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I'm trying to follow the advice from this TechNet article about partition alignment. Our San is an EMC, the disks are in a 4 disk raid 10. This services an I/O intensive application, 60:40 write:read.

According to the wmic query in the article for Partition_Offset, I get 1048576.

According to my SAN administrator the Stripe_Unit_Size is 524288000. Does that even sound right?

The simple calculation to find if you're aligned or not is:

Partition_Offset ÷ Stripe_Unit_Size 1048576 / 524288000 = .002

This is not an integer, so it appears we are not aligned.

Using diskpart to reformat the drives, what Partition_Offset and File_Allocation_Unit should we use?

Aaron Bertrand
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    What version of Windows? Recent ones just sort this all out for you automatically – Chopper3 Apr 20 '15 at 17:43
  • [Disk Partition Alignment - from Jimmy May](http://blogs.msdn.com/b/jimmymay/archive/2009/05/08/disk-partition-alignment-sector-alignment-make-the-case-with-this-template.aspx) and [this article from mssqltips](http://www.mssqltips.com/sqlservertip/2119/partition-offset-and-allocation-unit-size-of-a-disk-for-sql-server/) will help you. – Kin Shah Apr 20 '15 at 19:43

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