How to grep values under columns

Question

How can I grep for a specific column name and display the value underneath that column.

Sample data:

StandByFile  StandByPg  StandByLSN         StandByRcvBufUsed
S0082160.LOG 621668     0x00000C85118BC72D 0%  

I want to display 0% under StandByRcvBufUsed column. Mind you that file contains other data different from the above displayed columns, meaning there are different column lists in files on different rows.

Thanks

Update:
My file has the following format, so the column #s are not fixed:

HADR Information:
Role    State                SyncMode   HeartBeatsMissed   LogGapRunAvg (bytes)
Standby Peer                 Async    0                  365000              

ConnectStatus ConnectTime                           Timeout   
Connected     Tue May 20 09:34:23 2014 (1400592863) 120       

ReplayOnlyWindowStatus ReplayOnlyWindowStartTime             MaintenanceTxCount
Inactive               N/A                                   0         


PrimaryFile  PrimaryPg  PrimaryLSN        
S0082160.LOG 621668     0x00000C85118BC72D

StandByFile  StandByPg  StandByLSN         StandByRcvBufUsed
S0082160.LOG 621668     0x00000C85118BC72D 0%  

Answer 1

Let's look for the number of column that contains StandByRcvBufUsed and store it. Then, jump to the next line and print that column and finally exit:

$ awk 'f{print $f; exit} {for (i=1; i<=NF; i++) if ($i == "StandByRcvBufUsed") {f=i; next}}' file
0%