This is how I solved my problem (this will logout an idle user after at least 30 minutes of idle time):
First create a file and put this code in it (you might need to install xprintidle before you start):
#!/bin/bash
# Written by cz0 2010, adapted by dror 2013
# Distributed under the terms of the GNU General Public License v2
HALFHOUR=1800000
IDLETIME=`xprintidle`
QDBUS="/usr/bin/qdbus"
if [ $IDLETIME -gt $HALFHOUR ]
then
logger timeout of $HALFHOUR expired. idle is $IDLETIME
KDEPID=$(ps aux | grep 'startkde' | grep -v 'grep' | awk '{print $2}')
KDEUSER=$(ps u $KDEPID | grep 'startkde' | awk '{print $1}')
# If the DBUS_SESSION_BUS_ADDRESS environment variable is not already set correctly
# then set it by finding the environment file for the startkde process in proc and
# parsing it to get get the correct setting.
if [ -z "$DBUS_SESSION_BUS_ADDRESS" ]; then
ENVIRON_FILE=/proc/$(ps h --ppid $KDEPID -o pid | awk '{print $1}')/environ
CURRENT_DBUS_SESSION_BUS_ADDRESS=$(grep -z DBUS_SESSION_BUS_ADDRESS $ENVIRON_FILE | sed -e 's/DBUS_SESSION_BUS_ADDRESS=//')
export DBUS_SESSION_BUS_ADDRESS=$CURRENT_DBUS_SESSION_BUS_ADDRESS
fi
$QDBUS org.kde.ksmserver /KSMServer logout 1 0 2
else
logger timeout is $HALFHOUR not expired $IDLETIME
fi
Now cp it to /bin/
sudo cp myfile /bin/logoutonidle
Next make it executavble
sudo chmod +x /bin/logoutonidle
Next run per the user you want to logout automatically (if needed then run it on every user):
crontab -e
and add to it the following line (this will make cron check every 15 minutes so worst case is that user will be logged out after ~45 idle time):
*/15 * * * * export DISPLAY=:0 && /bin/logoutonidle 2>&1
I would like to thank the people in these threads Bryan and Johanns for pointing me in the right direction.
1Supplement to avoid error reporting: CODI="couldn't open display" if [ "$IDLETIME" -eq "$CODI" ];then exit fi – Klaus-Peter – 2017-04-16T06:04:00.490