Convert the Time to a String

Question

Problem

One day, you boss walks up to you and tells you he needs to know the time. He still insists after you pointing at the clock directly above you head, and confesses he has a severe case of dyscalculia, which causes him to not even be able to see numbers on a clock. While you're still left wondering how someone unable to see numbers can run a company, he tells you to "do something about it", whatever that is.

Your task is now to create a program or function that, given an input time with hours and minutes (seconds are optional)(hours are 24-based), outputs a readable english sentence, that doesn't contain numbers.

It is not necessary to ouput the seconds.

For example, 08:45:15 should output quarter to nine o'clock AM

Test cases

00:00:00 > twelve night
12:00:00 > twelve noon
06:00:00 > six o'clock AM
18:00:00 > six o'clock PM
06:15:00 > quarter past six o'clock AM
18:45:00 > quarter to seven o'clock PM
11:30:00 > half past eleven o'clock AM
13:22:00 > twentytwo minutes past one o'clock PM
17:43:00 > seventeen minutes to six o'clock PM
00:09:00 > nine minutes past twelve o'clock AM

Rules

Outputting numbers can be both in the form of fortytwo or forty-two, whichever you like best. Standard loopholes are not allowed. Trailing newlines are allowed, but the sentence should be on 1 line.

Input can be in any format you want, for example HH:MM:SS, HH,MM,SS, HHMMSS, HH/MM/SS, or any variant without seconds, but you should make the input format clear in your answer. It's not needed to output one minute instead of one minutes

for minutes ranging from 0 trough 30 (0 and 30 included) you should use past, and for the others you should use to

Because time is relative, shortest code in bytes wins.

Answer 1

Javascript, 384 381 bytes

(h,m)=>(o='one,two,three,four,five,six,seven,eight,nine,ten,eleven,twelve,thir,,fif,,,eigh,'.split`,`,o=o.map((x,i)=>i>11?(x||o[i-10])+'teen':x),(a=m>30,t=12,m?(m-30?m%15?((m=a?59-m:m)>=(b=a?19:20)?'twenty'+((m%=b)?o[a?m:m-1]:''):o[a?m:m-1])+' minutes':'quarter':'half')+(a?' to ':' past '):'')+(h%t|m?o[(a?h:(h?h-1:11))%t]+` o'clock ${h>t?'P':'A'}M`:o[11]+(h-t?' night':' noon')))

f=
(h,m)=>(
    o='one,two,three,four,five,six,seven,eight,nine,ten,eleven,twelve,thir,,fif,,,eigh,'.split`,`,
    o=o.map((x,i)=>i>11?(x||o[i-10])+'teen':x),
    (a=m>30,t=12,
    m?
        (m-30?
            m%15?
                ((m=a?59-m:m)>=(b=a?19:20)?
                    'twenty'+((m%=b)?o[a?m:m-1]:'')
                :o[a?m:m-1])+' minutes'
            :'quarter'
        :'half')+(a?' to ':' past ')
    :'')
    +(h%t|m?
        o[(a?h:(h?h-1:11))%t]+` o'clock ${h>t?'P':'A'}M`
    :o[11]+(h-t?' night':' noon'))
)

document.body.innerHTML = '<pre>' +
'f(00,00) = ' + f(00,00) + '\n' +
'f(12,00) = ' + f(12,00) + '\n' +
'f(06,00) = ' + f(06,00) + '\n' +
'f(18,00) = ' + f(18,00) + '\n' +
'f(06,15) = ' + f(06,15) + '\n' +
'f(18,45) = ' + f(18,45) + '\n' +
'f(11,30) = ' + f(11,30) + '\n' +
'f(13,22) = ' + f(13,22) + '\n' +
'f(17,43) = ' + f(17,43) + '\n' +
'f(00,09) = ' + f(00,09) + '\n' +
'f(23,59) = ' + f(23,59) + '\n' +
'</pre>'

Answer 2

LaTeX, 466 bytes

\usepackage{fmtcount,etoolbox}\def\x{\the\numexpr}\def\n[#1]{\numberstringnum{#1}}\def\h[#1]{\ifnumequal{#1}{0}{twelve night}{\ifnumequal{#1}{12}{twelve noon}{\ifnumless{#1}{13}{\n[#1] o'clock AM}{\n[\x#1-12\relax] o'clock PM}}}}\def\m[#1]{\ifnumequal{#1}{15}{quarter}{\ifnumequal{#1}{30}{half}{\n[#1] minutes}}}\newcounter{c}\def\f[#1]#2{\ifnumequal{#2}{0}{\h[#1]}{\ifnumless{#2}{31}{\m[#2] past \h[#1]}{\setcounter{c}{\x60-#2\relax}\m[\thec] to \h[\x#1+1\relax]}}}

