1
how do I print the value in col 2 as many times as it is specified in col 1.
10 -11
9 -10
7 -9
7 -8
7 -7
12 -6
362 -1
271 1
94 2
41 3
17 4
13 5
16 6
5 7
expected output:
-11
-11
-11
-11
-11
-11
-11
-11
-11
-11.....so on and so forth...
Gavin
Posted 2019-04-18T21:48:56.947
Reputation: 13
1
This perl one-liner does the job:
perl -ane '($x,$y)=split;print"$y\n"x$x' file
Outoout:
-11
-11
-11
-11
-11
-11
-11
-11
-11
-11
-10
-10
-10
-10
-10
-10
-10
-10
-10
...
Explanation:
($x,$y)=split; # split the values from each line ($x=first value, $y=second value)
print"$y\n"x$x # print $x times the value $y followed by line break
Toto
Posted 2019-04-18T21:48:56.947
Reputation: 7 722
Can you explain it some more and give a better example? If the expected output is -11 -11 -11 and so on, continuing that pattern seems rather easy. – Alex Cannon – 2019-04-18T21:51:49.320
There are two columns each have values. How can we print the value in the second col as many times as it is stated in the first col? If the value is -11 in col. 2 and the corresponding value in col 1 is 10 then it should be repeated 10 times. The value -11 should be printed in a new line each time. Similarly, this should be repeated for all the values in col 2 corresponding to the value in col 1. – Gavin – 2019-04-18T21:54:25.493
I understand now. If column 1 row 1 contains 4, and column 2 row 1 contains 6, it should print out 6 6 6 6 with each 6 on a new line. – Alex Cannon – 2019-04-18T21:57:40.280