
C Reynolds 		2 2  
  G Magers
W White 		6 6     G Magers
W White 		6 6  
  M L Daniels
A M Fernandez 		1 4   1 Lori McNeil
Martina Navratilova 		7 2 4
  S Collins
T Zambrzycki 		4 4   2 Katrina Adams
Zina Garrison 		6 6 6
  A Frazier
L Spadea 		6 6     A Frazier
L Spadea 		3 4  
  I Budařová
H Na 		3 1   4 P Barg
M Paz 		6 6  
4 P Barg
M Paz 		6 6   4 P Barg
M Paz 		1 4  
  Ca MacGregor
Cy MacGregor 		6 7 4 2 K Adams
Z Garrison 		6 6  
  M Lindström
H Ludloff 		7 6 6   M Lindström
H Ludloff 		1 1  
  E Hakami
G Mosca 		6 1   2 K Adams
Z Garrison 		6 6  
2 K Adams
Z Garrison 		7 6  
gollark: So you can do `2x^4+ px^3 - 6x^2 + qx + 6 = ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d`, and you know the coefficients on x^4 and so on should be equal.
gollark: Which you can then simplify to ax^4 + (b-a)x^3 + (c-b)x^2 + (d-c)x - d.
gollark: ax^4 + bx^3 + cx^2 + dx - ax^3 - bx^2 - cx - d
gollark: If you expand/simplify (x-1)(ax^3+bx^2+cx+d) you get, er, a lot of things, hold on.
gollark: This is a way you can do that, though.

References
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