Produce the number 2014 without any numbers in your source code

584

205

Note to challenge writers as per meta consensus: This question was well-received when it was posted, but challenges like this, asking answerers to Do X without using Y are likely to be poorly received. Try using the sandbox to get feedback on if you want to post a similar challenge.


It's 2017 2018 2019 2020 already, folks, go home.

So, now that it's 2014, it's time for a code question involving the number 2014.

Your task is to make a program that prints the number 2014, without using any of the characters 0123456789 in your code, and independently of any external variables such as the date or time or a random seed.

The shortest code (counting in bytes) to do so in any language in which numbers are valid tokens wins.


Leaderboard:

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Joe Z.

Posted 11 years ago

Reputation: 30 589

11Even though numbers are ignored in brainfuck, I thought I'd post one anyway. 32 Chars: ++++++[>++++++++<-]>++.--.+.+++. – Braden Best – 10 years ago

5Brainfuck isn't a valid language for this challenge. – Joe Z. – 10 years ago

1I know. That's why I posted it as a comment – Braden Best – 10 years ago

9I wonder if this question gets a small spike in popularity around New Year's. – Joe Z. – 9 years ago

3Waiting for "Come on folks, don't you realize it's 2016?" :) – padawan – 9 years ago

@cagirici Done. – Joe Z. – 9 years ago

1@BradenBest It's possible to do it in 31 characters in at least two different ways:

+++++++[>+++++++<-]>+.--.+.+++.

and

++++++++++[>+++++<-]>.--.+.+++.
 – Zubin Mukerjee  – 9 years ago

@JoeZ. It's almost that time of the year again. – Ian Limarta – 8 years ago

1possible to do the brainfuck answer in 23 bytes -[>+<-----]>-.--.+.+++. – FinW – 8 years ago

That language is full of language! – cascading-style – 8 years ago

@JoeZ. We're discussing this question on meta.

– xnor – 8 years ago

C++: cout<<to_string(('V'-'B'))+to_string(('V'-'H'))<<"\n"; – abhinav1602 – 5 years ago

Answers

132

Mouse-2002, 4 bytes.

That's 4 bytes of pure, sweet ASCII.

In Mouse, the letters of the alphabet are initialised to the values 0-25. ! is the operator for printing integers, thus this prints 20 then 14 (no intermittent newline).

U!O!

There's no online interpreter available, but here you will find an interpreter written in C (needing some tweaks before one can coerce gcc to compile it) and the same compiled interpreter for Win32 but which works perfectly on Linux with wine.

Here you can find the fixed version of the interpreter, which compiles.

cat

Posted 11 years ago

Reputation: 4 989

7Wow, this is an amazing find so much later after the challenge. And with a language so esoteric nobody here had heard of it yet! – Joe Z. – 9 years ago

1

I just discovered this language today and I already love it. However, it's not purely esoteric, which makes it even better!

– cat – 9 years ago

3BTW: this does the same thing as CJam's KE, but is actually valid because it's a language from before 2014. – Joe Z. – 9 years ago

7The smug look on my face right now resembles that of a Fortran-77 wizard after beating some proponent of Python in a [tag:fastest-code]. – cat – 9 years ago

1Also this solution will work until 2025 at least, until you pass U!Z!. – Joe Z. – 9 years ago

2But by then, somebody will invent a language that prints out the Unicode value of any unrecognized token, and then the high score will be at 2 bytes forevermore. – Joe Z. – 9 years ago

59This a game of @cat and Mouse-2002. – Digital Trauma – 8 years ago

5@DigitalTrauma indeed :3 – cat – 8 years ago

1Running the 2007 binary using Wine on Ubuntu, the program as written produces an error message to the standard output which doesn't include the string 2014. The modified program U!O!$ works, producing 2014 and no trailing newline. – LegionMammal978 – 8 years ago

@JoeZ, that's... that's kinda what I've done. ;) – Lyxal – 5 years ago

1 312

Python, 52 bytes

print sum(ord(c) for c in 'Happy new year to you!')

Updated for 2015 thanks to @Frg:

print sum(ord(c) for c in 'A Happy New Year to You!')

Mouse over to see 2016 version:

print sum(ord(c) for c in 'Happy New Year to you!!!')

Try it online!

dansalmo

Posted 11 years ago

Reputation: 8 901

5Updated: print sum(ord(c) for c in 'A Happy New Year to You!') – Frg – 10 years ago

Uh....I get invalid syntax in 3.4? How does one run this? – jvriesem – 9 years ago

For Python 3.x, print needs ( )'s around the expression. – dansalmo – 9 years ago

12Congrats on being the first answer on this site to reach 1,000 upvotes. :) – Joe Z. – 9 years ago

You don't need the space after ord(c) – Cyoce – 9 years ago

2print sum(ord(c) for c in 'Happy New Year to You!!!!') for 2017 :D – fedorqui – 9 years ago

Why were revisions undone for print sum(map(ord,'A Happy New Year to You!'))? It does the same thing. – Sunny Patel – 8 years ago

3@SunnyPatel it's frowned upon to edit in golfs – Cyoce – 8 years ago

When can haz 2017? – Pavel – 8 years ago

2@Phoenix print sum(ord(c) for c in 'Happy New Year to You!!!!') – dansalmo – 8 years ago

