Is there a way to create a single 2TB partition, which is 4096-byte-sector aligned, on a disk using the standard Linux fdisk (I have tried version 2.17.2)?
I've tried the following things and ran into the described error:
- If I simply use the
-u
flag, it sets the cluster size to one sector of 512 byte. Then, the partition would have to be 3,906,250,000 clusters long and fdisk truncates this number to 2,147,483,647 (2^31-1). - If I use
-b 4096
, it allows me to create the partition just fine (with length 488,281,506 sectors), but if I check the size of the resulting partition usingblockdev --getsize64
, it shows that the partition is only 250GB big, i.e. it is still using a sector size of 512. - If I try to set the sector and head count using
-S 64 -H 32
, for example, then it always sets the sector count back to 63, which doesn't divide evenly into 4096 (I know, 32 dividing evenly by 8 is technically enough, but - call me perfectionist - I'd really like to have the partition start at sector 2048 (1MB aligned), as I read is the recommended setting these days.
Is there some combination of parameters that I can pass to fdisk, that will allow me to create a partition that starts at 1MB (sector 2048 [256] for 512-[4096-]byte sectors) and is exactly 2TB long (3,906,250,000 [488,281,506] sectors for 512-[4096-]byte sectors)?
(I read that I can just use gparted and have it change the drive to GPT partitioning, but I'd really like to know if there is a way to do it with standard fdisk and an MBR partition. I don't see a reason why MBR partitions shouldn't allow for this...)