Just call the macro \f as \f[hour]{minutes}, here some tests:

\begin{document}

\noindent
\textbf{Test cases:} \\ \\
00:00 = \f[00]{00} \\
12:00 = \f[12]{00} \\
06:00 = \f[6]{00} \\
18:00 = \f[18]{00} \\
06:15 = \f[6]{15} \\
18:45 = \f[18]{45} \\
11:30 = \f[11]{30} \\
13:22 = \f[13]{22} \\
17:43 = \f[17]{43} \\

\noindent
\textbf{More test cases:} \\ \\
00:13 = \f[00]{13} \\
12:12 = \f[12]{12} \\
12:15 = \f[12]{15} \\
11:45 = \f[11]{45} \\
11:41 = \f[11]{41} \\

\end{document}

Answer 3

Python 2, 498 bytes

Input comes as function argument. First hour and then minute, both as integer. Result gets printed to the screen.

def g(h,m):
 a=lambda x:"twelve one two three four five six seven eigth nine ten eleven".split()[x%12];b=lambda x:a(x)+" o'clock "+["AM","PM"][x>=12]
 if m:
    z=m if m<30else 60-m;print(a(z)if z<13else("twenty"+(a(z-20)if z-20else"")if z>19else"thirteen fourteen fifteen sixteen seventeen eighteen nineteen".split()[z-13])if m%15else"quarter"if m-30else"half")+(" minutes"if m-30and m%15else"")+[" past "+b(h)," to "+b(h+1)][m>30]
 else:print"twelve "+("noon"if h else "night")if h in[0,12]else b(h)

Try it online! (with slightly extended testcases)

That was a pretty fun golf. Although all those nested ternaries drove me a little bit crazy ^^
I was planning on doing this in Pyth after this, but I don't think that I am mentally able to do this at the moment (or ever).

Ungolfed:

def ungolfed(h,m):
    toStr=lambda x:"twelve one two three four five six seven eigth nine ten eleven".split()[x%12]
    hour=lambda x:toStr(x)+" o'clock "+["AM","PM"][x>=12]
    minute=lambda x:"twenty"+(toStr(x-20)if x-20else"")if x>19else"thirteen fourteen fifteen sixteen seventeen eighteen nineteen".split()[x-13]

    if m:
        s=""
        if m==30:
            s+="half"
        else:
            if m%15==0:
                s+="quarter"
            else:
                z=m if m<30 else 60-m
                if z<13:
                    s+=toStr(z)
                else:
                    s+=minute(z)
        print s+(" minutes"if m-30and m%15else "")+[" past "+hour(h)," to "+hour(h+1)][m>30]
    else:
        if h in[0,12]:
            print"twelve "+("noon"if h else "night")
        else:
            print hour(h)

Answer 4

Perl 5, 367 361 385 Bytes

Garbled

use integer;$_=<>;~/(\d+):(\d+)/;@b=(one,two,three,four,five,six,seven,eight,nine,ten,eleven,twelve); @x=(@b,thirteen,(map{/fi/?quarter:$_.teen}@b[3..8]),(map{twenty.$_}'',@b[0..8]),half);@y=map{/^q|h/?$_:$_.' minutes'}@x;$s=1-$2/31;$y=abs((-29,0)[$s]+$2%31)-1;$h=$1-$s;print((+-$2?@y[$y].' '.(to,past)[$s].' ':'').@b[$h++%12]." o' clock ".($h%12?(AM,PM)[$h/12]:(night,noon)[$h/12%2]))

Formatted and test cases:

use integer;
map{
    # capture (implicit $_)
    ~/(\d+):(\d+)/;
    # bare words
    @b=(one,two,three,four,five,six,seven,eight,nine,ten,eleven,twelve);
    # construct up to 30
    @x=(@b,thirteen,
       (map{/fi/?quarter:$_.teen}@b[3..8]),
       (map{twenty.$_}'',@b[0..8]),half);
    # quarter/half business
    @y=map{/^q|h/?$_:$_.' minutes'}@x;
    # whether we are to/past
    $s=1-$2/31;
    # num minutes wrapped around
    $y=abs((-29,0)[$s]+$2%31)-1;
    # num hours
    $h=$1-$s;
    #print('$s='.$s."\th=".$h."\th%12=".($h%12)."\n");
    print($_.' > ');
    #minute component
    print((+-$2
          ?@y[$y].' '.(to,past)[$s].' '
          :'')
        # hours
        .@b[$h++%12]
        ." o' clock "
        # Night/Noon
        .($h%12
          ?(AM,PM)[$h/12]
          :(night,noon)[$h/12%2]));
    print "\n"
}
('00:00:00',
 '00:01:00',
 '11:59:00',
 '12:00:00',
 '12:01:00',
 '06:00:00', 
 '18:00:00', 
 '06:15:00', 
 '18:45:00', 
 '11:30:00', 
 '13:22:00', 
 '17:43:00',
 '23:59:59')

