Command to monitor which processes have a given file open

Question

I know I can use lsof path/to/file to see which processes currently have a given file open.

Is there a top-like command I can use to continuously monitor which processes have a given file open?

Answer 1

Take a look the +|-r option for repeat mode:

$ lsof -r 1 path/to/file

You can also use the watch command:

$ watch -n 1 'lsof path/to/file'

Answer 2

Instead of lsof, I would suggest using fuser(1), especially since you say you want to watch for processes, and not ports or users or anything else.