1@dansalmo Perhaps you want to add that one to the answer as well? Would be cool to see the entire list in 2025. ;) (Oh, and I took the liberty to add a TIO-link.) – Kevin Cruijssen – 8 years ago

188You deserve the cleverness award – Carter Pape – 11 years ago

You forgot a print somewhere. Nice one otherwise :) – jub0bs – 11 years ago

168wow - this is so in the spirit of this question. <3 – Johannes – 11 years ago

80I was a little surprised that it was only the 4th phrase I tried after "Happy new year!", which would have been perfect for the year 1374. – dansalmo – 11 years ago

3Is this a rip-off of Mikael Mayer's answer in Scala, though? – SimonT – 11 years ago

No, I did not look at anyone else's answers first. – dansalmo – 11 years ago

10I only posted mine two hours before yours. This one is not that hard to find by oneself. – Mikaël Mayer – 11 years ago

1Ugh, ever since I started programming in Befunge, Python looks so wordy. But since this is such an amazing solution (+1), here is the equivalent Befunge: "Happy new year to you!"aa+k+.@ – Justin – 11 years ago

14You want terse? Ruby: p 'Happy new year to you!'.sum – histocrat – 11 years ago

55print sum(ord(c) for c in 'HAPPY NEW YEAR To you too.') Oh wait, I'm a year late. That's 2013. – Warren P – 11 years ago

167sum(map(ord,'Happy new year to you!')) would save 7 characters. – None – 11 years ago

4Even at my best I am a bogey golfer. – dansalmo – 11 years ago

30I created this account just to give +1! – mkoistinen – 11 years ago

37sum(b'Happy new year to you!') in Python 3 – Kabie – 11 years ago

5sum(bytearray('Happy new year to you!')) in Python 2.6+ – martineau – 11 years ago

Awesome timing for awesome answer! – tumchaaditya – 11 years ago

haha good answer, in PHP : echo array_sum(array_map('ord',str_split('Happy new year to you!'))); – Tufan Barış Yıldırım – 11 years ago

@KevinCruijssen That wasn't their solution. fedorqui posted that solution nearly a year prior, up a few comments. – Mego – 8 years ago

2You guys made my day! Thank you and have a great year wherever you are :) – amyassin – 11 years ago

2Exactly 1234 upvotes at the time of the posting of this comment. – Comrade SparklePony – 7 years ago

One byte can be saved by deleting whitespace before "for". – stackzebra – 6 years ago

@stackzebra and also by deleting whitespace after in – dansalmo – 6 years ago

I offer: print(ord('&')*ord('j')/len('NY')) – Max – 6 years ago

This does not make a serious attempt at solving the question (this is code-golf) – MilkyWay90 – 6 years ago

print(ord('ߞ')) for -36 bytes. – None – 5 years ago

Printable ASCII at 32-127 means about max 62 chars, min 15. You clocked 22. I'd like to see your list of things you considered before picking this one, added to the answer. If it's code golf, how much smaller while being literate could it get...margin is 7 chars. :-) – HostileFork says dont trust SE – 11 years ago

1It's hard to remember exactly, but the first thing I tried was "Happy new year!", then "Happy new year!!!!!", then "Happy new year everyone!", and finally 'Happy new year to you!' – dansalmo – 11 years ago

print(sum(ord(c) for c in 'have a happy new year!!')) – MirroredFate – 5 years ago

Mind blown! That is very clever of you sir! – rageit – 11 years ago

244

Befunge 98 - 17 11 9 8 bytes

'-:*b-.@

Similar to the old version, but I remembered about '

'-:* pushes 45, duplicates it, then squares it, producing 2025
b-   subtracts 11 from it, resulting in 2014
.@   prints the result, then ends the program

Interestingly, 452-11 is the only pairing of numbers a,b where (a,b)[32,126]×[10,15]a2b=2014 The significance of those sets is that [32,126] is the set of printable ascii characters and [10,15] is the set of easily accessible Befunge numbers. I found that pair with this python program:

for a in range(32,127):
    for c in range(10,16):
        if (a**2-c)==2014:
            print("%s,%s"%(a,c))

Or, if your interpreter supports unicode, then this works:

Befunge 98 - 5 bytes (4 chars)

'ߞ.@

It at least works on http://www.quirkster.com/iano/js/befunge.html with the following code (Befunge 93 - 6 bytes / 5 chars):

"ߞ".@

Old version

cdd**e-.@

computes the number, then prints it:

cdd pushes numbers to the stack so that it is this: 12,13,13
**  multiplies top three values of stack, which is now: 2028
e   pushes 14
-   subtracts the top two values of the stack, resulting in: 2014
.   prints the numerical value
@   end of program

Older version:

"*'&("#;:a`j@a+,;

Pushes the ascii values for 2014, -10. Then prints each after adding 10 to it.

