1983 Bristol Open – Doubles

Doubles
	1983 Bristol Open
Champions	John Alexander; John Fitzgerald
Runners-up	Tom Gullikson; Johan Kriek
Final score	7–5, 6–4

Tim Gullikson and Tom Gullikson were the defending champions, but Tim Gullikson did not participate this year. Tom Gullikson partnered Johan Kriek, losing in the final.

John Alexander and John Fitzgerald won the title, defeating Gullikson and Johan Kriek 7–5, 6–4 in the final.

Seeds

Mark Edmondson / Sherwood Stewart (Semifinals)
Tom Gullikson / Johan Kriek (Final)
Victor Amaya / Hank Pfister (First Round)
John Alexander / John Fitzgerald (Champions)

Draw

Key

Draw

First Round					Quarterfinals					Semifinals					Final

1	M Edmondson S Stewart	6	6	8
	D Gitlin R Van't Hof	7	2	6	1	M Edmondson S Stewart	6	7
	B Drewett C Johnstone	7	6			B Drewett C Johnstone	4	5
	E Edwards J Smith	6	4							1	M Edmondson S Stewart	6	5
4	J Alexander J Fitzgerald	6	6							4	J Alexander J Fitzgerald	7	7
	M De Palmer B Testerman	4	4		4	J Alexander J Fitzgerald	3	6	6
	G Barbosa J Soares	7	3	6		G Barbosa J Soares	6	2	3
	R Harmon R Lewis	6	6	4											4	J Alexander J Fitzgerald	7	6
	L Bourne MS Strode	w/o													2	T Gullikson J Kriek	5	4
	M Dickson N Odizor					L Bourne MS Strode	7	6
	R Acuña M Hocevar	6	7			R Acuña M Hocevar	5	3
3	V Amaya H Pfister	2	5								L Bourne MS Strode	6	6	7
	R Case CB Strode	7	6							2	T Gullikson J Kriek	7	3	9
	F McMillan T Wilkison	6	4			R Case CB Strode	2	2
	J Fillol S Smith	1	4		2	T Gullikson J Kriek	6	6
2	T Gullikson J Kriek	6	6

gollark: I did make a thing for Fibonacci indentation.

gollark: 2 spaces <:bees:724389994663247974><:dodecahedron:724893894822854697>

gollark: More so than some handwritten one would be, most likely.

gollark: It's very\* readable\*\*.

gollark: ```javascriptconst spaces = regex(/^ */)const whitespace = regex(/^[ \n\t]*/)const name = regex(/^[^ \n\t():]+/)const code = many(coroutine(function*() { yield spaces return yield choice([ coroutine(function*() { yield char("(") const x = yield code yield spaces yield char(")") return x }), name ])}))const program = sequenceOf([ many1(coroutine(function*() { yield whitespace const n = yield name yield whitespace yield str(":=") const c = yield code return { code: c, name: n } })), possibly(whitespace)]).map(([x, _]) => x)```parsing™

References

Draw

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