My bash script's if / then check is always evaluating to true

Question

I was trying to write a bash script to handle a conditional switch, and it kept evaluating to true every time. So, I stripped it down to this, and I was getting the same behavior of it always echoing whatever parameter I sent it instead of only when sending it -c:

myfunc(){
if [[ $1 == "-c" ]];
  then
    echo $1
  fi
}

Answer 1

While I can't answer why this was always evaluating to true, I was able to fix it. I ended up having to remove the quotes from the switch, thus making the working version look like this:

myfunc(){
if [[ $1 == -c ]];
  then
    echo $1
  fi
};

Per Darth Android's suggestion, just keep the quotation marks consistent between the two comparisons, which is safer.

myfunc(){
if [[ "$1" == "-c" ]];
  then
    echo $1
  fi
};