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The beautiful pattern drawer
Good morning PPCG !
The other day, when I was trying to help someone on Stack Overflow, a part of his problem gave me an idea for this challenge.
First of all, check the following shape :
Where all black numbers are the index of the points in the shape and all dark-blue numbers are the index of the links between the points.
Now, given an hexadecimal number for 0x00000 to 0xFFFFF, you need to draw a shape in the console using only character space and "■" (using the character "o" is okay too).
Here are some examples where hexadecimal number is input and shape is output :
0xE0C25 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■
0xC1043 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■
■
■
■
■
■
■
■ ■ ■ ■ ■ ■ ■ ■ ■
0xE4F27 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
0xF1957 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
0xD0C67 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
0x95E30 :
■ ■ ■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■
0x95622 :
■ ■ ■ ■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
■
■
■
■ ■ ■ ■ ■
0xC5463 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
0xE5975 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
0xB5E75 :
■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■ ■ ■
0xF4C75 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■
■ ■ ■ ■ ■ ■
0xF5D75 :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■
■ ■ ■ ■ ■ ■
Here are some explanation about how it works :
0xFFFFF(16) = 1111 1111 1111 1111 1111(2)
You here have 20 bits, each bit says whether a link exists or not.
Index of the Most Significant Bit (MSB) is 0 (picture reference) or the Less Significant Bit (LSB) is 19 (picture reference again).
Here's how it works for the first shape given as example :
0xE0C25(16) = 1110 0000 1100 0010 0101(2)
Meaning you'll have the following existing links : 0,1,2,8,9,14,17,19.
If you highlight the lines on the reference picture with those numbers, it will give you this shape :
■ ■ ■ ■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■ ■
■ ■
■ ■
■ ■
■ ■ ■ ■ ■
Here is a simple and ungolfed Python implementation if you need more help :
patterns = [
0xE0C25, 0xC1043, 0xE4F27, 0xF1957,
0xD0C67, 0x95E30, 0x95622, 0xC5463,
0xE5975, 0xB5E75, 0xF4C75, 0xF5D75
]
def printIfTrue(condition, text = "■ "):
if condition:
print(text, end="")
else:
print(" "*len(text), end="")
def orOnList(cube, indexes):
return (sum([cube[i] for i in indexes]) > 0)
def printPattern(pattern):
cube = [True if n == "1" else False for n in str(bin(pattern))[2::]]
for y in range(9):
if y == 0: printIfTrue(orOnList(cube, [0, 2, 3]))
if y == 4: printIfTrue(orOnList(cube, [2, 4, 9, 11, 12]))
if y == 8: printIfTrue(orOnList(cube, [11, 13, 18]))
if y in [0, 4, 8]:
printIfTrue(cube[int((y / 4) + (y * 2))], "■ ■ ■ ")
if y == 0: printIfTrue(orOnList(cube, [0, 1, 4, 5, 6]))
if y == 4: printIfTrue(orOnList(cube, [3, 5, 7, 9, 10, 13, 14, 15]))
if y == 8: printIfTrue(orOnList(cube, [12, 14, 16, 18, 19]))
printIfTrue(cube[int((y / 4) + (y * 2)) + 1], "■ ■ ■ ")
elif y in [1, 5]:
for i in range(7):
if i in [2, 5]:
print(" ", end=" ")
printIfTrue(cube[y * 2 + (1 - (y % 5)) + i])
elif y in [2, 6]:
for i in range(5):
if i in [1, 2, 3, 4]:
print(" ", end=" ")
if i in [1, 3]:
if i == 1 and y == 2:
printIfTrue(orOnList(cube, [3, 4]))
elif i == 3 and y == 2:
printIfTrue(orOnList(cube, [6, 7]))
if i == 1 and y == 6:
printIfTrue(orOnList(cube, [12, 13]))
elif i == 3 and y == 6:
printIfTrue(orOnList(cube, [15, 16]))
else:
printIfTrue(cube[(y * 2 - (1 if y == 6 else 2)) + i + int(i / 4 * 2)])
elif y in [3, 7]:
for i in range(7):
if i in [2, 5]:
print(" ", end="")
ri, swap = (y * 2 - 2) + (1 - (y % 5)) + i, [[3, 6, 12, 15], [4, 7, 13, 16]]
if ri in swap[0]: ri = swap[1][swap[0].index(ri)]
elif ri in swap[1]: ri = swap[0][swap[1].index(ri)]
printIfTrue(cube[ri])
if y == 0: printIfTrue(orOnList(cube, [1, 7, 8]))
if y == 4: printIfTrue(orOnList(cube, [6, 8, 10, 16, 17]))
if y == 8: printIfTrue(orOnList(cube, [15, 17, 19]))
print()
for pattern in patterns:
printPattern(pattern)
Of course it's not perfect and it's pretty long for what it should do, and that's the exact reason why you're here !
Making this program ridiculously short :)
This is code-golf, so shortest answer wins !
Sygmei
Posted 2017-01-27T10:19:20.723
Reputation: 1 137
Can we print a single trailing space on lines? Your examples contain them. – orlp – 2017-01-27T11:48:31.027
Yup :) It's allowed – Sygmei – 2017-01-27T12:32:06.470
4Is graphical output allowed? – 12Me21 – 2017-01-27T16:11:13.513
Is a leading space allowed as well? – Arnauld – 2017-01-27T16:59:38.663
Does it have to be a function, or can we get input directly from the user? – 12Me21 – 2017-01-27T17:06:45.210
1Do you require hexadecimal input or is decimal ok? – Titus – 2017-01-27T19:47:30.273
1Maybe all the code golf is just getting to me, but that code is painful to read… – Lynn – 2017-01-27T23:06:25.887
@12Me21 You can get input from user ! – Sygmei – 2017-01-28T07:55:07.437
@12Me21 Graphical output is not allowed as you can use some stuff like "drawline" and not have to care abour corners overlapping :) – Sygmei – 2017-01-28T07:57:56.653
@Arnauld Leading space is allowed, doesn't change much here :) – Sygmei – 2017-01-28T07:59:26.233
@Titus Hexadecimal required ! – Sygmei – 2017-01-28T08:00:10.740