1949 Tour de Hongrie

The 1949 Tour de Hongrie was the 14th edition of the Tour de Hongrie cycle race and was held from 29 June to 3 July 1949. The race started and finished in Budapest. The race was won by André Labeylie.

1949 Tour de Hongrie
Race details
Dates29 June – 3 July
Stages5
Distance1,036[1] km (643.7 mi)
Winning time31h 23' 33"
Results
  Winner  André Labeylie (FRA)
  Second  Rudolf Lauscha (AUT)
  Third  Roger Bourgeteau (FRA)
  Team France (national team)

Route
Stages of the 1949 Tour de Hongrie[1]
Stage Date Route Distance Winner
1 29 June Budapest to Debrecen 229 km (142 mi)  Varnayo (FRA)
2 30 June Debrecen to Miskolc 231 km (144 mi)  Sandru (ROU)
3 1 July Miskolc to Budapest 184 km (114 mi)  Roger Bourgeteau (FRA)
4 2 July Budapest to Keszthely 192 km (119 mi)  André Labeylie (FRA)
5 3 July Keszthely to Budapest 200 km (124 mi)  Varnayo (FRA)
Total 1,036 km (644 mi)

General classification
Final general classification[1][2]
Rank Rider Team Time
1  André Labeylie (FRA) France 31h 23' 33"
2  Rudolf Lauscha (AUT) Austria + 10' 01"
3  Roger Bourgeteau (FRA) France + 15' 02"
gollark: 25G? Incredible.
gollark: Yay, a dino!
gollark: They do lots of crazy PB prize stuff.
gollark: Probably <@159455345024958464>.
gollark: I can also do ARing, and faster.

References
  1. "14. Tour de Hongrie: Francia uralom (1949)". tdh.hu. Retrieved 15 July 2019.
  2. "1949 Tour de Hongrie". First Cycling. Retrieved 15 July 2019.
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