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This came up in a test question and I would like to know the real answer as the possible choices confuse me.
How many hosts can a network handle at the most, based on the following address: 135.46.56.0/22
A: 1024, B: 1023, C: 1022, D: other
So if I'm not mistaken, /22 is 1024 (2^10) hosts. However, I'm not sure if network and broadcast address should be taken into consideration. I have the big book of networking by Tanenbaum and the example shown there doesn't exclude either one. I have an app on my phone that does this calculation and it points out the usable number of IP addresses is 1022 (google also found a claculator that said the usable number was 1023).
Could someone clear this up for me?
Are you a CCNA student? because that comes pretty well explained in your course's docs you know. – arielnmz – 2014-06-11T06:17:41.657
@arielnmz I'm a university student, and I had to google what CCNA stands for, so no, I'm not a CCNA student :) – romeozor – 2014-06-11T07:48:41.877
CCNA is a networking course by Cisco, many schools have it available that's why I was wondering. – arielnmz – 2014-06-11T17:51:41.853