If a IP address is 192.168.112.28 what does each quadrant represent in this IP address?
Asked
Active
Viewed 2,063 times
-2
-
possible duplicate of [How does IPv4 Subnetting Work?](http://serverfault.com/questions/49765/how-does-ipv4-subnetting-work) – EEAA Feb 27 '13 at 04:38
-
An IPv4 address is 32 bits, the pieces are simply the bytes in the address written in decimal. – vonbrand Feb 27 '13 at 13:29
-
for reference, its also called an octet. – Sirex Feb 27 '13 at 23:33
2 Answers
4
It is a 32-bit unsigned integer, converted into four 8-bit unsigned integers so that humans can read it more easily. The numbers are represented most-significant-bit-first.
Michael Hampton
- 237,123
- 42
- 477
- 940
-
1Which is why you can `ping 3232264220` and it will work (well, if you have a `192.168.112.28` on your network anyway) – Mark Henderson Feb 27 '13 at 04:46
-
thanks for the reply, yes.. they are 32-bit unsigned integers. but i want to know what exactly those integers represent. ex: 192/11000000 -represents a port or something – chamz33 Feb 27 '13 at 05:31
-
1I don't understand what you're trying to ask there. Ports are not part of an IP address, and that example doesn't correspond to anything. – Michael Hampton Feb 27 '13 at 05:33
-
-1
IP address consists of 32 bits, it is represented as 4 octets of numbers from 0-255 instead of binary form. For example, the IP address: 192.168.112.28 in binary form is 11000000.10101000.01110000.0011100
ks_1010
- 121
- 1
- 2
- 8