Answer 5

C, 478 bytes

*w(i){char*p,*n[]={"","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};return i>19?asprintf(&p,"twenty%s",n[i%20]),p:n[i];}main(m,h){scanf("%d%d",&h,&m);m>30?h++:0;printf("%s%s%s%s%s %s\n",m%15?m>30?w(60-m):w(m):m^30?m?"quarter":"":"half",m%15?" minutes":"",m?m>30?" to ":" past ":"",w((h+11)%12+1),h%12||m?" o'clock":"",h%12||m?h>11?"PM":"AM":h?"noon":"night");}

Test Cases

$ echo "0 0" | ./a.out
twelve night
$ echo "12 0" | ./a.out
twelve noon
$ echo "6 0" | ./a.out
six o'clock AM
$ echo "18 0" | ./a.out
six o'clock PM
$ echo "6 15" | ./a.out
quarter past six o'clock AM
$ echo "18 45" | ./a.out
quarter to seven o'clock PM
$ echo "11 30" | ./a.out
half past eleven o'clock AM
$ echo "13 22" | ./a.out
twentytwo minutes past one o'clock PM
$ echo "17 43" | ./a.out
seventeen minutes to six o'clock PM
$ echo "0 9" | ./a.out
nine minutes past twelve o'clock AM

Try it here.

Answer 6

Batch, 779 774 752 749 bytes

@echo off
set t=%1
set/ah=%t:~0,2%,m=%t:~3,2%
set p=past
if %m% gtr 30 set p=to&set/am=60-m,h+=1
for %%a in ("one minute.1" quarter.15 half.30)do if %%~xa==.%m% set o=%%~na&goto g
set o=
if %m% gtr 20 set o=twenty-&set/am-=20
for %%a in (one.1 two.2 three.3 four.4 five.5 six.6 seven.7 eight.8 nine.9 ten.10 eleven.11 twelve.12 thirten.13 fourteen.14 sixteen.16 seventeen.17 eighteen.18 nineteen.19 twenty.20)do if %%~xa==.%m% set o=%o%%%~na minutes
:g
if not %m%==0 set o=%o% %p% 
set a= AM
if %h% gtr 12 set a= PM&set/ah%%=12
if %h%==0 (echo %o%twelve night)else if %h%==12 (echo %o%twelve noon)else for %%a in (one.1 two.2 three.3 four.4 five.5 six.6 seven.7 eight.8 nine.9 ten.10 eleven.11)do if %%~xa==.%h% echo %o%%%~na o'clock%a%

Change the second line to set t=%1%time% to default to saying the current time if no time is provided.

Edit: Saved 22 bytes by optimising my set/a statements. Saved 3 bytes thanks to @EʀɪᴋᴛʜᴇGᴏʟғᴇʀ.

When I wrote my original version I made the mistake of saying the time as I would actually say it, i.e. o'clock only on exact hours, and midnight and midday instead of twelve night and twelve noon:

@echo off
set t=%1
set/a h=%t:~0,2%
set/a m=%t:~3,2%
set p=past
if %m% gtr 30 set p=to&set/a m=60-m&set/a h=h+1
for %%a in ("one minute.1" quarter.15 half.30) do if %%~xa==.%m% set o=%%~na&goto g
set o=
if %m% gtr 20 set o=twenty-&set/a m=%m%-20
for %%a in (one.1 two.2 three.3 four.4 five.5 six.6 seven.7 eight.8 nine.9 ten.10 eleven.11 twelve.12 thirten.13 fourteen.14 sixteen.16 seventeen.17 eighteen.18 nineteen.19 twenty.20) do if %%~xa==.%m% set o=%o%%%~na minutes
:g
set o=%o% %p% 
set a= AM
if %h% gtr 12 set a= PM&set/a h=h%%12
if %m%==0 set a= o'clock%a%&set o=
if %h%==0 (echo %o%midnight)else if %h%==12 (echo %o%midday)else for %%a in (one.1 two.2 three.3 four.4 five.5 six.6 seven.7 eight.8 nine.9 ten.10 eleven.11) do if %%~xa==.%h% echo %o%%%~na%a%