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I have a file with a similar format...
16:28 asdfasdf
16:29 4398upte
16:30 34liuthr
16:31 34tertio
How can I use SED to print out every line including and after the line with "16:30"?
The result would be...
16:30 34liuthr
16:31 34tertio
Right now, I am using sed as follows, but I have to manually find the first line's line number e.g. "562697":
sed -n '562697,$p'
What if I needed to search 16/30? I'm not sure how to modify the syntax in this case. Thanks! – barrrista – 2013-03-07T00:01:05.657
@barrrista I've edited my answer to show how to escape the character with a backslash. Hope this helps. – Nicole Hamilton – 2013-03-07T00:12:15.387