Justin

Posted 11 years ago

Reputation: 19 757

Can I edit the question to include my answer? – cat – 9 years ago

78http://en.wikipedia.org/wiki/Befunge ...what is this i don't even... – Plato – 11 years ago

37"The language was originally created by Chris Pressey in 1993 as an attempt to devise a language which is as hard to compile as possible"... – will – 11 years ago

1Wouldn't a:+.e.@ achieve the same? Saves a character by printing 20 and then 14. – MSalters – 11 years ago

@MSalters That would actually print 20 14 – Justin – 11 years ago

@Quincunx Where does it say that isn't allowed? – 11684 – 11 years ago

7@11684 The output is rather well defined in the question. If a program printed: randomstuff2randomstuff0randomstuff1randomstuff4 I wouldn't consider it a valid solution. – Cruncher – 11 years ago

1I agree. But at least in my native language (Dutch) spaces can be used in numbers to make numbers more readable. So I wouldn't categorise a space as 'random stuff'. – 11684 – 11 years ago

7

@Plato Rather than read the wikipedia article (which only includes Befunge 93), if you want to learn about Befunge 98, read the official specs

– Justin – 11 years ago

1By the same idea, '&:f+*.@ should work as well. – MvG – 11 years ago

@MvG yeah, I was just manually searching for short solutions, then wrote a program, then tried different methods with that program. Of course there are other short methods. – Justin – 11 years ago

3Wiki: 'The language was originally created by Chris Pressey in 1993 as an attempt to devise a language which is as hard to compile as possible' ...but why? – CousinCocaine – 11 years ago

241

Ruby, 15

p Time.new.year

Temporary ;)


Note that the section of the question

independently of any external variables such as the date or time or a random seed

was not edited in until long after I posted my answer...


Jan Dvorak offers a great alternative in the comments:

Happy = Time
Happy.new.year

But it's so unenthusiastic. I prefer:

Happy = Time
class Time; alias year! year; end

Happy.new.year!

Or even:

class Have; def self.a; A.new; end; end
class A; def happy; Time; end; end
class Time; alias year! year; end

Have.a.happy.new.year!

And here's correct English punctuation:

def noop x = nil; end
alias a noop
alias happy noop
alias new noop
alias year! noop
def Have x
    p Time.new.year
end

Have a happy new year!

Okay okay, I couldn't help it:

def noop x = nil; end
eval %w[we wish you a merry christmas! christmas and a happy new].map{|x|"alias #{x} noop"}*"\n"
def year!; p Time.new.year; end

we wish you a merry christmas! we wish you a merry christmas!
we wish you a merry christmas and a happy new year!

Doorknob

Posted 11 years ago

Reputation: 68 138

170Happy = Time; Happy.new.year – John Dvorak – 11 years ago

232

Go, 2 bytes (UTF-16)

One unicode character (2 bytes in UTF-16, 3 bytes in UTF-8 format), output 2014 as part of an error

http://ideone.com/dRgKfk

can't load package: package : 
prog.go:1:1: illegal character U+2014 '—'

YOU

Posted 11 years ago

Reputation: 4 321

7That's very clever, but the question requests a program that prints the number. – HelloGoodbye – 11 years ago

42If printed error codes count, this submission should win. – ToastyMallows – 11 years ago

39+1. The question doesn't say, "prints only the number and nothing else". – Kaz – 11 years ago

1I don't care if its valid or not, it's pretty awesome. – Redwolf Programs – 6 years ago

2

This is a standard loophole

– MilkyWay90 – 6 years ago

I joined this community just to like this post. – Gaurav – 5 years ago

177

Python, 26

print int('bbc',ord("\r"))

Darren Stone

Posted 11 years ago

Reputation: 5 072

2Woah I almost upvoted your bbc is 2014 in base 13 but then I realized it has 42 upvotes. Perfection – User – 9 years ago

Here is a permalink to Base 13 as of Jan 4 '14 for anyone interested. Be wary that it contains a mild spoiler to "The Restaurant at the End of the Universe".

– arekolek – 9 years ago

53bbc is 2014 in base 13 – Darren Stone – 11 years ago

Would've been my approach. Until I saw the accepted answer... – Kiruse – 11 years ago

71I assume the use of the characters 'bbc' and the use of base 13 is a Douglas Adams tribute. "I may be a sorry case, but I don't write jokes in base 13." – Brian Minton – 11 years ago

1013 years ago. RIP. – Darren Stone – 11 years ago

4IMO, this answer is in "True Pythonese" – kmonsoor – 11 years ago

Wikipedia reference for the Douglas Adams and base-13, http://en.wikipedia.org/wiki/Base_13

– Juha Palomäki – 11 years ago

8@BrianMinton: The use of Base 13 is probably because it's the only base between 2 and 36 that allows the number 2014 to be represented without any of the characters 0-9. – dan04 – 11 years ago

1Coincidence? I think not! :-) – Darren Stone – 11 years ago

146

MATLAB, Scala (4 characters, 5 bytes)

You can take advantage of MATLAB's (and Scala's) relatively weak type system, here. The trick is to apply the unary + operation on a string composed only of the character ߞ (of UTF-8 code point U+07DE, or 2014 in decimal). This operation implicitly converts the string to a double (in MATLAB) and to an Int (in Scala):

+'ߞ'

Byte-count details:

  • + is ASCII and counts for 1 byte
  • ' is ASCII and counts for 1 byte (but appears twice in the expression)
  • ߞ is a 2-byte UTF-8 character

Total: 5 bytes

TeX (32 26 characters, as many bytes)

\def~{\the\catcode`}~}~\\~\%\bye

An even shorter alternative (proposed by Joseph Wright) is

\number`^^T\number`^^N\bye

XeTeX/LuaTeX (13 characters, 14 bytes)

If XeTeX or LuaTeX are allowed, UTF-8 input can be used directly (as proposed by Joseph Wright):

\number`ߞ\bye

jub0bs

Posted 11 years ago

Reputation: 1 422

\let~\number~`^^T~`^^N\bye 25 chars/bytes. You IMHO count wrong, it's 25 for your solution as well. – yo' – 11 years ago

1@tohecz I think both our solutions are actually 26-byte long. – jub0bs – 11 years ago

1If the current year is wanted, then 13 bytes: \the\year\bye – yo' – 11 years ago

2+'ߞ' also works in Scala (and a few other languages I imagine) – theon – 11 years ago

118

dc, 6 chars

DiBBCp
  • D pushes 13 on the stack, even tho the input radix is 10 initially
  • i changes input radix (to 13 from 10)
  • BBC is 2014 base 13.
  • p prints.

