24
8
For example, I have date: 4 August 1993 and I want to add 348 days to it, how can I do it in bash?
24
8
For example, I have date: 4 August 1993 and I want to add 348 days to it, how can I do it in bash?
30
Just use the date
command with -d
option:
$ date -d "1983-08-04 348 days"
Tue Jul 17 00:00:00 BST 1984
You can change the output format if you want:
$ date -d "1983-08-04 2 days" +%Y-%m-%d
1983-08-06
12
In bash on Mac OS X, you can do this:
date -j -v +348d -f "%Y-%m-%d" "1993-08-04" +%Y-%m-%d
Output: 1994-07-18
1Been looking for this for a while. I appreciate. I wanted to replace the number "348" with a variable from a bash script. I ended up with NEXT_DATE=$(date -j -v +$(( incrementDays ))d -f "%Y-%m-%d" "1993-08-04" +%Y-%m-%d)
for anyone else looking to do this. – Ian G – 2019-01-15T21:11:50.213
1
Here is a little more complex usage of this:
for i in `seq 1 5`;
do;
date -d "2014-02-01 $i days" +%Y-%m-%d;
done;
or with pipes:
seq 1 5 | xargs -I {} date -d "2014-02-01 {} days" +%Y-%m-%d
1You can use the OP's date format, too:
date -d "4 August 1993 348 days" +"%d %B %Y"
– Paused until further notice. – 2009-09-23T16:54:35.2571According to man date:
%F full date; same as %Y-%m-%d
– jperelli – 2012-05-02T21:58:55.243