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While playing CTF competition I came across this ARJ
files. After doing some research found out that.
ARJ is Archiver for .arj files and Like most archive file types, they're used to store and compress multiple files and folders into one easily manageable file.
I Want to extract this ARJ files. I have 4 files named as 36 , 18914 , 19880 , E723
.
I tried this command
arj e 36
It gives this error,
Can't find 36.arj
Found 1 error(s)!
So, I renamed this files as 36.arj , 18914.arj , 19880.arj , E723.arj
And tried this command
arj e 36.arj
It gives this error,
Processing archive: 36.arj
Archive created: 2019-01-31 17:33:18, modified: 1970-01-01 21:54:09
Bad header
UPDATE : The CTF is finally over and I read the write up related to this question. Actually I was digging the wrong hole. The main file that was given in the question was corrupted and we had to correct the headers
. And later we have to extract that file using binwalk
. Again thanks to kamil and roberts
How about you rename (
mv
) the file so the name ends with.arj
? – Kamil Maciorowski – 2019-02-03T19:18:28.7771OK. Please [edit] the question and put this information about your research there, so it's all in the question body, not (partially) in comments. Also add the output of
file 36.arj
(or whatever the name is). – Kamil Maciorowski – 2019-02-03T19:29:05.1002It's possible that fixing the header is a part of the task in the competition. – Kamil Maciorowski – 2019-02-03T19:42:22.577
@KamilMaciorowski Might be. Added few more details related to question. – Smshrimant – 2019-02-04T06:08:36.047