Concat string with variable after a 'grep'

Question

Here is the structure of my file:

g-4.n.g.fr 10.147.243.63 g-4.n.g.fr-w1

Here is my script:

 #! /bin/sh
 ip=10.147.243.63
 worker=$(grep -e $ip $1 | awk '{ print $3; }')
 echo "[Hostname: ]"
 echo $worker
 echo "[Before concat]"
 echo $worker
 echo "[After concat]"
 echo "$worker.v.1"

I have this output:

[Hostname: ]
g-4.n.g.fr-w1
[Before concat]
g-4.n.g.fr-w1
[After concat]
.v.1n.g.fr-w1

I want to have .v.1 after g-4.n.g.fr-w1 without substitution, like this:

g-4.n.g.fr-w1.v.1

How can I modify my script to have this output?

Answer 1

Strange results when playing with strings or parts thereof

First, test your line endings:

$ file test.txt
test.txt: ASCII text, with CRLF line terminators

If you get the above, and in fact don't want DOS line endings, you can use the dos2unix tool:

$ dos2unix test.txt
dos2unix: converting file test.txt to Unix format ...
$ file test.txt
test.txt: ASCII text

Okay, got my data in a consistent format

Your script should work more or less as intended (it does here):

[Hostname: ]
g-4.n.g.fr-w1
[Before concat]
g-4.n.g.fr-w1
[After concat]
g-4.n.g.fr-w1.v.1

if that doesn't work, try:

printf "%s.v.1" "$worker"

I would suggest modifying your script to make it clear that you are using grep to search for a string in the file, and removing plain echo $vars as per Bash pitfalls:

ip="10\.147\.243\.63"
worker=$(grep -e $ip $1 | awk '{ print $3; }')
printf "[Hostname: ]\n"
printf '%s\n' "$worker"
printf "[Before concat]\n"
printf '%s\n' "$worker"
printf "[After concat]\n"
printf '%s.v.1\n' "$worker"