Convert to Bibi-binary

Question

Bibi-binary is a numeric system invented by Boby Lapointe in order to represent numbers in letters which pronunciation seems funny.

Your task is to convert decimal numbers into Bibi-binary!

Conversion

A number is converted to base 16 (hexadecimal) and each character is replaced by its Bibi-binary name:

0 = HO
1 = HA
2 = HE
3 = HI
4 = BO
5 = BA
6 = BE
7 = BI
8 = KO
9 = KA
A = KE
B = KI
C = DO
D = DA
E = DE
F = DI

Let N be a positive integer (between 1 -> 2^31-1). For every character in the hexadecimal representation of N, replace the character by its according Bibi-binary pair (the table above contains all the pairs).

Example

• N = 156
• H = (hexadecimal representation of N) --> 9C
• 9 --> KA, C --> DO

Thus the output is KADO.

Input & output

You will receive an positive 32-bit integer N, which you will have to turn into Bibi-binary.

You may (return, print, etc...) in any convenient format, but the pairs have to be connected! So KA DO wouldn't be okay, but KADO would.

Both, lowercase and uppercase are allowed.

Rules

• No loopholes.
• This is code-golf, so the shortest code wins.

Testcases

2048 -> KOHOHO
156 -> KADO
10000 -> HEBIHAHO
12 -> DO

Answer 1

05AB1E, 20 18 16 bytes

hv…ÂkdžM¨ÁâyHèJ

Explanation

h                     # convert input to hex
 v                    # for each
  …Âkd               # string of the possible first Bibi-binary letters
       žM¨Á           # string of the possible second Bibi-binary letters
           â          # cartesian product to produce list of Bibi-binary pairs
            yH        # convert hex char to base 10
              è       # use this to index into the list
               J      # join

Try it online!

Saved 2 bytes thanks to Adnan

Answer 2

Python 2, 58 bytes

f=lambda n:(n>15and f(n/16)or"")+"HBKD"[n/4%4]+"OAEI"[n%4]

A recursive solution. Try it on Ideone.

Answer 3

Python 2, 81 76 bytes

lambda n:''.join('HBKD'[int(x,16)/4]+'OAEI'[int(x,16)%4]for x in hex(n)[2:])

Chooses the bibi-digit to represent each hex digit based on the patterns in the bibi-digits.

Answer 4

Javascript (ES6), 58 53 43 bytes

f=n=>n?f(n>>4)+'HBKD'[n/4&3]+'OAEI'[n&3]:''

Saved 10 bytes (no support for n = 0 anymore)

Demo

var f=n=>n?f(n>>4)+'HBKD'[n/4&3]+'OAEI'[n&3]:''

console.log(f(2048));   // -> KOHOHO
console.log(f(156));    // -> KADO
console.log(f(10000));  // -> HEBIHAHO
console.log(f(12));     // -> DO

Answer 5

Pyth, 28 bytes

L+?>b15y/b16k@*"HBKD""OAEI"b

Defines a function y. Basically the same algorithm as my Python answer.

Explanation:

L                            # Define a function, y, with an argument, b.
  ?>b15                      # If b > 15, then:
       y/b16                 # Call y with b / 16, else:
            k                # The empty string.
 +                           # Append with
              *"HBKD""OAEI"  # The Cartesian product of "HBKD" and "OAEI". Gives all the letter pairs in order
             @             b # Get the b'th number from that list. Because @ in Pyth is modular, we don't need to take b % 16.

Try it here! (The extra two chars at the end is just to call the function)

Answer 6

Ruby, 55 51 bytes

A recursive anonymous function:

f=->i{(i>15?f[i/16]:'')+'HBKD'[i%16/4]+'OAEI'[i%4]}

Call it for example with f[156] and it returns "KADO"

Answer 7

PHP ,63 Bytes

contribution by @Titus Thank You

for($n=$argv[1];$n;$n>>=4)$r=HBKD[$n/4&3].OAEI[$n&3].$r;echo$r;

72 Bytes works also with zero

do$r=OAEIHBKD[$t*4+($n=&$argv[1])%4].$r;while(($t=!$t)|$n=$n>>2);echo$r;

76 Bytes alternative Version

for($i=2*strlen(dechex($n=$argv[1]));$i;)echo HBKDOAEI[$i%2*4+$n/4**--$i%4];

Answer 8

Jelly, 17 bytes

b⁴d4ị"€“BKDH“AEIO

Try it online! or verify all test cases.

How it works

b⁴d4ị"€“BKDH“AEIO  Main link. Argument: n

b⁴                 Convert n to base 16.
  d4               Divmod 4; map each base-16 digit k to [k / 4, k % 4].
       “BKDH“AEIO  Yield ["BKDH", "AEIO"].
      €            For each quotient-remainder pair [q, r]:
    ị"               Yield "BKDH"[q] and "AEIO"[r] (1-based indexing).

Answer 9

J, 35 33 bytes

[:,(,/'HBKD',"0/'OAEI'){~16#.inv]

Generates the table of bibi-binary values for integers [0, 16), then converts the input n to a list of base 16 digits and selects the corresponding bibi-binary name for each hex digit.

Saved 2 bytes thanks to @randomra.