Console output:

$ dc <<< "DiBBCp"
2014

daniero

Posted 11 years ago

Reputation: 17 193

dc<<<DiBBCp - a bit shorter – mpapis – 11 years ago

10True, but the actual dc program is still DiBBCp (6 chars), the rest is just a way to run it. – daniero – 11 years ago

11

I was going to upvote this but it has 42 points! uses base 13 and the word BBC. How cool is that! Seems that this year we will find the question for life, universe and everithing ;-) http://en.wikipedia.org/wiki/Base_13. I am upvoting @daniero's comment instead and leave the answer with this magnificent 42 reputation ;-)

– Pablo Marin-Garcia – 11 years ago

4@PabloMarin-Garcia, unfortunatelly some unaware person broke it... Has 43 votes now. Please go back and downvote! :) – Tomas – 11 years ago

3@Tomas Vogons always the Vogons. Resistance is futile against the intergalactic burocracy. – Pablo Marin-Garcia – 11 years ago

2I cannot even find the D command in the man page. What does it do? Never mind... D is hex for 13. – kzh – 11 years ago

I would upvote but you have 64 votes – None – 10 years ago

@mpapis Or dc -eDiBBCp. Same length, I think. – nyuszika7h – 10 years ago

92

Morse Code, 23

;)

..--- ----- .---- ....-

DavidC

Posted 11 years ago

Reputation: 24 524

9I claim this language isn't Turing-complete. – Joe Z. – 10 years ago

1@JoeZ. I claim this language is not even a programming language. – SuperJedi224 – 9 years ago

21"in any language in which numbers are valid tokens" – Doorknob – 11 years ago

14"..---" is a valid token, in 5 strokes, for the number two, right? Just as "4" is a valid token, in three strokes, for the number "four". – DavidC – 11 years ago

3No, the question said that numbers have to be valid in the language you're using. . and - aren't numbers. – Doorknob – 11 years ago

1@Doorknob — David is right. – Nicolas Barbulesco – 11 years ago

8Braille could be shorter :) – Dr. belisarius – 11 years ago

31Good point. Btw, I was relieved that no one asked how I get Morse Code to run on my computer. – DavidC – 11 years ago

14

@DavidCarraher What do you mean? I naturally assumed you used this repo to decode it. https://github.com/Nyubis/mspa-morse-decoder Everyone's doing it...

– Michael J. Calkins – 11 years ago

6@MichaelCalkins Of course. How silly of me. – DavidC – 11 years ago

5This isn't compiling for me... – Embattled Swag – 11 years ago

@SuperJedi224 I claim that non-languages are now allowed on CGCC. – None – 5 years ago

88

72 45 characters in the code; Zero character codes

This is far from the shortest answer posted, but no one has yet posted an answer that

  • doesn't use character codes as a substitute for numbers, and
  • doesn't call the system date.

Using pure math (okay, and an automatic boolean conversion) in R, from the R console:

x<-(T+T);x+floor(exp(pi)^x)*x*x-(x*x)^(x*x)/x

Prints out the number 2014. T is a pre-defined synonym for true in R. The floor and exp functions are directly available in the base package, as is the pi constant. R doesn't have an increment operator, but repeating the (x*x) turned out to be fewer characters that doing increment and decrement twice each.


Original version in Javascript (72 characters)

For the simple reason that I could test out in the console, and it doesn't mind a complete lack of whitespace:

m=Math;p=m.pow;t=true;++t+m.floor(p(m.exp(m.PI),t))*t*t++-p(++t,t--)/--t

run in your console and it will print back the number 2014.


Props to xkcd (and also) for getting me to think about exp(pi): e to the pi Minus pi

P.S. If you can make the same algorithm shorter in a different language, post a comment with it.

AmeliaBR

Posted 11 years ago

Reputation: 1 031

1o=!"";(o+o)+""+(o-o)+(o+o-o)+(o+o+o+o) – Kernel James – 11 years ago

425 bytes: alert('ߞ'.charCodeAt()) – oberhamsi – 11 years ago

1

+1. However, you claim your answer was the first answer that "doesn't use character codes as a substitute for numbers, and doesn't call the system date". That is actually false. My answer has this solution cdd**e-.@ (posted before yours) which does not make use of character codes or system date. It computes the number 2014. c,d, and e are hexadecimal number digits. a,b,...,f push (respectively) 10,11,...15 so 12 * 13 * 13 - 14 is the computation.

