Redifferencing multiple checkpoint-avhdx'es agains the root vhdx instead of an intermediate avhdx

Question

I'm currently in this situation of differentiating avdhx-files where A1, A2, B and C represents the actual checkpoints I'm using.

I would like to convert A1 and A2 into differentials directly against master.vhdx like B and C are, removing the dependency to A.

Is this possible?

Are these standalone differential files or do they belong to checkpoints? — Eric Siron, Mar 06 '20 at 15:25
@EricSiron A1, A2, B and C belong to checkpoints. A does not, but A1 and A2 depend on it. I'm not sure how this happened. — Alex, Mar 06 '20 at 16:35

score -1 · Answer 1 · answered Mar 10 '20 at 17:46

-1

Make a copy of A and A1. Call them D and D1. (If you're using ReFS, this copy won't actually need to replicate the data.) Then use the Merge-VHD PowerShell cmdlet (or any other method) to merge D1 into D. (Again, if you're using ReFS, this won't actually move any data.) D is now the VHD that you want from A1. Replicate the process for A2.

answered Mar 10 '20 at 17:46

Jake Oshins

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Thank you Jake! I see that someone downvoted your answer, any idea why? – Alex Mar 15 '20 at 18:04

Redifferencing multiple checkpoint-avhdx'es agains the root vhdx instead of an intermediate avhdx

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