Usage

   ,/'HBKD',"0/'OAEI'
HO
HA
HE
HI
BO
BA
BE
BI
KO
KA
KE
KI
DO
DA
DE
DI

This part generates a 16 x 2 array of characters for the bibi-binary name of each hex digit.

   f =: [:,(,/'HBKD',."0 1'OAEI'){~16#.inv]
   f 156
KADO
   f 2048
KOHOHO

Explanation

,/'HBKD',"0/'OAEI'
  'HBKD'    'OAEI'  Constant char arrays
        ,"0/        Form the table of joining each char with the other
,/                  Join the rows of that table

[:,(,/'HBKD',."0 1'OAEI'){~16#.inv]  Input: n
                                  ]  Identity function, get n
                           16#.inv   Performs the inverse of converting an array of
                                     hex digits meaning it converts a value to a list of
                                     hex digits
   (,/'HBKD',."0 1'OAEI')            Create the bibi-binary names of each hex digit
                         {~          For each hex digit, select its bibi-binary name
[:,                                  Join the names to form a single string and return

Answer 10

Perl, 52 51 bytes

Includes +1 for -p

Run with the number on STDIN

bibi.pl <<< 156

bibi.pl:

#!/usr/bin/perl -p
1while$\=(<{H,B,K,D}{O,A,E,I}>)[$_%16].$\,$_>>=4}{

Answer 11

Ruby, 85 83 bytes

->x{x.to_s(16).chars.map{|d|"HOHAHEHIBOBABEBIKOKAKEKIDODADEDI"[2*d.to_i(16),2]}*''}

Just a quick and simple solution without encoding the string.

Answer 12

Pyth, 21 bytes

sm@*"HBKD""OAEI"djQ16

A program that takes input of an integer from STDIN and prints the result.

Try it online

How it works

sm@*"HBKD""OAEI"djQ16  Program. Input: Q
                 jQ16  Yield decimal digits of the base-16 representation of Q as a list
    "HBKD"              Possible first letters
          "OAEI"        Possible second letters
   *                    Cartesian product of those two strings
  @                     Index into the above
 m              d      Map that across the digits list
s                      Concatenate
                       Implicitly print

Answer 13

PHP, 93 bytes

$a=HBKDOAEI;$h=dechex($argv[1]);while($h{$i}!=''|$c=hexdec($h{$i++}))echo$a{$c/4}.$a{4+$c%4};

This basically leverages the integrated hexadecimal functions and a little trick in the while statement to save on curly braces.

Answer 14

Java, 224 bytes

class N{public static void main(String[]a){String x="0HO1HA2HE3HI4BO5BA6BE7BI8KO9KAaKEbKIcDOdDAeDEfDI";for(int c:Long.toHexString(Long.valueOf(a[0])).toCharArray()){c=x.indexOf(c)+1;System.out.print(x.substring(c++,++c));}}}

Using some lookup table trickery Usage of Long type was to shave off a few bytes compared to Integer

Answer 15

Dyalog APL, 19 bytes

Requires ⎕IO←0 which is default on many systems.

∊(,'HBKD'∘.,'OAEI')[16⊥⍣¯1⊢⎕]

∊ enlist (make completely flat)

(...

 , the raveled

 'HBKD'∘.,'OAEI' concatenation table (i.e. all combos)

)[ indexed by...

 16⊥⍣¯1 the inverse of base-16 to base 10 (i.e. base-10 to base 16) representation

 ⊢ of

 ⎕ the numeric input

]

TryAPL online!

Answer 16

CJam, 20 bytes

qiGb"HBKD""OAEI"m*f=

Try it online! (As a linefeed-separated test suite.)

Explanation

qi      e# Read input and convert to integer.
Gb      e# Get hexadecimal digits.
"HBKD"  e# Push this string.
"OAEI"  e# Push this string.
m*      e# Cartesian product, yields ["HO" "HA" "HE" "HI" "BO" ... "DE" "DI"].
f=      e# For each digit, select the corresponding syllable.

Answer 17

Lua, 196 Bytes

function(n)s=""t={"H","B","K","D"}p={"O","A","E","I"}while n>0 do s=n%4 ..s n=math.floor(n/4)end s=("0"):rep(#s%2)..s o=nil return s:gsub(".",function(s)o=not o return o and t[s+1]or p[s+1]end)end

Lua is annoying for this sort of a task, as it doesn't per default contain a hex or binary conversion method. Most of the flesh is converting it to base 4. After that we force a 0 behind it if we need to using s=("0"):rep(#s%2), then we using gsub replace all the didgets with with their BIBI counterpart.

Answer 18

Chip, 174 bytes

 z---.
!+ZZZ^~s
Axxx])~-vv/c
Ex]xx' ,x]/b
Bxxx])~^}~/d
Fx]xx'g*-}^a
Cxx])v]--/c
G]xx'>x~v/d
Dxx])x+-]/a
H]xx'`}--/b
 )x)-----'
Axx].zv~S
Bxx]+^'
Cxx]<
Dxx]<
E]v-'
F]<
G]<
H]'

Try it online! TIO includes a Bash wrapper that converts an integer string to an actual 32-bit integer value.

The top half prints out the letters corresponding to the binary data, once the bottom half has detected that we've reached the interesting data (in other words, we skip leading zeroes. To print all leading zeroes, remove the second line that starts with A and down.