– Justin – 11 years ago

This wasn't the first answer to not use character codes; I have several earlier ones. – Timtech – 11 years ago

1@Quincunx: you're right; skimming through I didn't catch that your version was using hex digits, not character codes. – AmeliaBR – 11 years ago

o=+!'';t=o+o;''+t+(+!o)+o+(t+t), a bit smaller than @kernel-james one – Ricardo Panaggio – 11 years ago

R code with 38 characters x=T+T;y=x*x;x+floor(exp(pi)^x)*y-y^y/x – djhurio – 11 years ago

Nice catch, @djhurio. – AmeliaBR – 11 years ago

I also like @KernelJames version (and Ricardo's improvement) though they really qualify as a completely different method rather than an improvement on mine -- I assume the "protected" status wasn't letting you post? – AmeliaBR – 11 years ago

two k implementations of this algo, both 39 chars: 1: -_-(x*p*p:exp acos@-#`)-f*x*x*x:f*f:#``; 2: f+(x*_p*p:exp acos@-#`)-f*x*x*x:f*f:#``. I can't seem to squeeze it any further at the moment.... – Aaron Davies – 11 years ago

and here it is in APL in 31 chars (which i'm quite new to, so i'm sure it can be improved--particularly the hacky generation of the 2 constant): ⌈(x×p×p)-f×x×x×x←f×f←⍴⍕⌊p←*○~⊃⍬ – Aaron Davies – 11 years ago

86

Scala REPL

34 29 characters.

+"Happy new year to you!".sum

Well ok if you really want it golfed with any chars, you can use:

'@'*' '-'"'

or

"{yz}"map(_-'I'toChar)

which have 11 and 22 chars respectively.

Mikaël Mayer

Posted 11 years ago

Reputation: 1 765

4Interesting idea, even if it's not particularly golfed. But the string itself makes it more interesting, than something using high bytes, or something like that. – Konrad Borowski – 11 years ago

I added a golfed version. – Mikaël Mayer – 11 years ago

You could save a couple characters from the toInt like this: +"Happy new year to you!".sum Test

– theon – 11 years ago

Updated. I did not know that + could also be a prefix. – Mikaël Mayer – 11 years ago

68

PHP, 9 bytes

This requires PHP 7.1 or lower. It will work in PHP 7.2, but it will result in a warning. No guarantees for any future version.

xxd needed because of binary data (so copying and pasting it would be easier). May return E_NOTICE, but it doesn't really matter, does it?

~ $ xxd -r > 2014.php
0000000: 3c3f 3d7e cdcf cecb 3b                   <?=~....;
~ $ php 2014.php
2014

Alternatively, save this using ISO-8859-1 encoding.

<?=~ÍÏÎË;

Konrad Borowski

Posted 11 years ago

Reputation: 11 185

Why not <?=~ÍÏÎË instead? – Ismael Miguel – 10 years ago

@IsmaelMiguel: I guess (if you save it using ISO-8859-1). – Konrad Borowski – 10 years ago

@Quincunx: Uploading this was relatively tricky, but here is Ideone - http://ideone.com/APHKhn.

– Konrad Borowski – 11 years ago

1This looks interesting; what does it do? – Justin – 11 years ago

7@Quincunx: It does bitwise not (0x00 changes into 0xFF, and 0x7F changes into 0x80) on every character of the string. As the string is valid identifier (anything with high bit set is an identifier character for PHP, probably to support other encodings), PHP thinks it's a constant, but because it's not defined, it treats it as a string. – Konrad Borowski – 11 years ago

2Since the question was "Now that it is 2014...", how about echo date('Y');? – John – 11 years ago

6@John: Nope. If you would read the comments for the question, you would notice that OP doesn't want the to get current year as an answer. Besides, <?=date(Y); would be 11 characters, and I have solution in 9 characters. – Konrad Borowski – 11 years ago

67

C, 33 bytes

main(){printf("%d",'A'*' '-'B');}

Sudharsan Mohan

Posted 11 years ago

Reputation: 851

@JonathonReinhart multi-character literals are entirely implementation-defind. – FUZxxl – 10 years ago

19How annoying that the prime factorization of 2014 requires ASCII 5! – Ben Jackson – 11 years ago

I got for(int a;YES;a++){NSLog(@"%i",a);} for Cocoa Touch objective C but I can't add yet (not rated enough). It does show a 2014 eventually and it has a compiler error and is possible it may not work at all and compiled is probably about 4.2 meg - but hey. – Recycled Steel – 11 years ago

main(){printf("%d",'\a\xde');} – mjy – 11 years ago

1@mjy Byte order of multi-character literals is not guaranteed. – Jonathon Reinhart – 11 years ago

On specified env. using multichar is good – l4m2 – 7 years ago

54

Mathematica, 14 characters (or 15 if you count the bitmap as a character)

TextRecognize@enter image description here

Michael Stern

Posted 11 years ago

Reputation: 3 029

50Actually, you should count bytes so it's 14 + the size of the bitmap image. – Sylwester – 11 years ago

22The bitmap would probably be 7,357 characters, really. – Joe Z. – 11 years ago

5Also, I believe some of the bytes in the image fall into the \d range. Namely, if it's the GIF, then the header itself is guaranteed to contain some. – John Dvorak – 11 years ago

13You are all killjoys. Fine, use First@ToCharacterCode@"ߞ" for 25 characters, 26 bytes. – Michael Stern – 11 years ago

@MichaelStern Yup, that's been done allready. – Ajasja – 11 years ago

@Ajasja only after I fixed it. The old solution as given produced a list of answers rather than '2014' as specified by the problem. – Michael Stern – 11 years ago

