Linux - Print specific line from output

Question

I am used to working with single line output and can use $1 $4 $8 to specify certain items in that line, but I have never worked with multiple line outputs and would like to just print one line instead of all of it to a log file. Here is the output I am working with:

# bitcoind getinfo
{
"version" : 80100,
"protocolversion" : 70001,
"walletversion" : 60000,
"balance" : 0.00000000,
"blocks" : 352256,
"connections" : 0,
"proxy" : "",
"difficulty" : 49446390688.24143982,

"paytxfee" : 0.00000000,
"errors" : ""
}

I would like to print just the "balance" : 0.00000000," line to a log file, right now I have all of the output going to the log file with the time ran. I am just not sure how to print a line from an output that is not single line.

Why did I get a downvote, i am new to Linux and dont know every command out there

well ok! I was stuck on using awk and print with $1 $2 etc... — LinHost, Apr 24 '15 at 19:43
Mouse over the down arrow; the popup says "*This question does not show any research effort; it is unclear or not useful*". Downvotes without comment may be presumed to be for at least one of those reasons. — MadHatter, Apr 24 '15 at 19:50
You could do it with awk just fine `awk '/pattern/ {print}'`. — Zoredache, Apr 24 '15 at 20:19

score 2 · Accepted Answer · edited Apr 25 '15 at 11:24

2

As @Hyppy stated you need to use grep in any of these ways:

Against a file: grep balance filename
At the end of a pipe: somecommand | grep balance
With extended regex : grep -E '^"balance":'

edited Apr 25 '15 at 11:24

moebius_eye

1,092
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answered Apr 24 '15 at 19:25

alphamikevictor

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Linux - Print specific line from output

1 Answers1