run cron on ssh, error message

Question

how to run the script below

* * * * * /usr/bin/wget -O - -q "http://example.com/scheduler/cron"

when i run the script, the error message show as below:

$ * * * * * /usr/bin/wget -O - -q "http://website.com/?q=admin/settings/scheduler/cron"
-sh: CHANGELOG.txt: not found
$ 30 15 * * * /usr/bin/wget -O - -q "http://website.com/?q=admin/settings/scheduler/cron"
-sh: 30: not found

can the script above run in ssh (using putty software)

Answer 1

Crontab files are not scripts. They're configuration files for cron, which runs commands periodically. The first five fields of a line specify the schedule, the rest of the line specifies the command to run at those times. See man crontab for how to submit or edit your personal crontab.

Answer 2

Go to your terminal and do

crontab -e 

which will ask you for editor options. select VIM or whichever you are comfortable with. paste this there.

*/1 * * * * /usr/bin/wget -O - -q "http://example.com/scheduler/cron"

save the file and then things should work

Redirect your commands output to see if things are working. Like this

*/1 * * * * /usr/bin/wget -O - -q "http://example.com/scheduler/cron" >> /home/../asd.log 2>&!

Answer 3

go to terminal and do
crontab -e

and it redirect to this：

Edit this file to introduce tasks to be run by cron.

#

# For example, you can run a backup of all your user accounts
# at 5 a.m every week with:
# 0 5 * * 1 tar -zcf /var/backups/home.tgz /home/

see the attachment image below http://i.imgur.com/aFg8C.jpg

is that add the code on file above?
*/1 * * * * /usr/bin/wget -O - -q "http://example.com/scheduler/cron" on file above?

if yes, how to save the file?
i have press "vi" and press escape, but not working.