9

As a bonus, here's a Mathematica solution in 30 characters --URLFetch@"http://goo.gl/miVwHe"

– Michael Stern – 11 years ago

1

I liked this answer so much I made it into its own question: http://codegolf.stackexchange.com/q/17588/2605

– Charles – 11 years ago

54

Python3.4.0b2 (0 bytes)

% python3.4  
Python 3.4.0b2 (v3.4.0b2:ba32913eb13e, Jan  5 2014, 11:02:52) 
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> 

YOU

Posted 11 years ago

Reputation: 4 321

2Also works in Python 3.4.2. – Erik the Outgolfer – 8 years ago

This won't work once people update their version of Python 3 a year from now. – Joe Z. – 11 years ago

21That's why I mentioned python3.4.0b2, It wont happen twice. Its release date, not system date. – YOU – 11 years ago

You are not allowed to add extraneous output. – MilkyWay90 – 6 years ago

6This made me smile! – Matt Fletcher – 11 years ago

48

Javascript, 23 bytes

Uses Base 64 Conversion

alert(atob("MjAxNA=="))

23 chars (16 with atob by itself)

Or

alert("MMXIV") // ;)

logic8

Posted 11 years ago

Reputation: 601

alert("ߞ".charCodeAt()) – programmer5000 – 8 years ago

27MMXIV has no characters in common with 2014, last I checked... // ;) – Joe Z. – 11 years ago

23The ancient Romans might disagree. The first one produces 2014 though, in modern English. – logic8 – 11 years ago

1Your first one doesn't output though... – Doorknob – 11 years ago

1if you open the console in chrome, paste it and hit enter it returns the value - I'll add an alert to it as its longer than others anyway. – logic8 – 11 years ago

5@logic8: Nice one +1. Another JavaScript version which also works: (4 bytes) [!+[]+!+[]]+[+[]]+[+!+[]]+[!+[]+!+[]+!+[]+!+[]] - alert([!+[]+!+[]]+[+[]]+[+!+[]]+[!+[]+!+[]+!+[]+!+[]]); Though I'm not sure it meets Joe Z's requirements. – Nope – 11 years ago

@FrançoisWahl, Now that's cool! Nice one. – logic8 – 11 years ago

Or go the other way btoa("ÛMx") for 11 characters – Phil McCullick – 11 years ago

Just so you know, atob("MjAxNA==") returns "2014" (a string). +atob("MjAxNA==") returns a number. Doesn't matter for alert, though. – Pascal – 11 years ago

@logic8 The ancient Romans would probably find it quirky as they didn't use generally use subtractive notation (e.g. IV for 4). – Peter Cooper – 11 years ago

1Here's another javascript base one: alert(parseInt('bbc',+[]+'xd')) – Adam Iley – 11 years ago

@PeterCooper: That's interesting. Would the standard have been "IIII" then? – logic8 – 11 years ago

1@logic8 You can omit the equals signs to get 21 chars – gengkev – 11 years ago

41

Perl - 10 characters

This solution is courtesy of BrowserUK on PerlMonks, though I've shaved off some unnecessary punctuation and whitespace from the solution he posted. It's a bitwise "not" on a four character binary string.

say~"ÍÏÎË"

The characters displayed above represent the binary octets cd:cf:ce:cb, and are how they appear in ISO-8859-1 and ISO-8859-15.

Here's the entire script in hex, plus an example running it:

$ hexcat ~/tmp/ten-stroke.pl
73:61:79:7e:22:cd:cf:ce:cb:22
$ perl -M5.010 ~/tmp/ten-stroke.pl
2014

Perl (without high bits) - 14 characters

say'````'^RPQT

This uses a bitwise "or" on the two four-character strings "RPQT" and "````" (that is, four backticks).

$ ~/tmp/fourteen-stroke.pl
73:61:79:27:60:60:60:60:27:5e:52:50:51:54
$ perl -M5.010 ~/tmp/fourteen-stroke.pl
2014

(I initially had the two strings the other way around, which required whitespace between print and RPQT to separate the tokens. @DomHastings pointed out that by switching them around I could save a character.)

Perl (cheating) - 8 characters

This is probably not within the spirit of the competition, but hdb on PerlMonks has pointed out that Perl provides a variable called $0 that contains the name of the current program being executed. If we're allowed to name the file containing the script "2014", then $0 will be equal to 2014. $0 contains a digit, so we can't use it directly, but ${...} containing an expression that evaluates to 0 will be OK; for example:

say${$|}

For consistency, let's do the hexcat-then-perl thing with that:

$ hexcat 2014
73:61:79:24:7b:24:7c:7d
$ perl -M5.010 2014
2014

I think this is cheating, but it's an interesting solution nonetheless, so worth mentioning.

tobyink

Posted 11 years ago

Reputation: 1 233

2Hey there, if you reverse the string and barewords, you can save a char: print"````"^RPQT. It might be possible to use say too on 5.10+ using -E instead of -e, but I don't know if that incurs a +2 penalty for different command-line args? – Dom Hastings – 11 years ago

2It's considered acceptable to specify that you're using Perl 5 and use say for no penalty. – Peter Taylor – 11 years ago

@DomHastings, personally I think if you're going to do it with "-e" or "-E", I'd say that you should then have to include the entire command, including "perl -E" in your character count. – tobyink – 11 years ago

@PeterTaylor, say is a syntax error in Perl 5 unless you explicitly write a pragma to enable it such as use v5.10 or use feature 'say'. In Perl 6 it's enabled automatically. – tobyink – 11 years ago

1Relevant meta answer – Peter Taylor – 11 years ago

4You may also save another byte by using string literals that don't require quotes, such as say ABCD^srrp. – primo – 11 years ago

40

Ruby, 20

p 'bbc'.to_i ?\r.ord

Explanation: bbc is 2014 in base 13. Shorter than Python. Not as short as Forth.

