Convert string to time

2

1

This challenge is inspired by this other.

The challenge

Write a program or a function in any programming language that given as input a string representing a time in English (see below, for further details) it outputs or prints the equivalent in the 24 hours "digital" format HH:MM.

Shortest code in bytes wins, standard loopholes are forbidden.

Input format

Your program should be able to handle all this kind of inputs:

one minute past 'HOUR'
'MINUTES' minutes past 'HOUR'
quarter past 'HOUR'
half past 'HOUR'
one minute to 'HOUR'
'MINUTES' minutes to 'HOUR'
quarter to 'HOUR'
'HOUR'
'HOUR12' 'MINUTES' AM
'HOUR12' 'MINUTES' PM

where: MINUTES is a number from 1 to 59 written in English with hyphen; HOUR is the name of an hour in one of the formats:

midnight
noon
midday
'HOUR24' o'clock
'HOUR12' o'clock AM
'HOUR12' o'clock PM

HOUR12 is a number from 1 to 12 written in English with hyphen; and HOUR24 is a number from 1 to 23 written in English with hyphen.

Some examples

midnight                                  ->   00:00
midday                                    ->   12:00
twelve o'clock                            ->   12:00
quarter to midnight                       ->   23:45
twenty-two minutes past eight o'clock PM  ->   20:22
thirty-four minutes to fifteen o'clock    ->   14:26
six o'clock AM                            ->   06:00
one minute to twenty-one o'clock          ->   20:59
seven thirteen AM                         ->   07:13
nine fourteen PM                          ->   21:14

Good luck!

Bob

Posted 2016-02-06T14:59:04.273

Reputation: 957

So is 'MINUTES' minutes past 'HOUR24' o'clock a valid time? – Blue – 2016-02-06T15:06:39.370

@muddyfish Yes, it is. – Bob – 2016-02-06T15:08:34.383

2Should HOUR24 be a number from 0 to 23? – ETHproductions – 2016-02-06T15:21:12.540

1@ETHproductions No, from 1 to 23. "zero o'clock" doesn't sound well. – Bob – 2016-02-06T16:41:24.160

@Bob neither does "24 o-clock" or "23-oclock" – cat – 2016-07-07T13:30:20.580

Answers

2

Ruby, 653 597 Bytes

P=/ past | to /;T=%w{q twen thirty fourty fifty sixty el twe thi fourte fifte sixt sevent eighte ninet o tw th fo fi si s e n t}.zip([15,*(2..6).map{|i|i*10},*11..19,*1..10]).to_h;D={'middnight'=>0,'midday'=>12,'noon'=>12};n=->s{s.split('-').reduce(0){|p,v|(Array(T.find{|k,_|v.start_with? k}).last||0)+p}};i=->s{m=0;s=s.gsub(/^\s+|\s+$/,'');c=s.split(P);(c.reverse! if s.match(P));h=D[c[0]]||n.(c[0].gsub(/ o\'clock (A|P)m/,''));h+=(s.end_with?('PM') ? 12 : 0);m=n.(c[1]||c[0].split(' ')[1]) if c[1]||c[0].match(/^\w+ (?!o'clock)/);(m=60-m;h=(h-1)%24)if s.match(/ to /);(sprintf '%02d:%02d',h,m)}

Ungolfed:

P=/ past | to /
# configuration for translating english words to numbers
T=%w{q twen thirty fourty fifty sixty el twe thi fourte fifte sixt sevent eighte ninet o tw th fo fi si s e n t}.zip([15,*(2..6).map{|i|i*10},*11..19,*1..10]).to_h
D={'middnight'=>0,'midday'=>12,'noon'=>12}

# proc for translating english word groups to a number
n=-> s {
  s.split('-').reduce(0) { |p,v|
    (Array(T.find {|k,_| v.start_with? k}).last || 0) + p
  }
}

i=-> s {
  m=0
  s=s.gsub(/^\s+|\s+$/,'')
  c=s.split(P)
  (c.reverse! if s.match(P))

  # set the hour
  h=D[c[0]]||n.(c[0].gsub(/ o\'clock (A|P)m/,''))
  h+=(s.end_with?('PM') ? 12 : 0)

  # set the minute
  m=n.(c[1]||c[0].split(' ')[1]) if c[1]||c[0].match(/^\w+ (?!o'clock)/)

  # adjust for 'past'
  (m=60-m;h=(h-1)%24)if s.match(/ to /)

  sprintf '%02d:%02d',h,m
}

Verification script used:

examples = <<EXAMPLES
midnight                                  ->   00:00
midday                                    ->   12:00
twelve o'clock                            ->   12:00
quarter to midnight                       ->   23:45
twenty-two minutes past eight o'clock PM  ->   20:22
thirty-four minutes to fifteen o'clock    ->   14:26
six o'clock AM                            ->   06:00
one minute to twenty-one o'clock          ->   20:59
seven thirteen AM                         ->   07:13
nine fourteen PM                          ->   21:14
EXAMPLES

examples.split("\n").each do |example|
  text, expected = example.split(/\s+->\s+/)
  r = i.(text)
  raise "Unexpected result for \"#{text}\". Got \"#{r}\", expected \"#{expected}\"" unless r == expected
  print "."
end

Thank you to Kevin Lau for 47 bytes of optimization

Daniel Evans

Posted 2016-02-06T14:59:04.273

Reputation: 121

[15,*(2..6).map{|i|i*10},*11..19,*1..10] is a much more concise representation of the numbers you are using to construct your hash. Also, there's a lot of whitespace you can remove between brackets, and using Ruby interpolation within regex patterns allows you to replace v.start_with? k with v=~/^#{k}/ – Value Ink – 2016-07-06T00:43:36.937

I should have thought of the ranges and splats, thanks! Also removed some unnecessary whitespace. – Daniel Evans – 2016-07-06T04:27:00.290