1
(1,200)
and (1000,10)
(those are the points at the right and left border).(0,2.301)
, (3,1)
.y = ax+b
=> 2.301 = 0a +b
; 1 = 3a +b
=> the first one conveniently collapses to b=2.301
, and using this in the second one gives a=-1.301/3=-0.434
So your line is y = -0.434 x + 2.301
, and if you want it back in the base variables log(p) = -0.434*log(t) + 2.301
Welcome to Super User. What have you tried? – I say Reinstate Monica – 2016-09-03T19:44:42.840