Darren Stone

Posted 11 years ago

Reputation: 5 072

(late comment) Can you do i? instead of i ?? – Erik the Outgolfer – 9 years ago

23"Nobody writes jokes in base 13!" – Jean-Michaël Celerier – 11 years ago

1w=?;"^XA[_AXeMFGIAHJLjKNAEFEJJNHQHNKLAEMINJOJOHLAGKHOJOJ[AG[HQHRFJAH}IHAIGGwIIAHHGwKHAHGHrEUAGQFiGVAGQGfIPAFHKHHbJHAQII]MGASHNSOHATIdIAUJJRLIAWLIQGKAZOFUA]ZAeSAiPAjOAkLA".codepoints{|r|r-=68;><<(r<0??\n:(w=w==??:?)*r)} – Darren Stone – 11 years ago

1p 'ߞ'.ord for a fully functional program, 'ߞ'.ord inside irb. Works on 1.9+ – Ricardo Panaggio – 11 years ago

1Without "strange" unicode characters: ?-*?--?\v (45 * 45 - 11) (Ruby 1.8) – Ricardo Panaggio – 11 years ago

One character smaller: ?.*?.-?f (46 * 46 - 102) (Ruby 1.8 only again) – Ricardo Panaggio – 11 years ago

How is the base 13 indicated in the print? – Recycled Steel – 11 years ago

@RecycledSteel, to_i takes a base parameter. I'm passing it 13 since that's the ordinal value of a carriage return (\r). – Darren Stone – 11 years ago

z=''.to_i;o=Math.cos(z).to_i;t=o+o;"#{t}#{z}#{o}#{t+t}" without relying on charcodes – Ricardo Panaggio – 11 years ago

@RicardoPanaggio, those are some sweet answers. You should submit. I'm going to leave mine as-is, simply for the BBC - Base-13 - Douglas Adams connections. :-) – Darren Stone – 11 years ago

29

Powershell, 9

+"ߞ"[""]

ߞ (U+07DE NKO LETTER KA) is counted as two bytes according to the code-golf tag info.

[""] returns the first character from the string ("" is converted to 0). The unary plus opeartor (+) converts the character to an integer.

Danko Durbić

Posted 11 years ago

Reputation: 10 241

1

According to http://codegolf.stackexchange.com/tags/code-golf/info, it should count as 9 characters.

– Konrad Borowski – 11 years ago

@GlitchMr, thanks, I've corrected my answer. – Danko Durbić – 11 years ago

3The [''] is a nice trick. I usually used [char] but that's indeed shorter :) – Joey – 11 years ago

27

Javascript, 18 characters

alert(btoa('ÛMx'))

Update: in ES6, using a template literal can save two characters:

alert(btoa`ÛMx`)

The code above is fairly easy to understand by keeping in mind that btoa converts a string into another string according to a set of well-defined rules (RFC 4648). To see how the conversion works, we're going to write the input string "ÛMx" as a sequence of binary digits, where each character is rendered as its 8-bit character code.

Input character          |        Û |        M |        x
Character code (decimal) |      219 |       77 |      120
Character code (binary)  | 11011011 | 01001101 | 01111000

After reorganizing the binary digits in the last row in groups of 6, we get the binary representation of 4 new numbers, corresponding to the Base64 indices of the 4 characters in the string "2014".

Base64 index (binary)  | 110110 | 110100 | 110101 | 111000
Base64 index (decimal) |     54 |     52 |     53 |     56
Output character       |      2 |      0 |      1 |      4

As per HTML specification, the output characters can be retrieved from their Base64 indices according to this table: http://dev.w3.org/html5/spec-LC/webappapis.html#base64-table.

If you don't care about the details, you could let the browser do the calculations for you and find out that "ÛMx" is the result of evaluating atob('2014') in Javascript.

GOTO 0

Posted 11 years ago

Reputation: 752

Or in a function expression (allowed by default) x=>btoa\ÛMx`` – programmer5000 – 8 years ago

@programmer5000 Times have changed but the consensus in 2014 was to use alert. You can find the discussion in the link in xfix's comment. – GOTO 0 – 8 years ago

the question mentions printing the number. I know that evaluation in a console will lead to the result being returned, but on [CodeGolf.SE] it's generally expected that JS answers will include some form of IO (alert is most common). – zzzzBov – 11 years ago

@zzzzBov Yes, my original answer included an alert call.

– GOTO 0 – 11 years ago

It lists Community as having removed the alert. I wonder if the standards have changed for JS codegolf or whether it's just a change that was adopted by Community.

– zzzzBov – 11 years ago

@zzzzBov: It was a change by anonymous user accepted by SHiNKiROU and luser droog. Anyway, this edit triggered a discussion on Meta (http://meta.codegolf.stackexchange.com/questions/803/javascript-standards-for-io).

– Konrad Borowski – 11 years ago

@xfix, It's not this edit alone that caused me to ask that question on meta, I've seen enough code golfs where people get into disagreements over whether the dev console counts as printing, that I figured it was worth asking for a standard. – zzzzBov – 11 years ago

I'd love to have an explanation of how this works. – DA. – 11 years ago

@DA. I added a short explanation. – GOTO 0 – 11 years ago

if functions are allowed instead of full program: _=>btoa'ÛMx' which is 13 bytes (the ' symbols should be `, but i can't because of the limitations in comments) – Brian H. – 7 years ago

27

Scala REPL - 6 chars

"?="##

(## is Scala's symbol meaning hashCode, and the Java string "?=" hashes to 2014.)

Scala REPL - 4 chars, 5 bytes

+'ߞ'

Math on our favorite unicode character produces an Int.

Rex Kerr

Posted 11 years ago

Reputation: 903

24

Yet another GolfScript entry, 9 printable characters

I believe this is shorter than any of the printable GolfScript entries so far:

"!="{*}*)

(Peter Taylor's 7-char entry beats it, but includes non-printable control characters.)

I call this the "that's so last year!" entry, because what it actually does is generate the number 2013 in 8 chars, as 33 × 61, and then increments it by one. ;-)

Ilmari Karonen

Posted 11 years ago

Reputation: 19 513

You win (for ascii golfscript) – aditsu quit because SE is EVIL – 11 years ago

21

C (31)

main(){printf("%o",' b'/'\b');}

C (32)

main(){printf("%x%o",' ','\f');}

C (30)

main(){printf("%x",' j'^'~');}

C (30)

main(){printf("%d",'\a\xde');}

fredoverflow

Posted 11 years ago

Reputation: 2 671

The most recent edit included a variation of code which breaks the rule of including numbers in the code. It uses the number "5". – Albert Renshaw – 8 years ago

How about just "%x" and 'b'*'S' ? That's 8212 dec or 2014 hex. Saves one char one literal and two on format string. – MSalters – 11 years ago

@MSalters No, 'b'*'S' is 8134. The prime factorization of 8212 is 222053, so I don't see an easy way to produce it. – fredoverflow – 11 years ago

Bah, checked with integer division that 8212/'b' == 'S' :( – MSalters – 11 years ago

and octal doesn't work either (02014=1036=37*28, 28 is unprintable) – MSalters – 11 years ago

@MSalters The octal was a nice hint though, see my new 31 solution ;) – fredoverflow – 11 years ago

1@FredOverflow what about my 28 char solution?

main(){puts(DATE+'\a');} – Arunprasad Rajkumar – 11 years ago

@ArunprasadRajkumar Will it work in the next year too? (eg. display "2014") – Spook – 11 years ago

28 characters: main(){printf("%o\b",' a');} A space is 32 in decimal. 'a' is 97. Appending them in a character literal, 32*256+97=8289. 8289 decimal is 20141 in octal. Following that printout with a backspace produces just the required 2014. – durette – 5 years ago

Your last solutions employs implementation defined behavior and is likely invalid. – FUZxxl – 10 years ago

20

GolfScript, 14

'-+,/'{)))))}%

How it works: ASCII goes like this:

...
+
,
-
.
/
0
1
2
3
4
...

So, this takes the ASCII codes of each character, subtracts five, and sticks it in a string.

{...}% yields an array of the characters of a string mapped, when given a string as an argument. So, it increments each character by 5 () means increment).

Doorknob

Posted 11 years ago

Reputation: 68 138

The CJam version of this: "-+,/"_,)f+. :) (Then again, CJam has KD.) – Martin Ender – 10 years ago

The + at the end is unnecessary. Also, rather than increment 5 times, just add five. Total savings: 4 chars. '-+,/'{5+}% – Justin – 11 years ago

16@Quincunx, 5 is a number. – Peter Taylor – 11 years ago

5@PeterTaylor I keep forgetting. – Justin – 11 years ago

Clever solution – Sumurai8 – 11 years ago

20

Forth, 14

'> '" * '^ - .      

Darren Stone

Posted 11 years ago

Reputation: 5 072

1Can you explain how this works? – ProgramFOX – 11 years ago

1I'm expressing integer constants as character literals using their ordinal (ASCII) values. So this is: 62 34 * 94 - . If you don't speak Forth, this means print (62 * 34 - 94). – Darren Stone – 11 years ago

Forth (Gforth 0.7.0), 5 bytes, 4 chars: 'ߞ . It prints the character. – 18446744073709551615 – 11 years ago

19

Python, 32 chars

print ord(',')*ord('-')+ord('"')

Probably possible to reduce it using the 2014 th Unicode char ߞ, but I didn't try.

Quincunx notes that

a=ord('.');print a*a-ord('f')

is shorter by three chars.

Bruno Le Floch

Posted 11 years ago

Reputation: 1 181

The unicode version works, at least in Python 3 with IDLE: print(ord("ߞ")). It does not appear to work in Python 2; Python 2 probably does not support unicode. – Justin – 11 years ago

3

Also, with your version, a=ord('.');print(a*a-ord('f')) is 2 chars shorter.

– Justin – 11 years ago

@Quincunx It does support, however you need to have a specific encoding set to your file and append u at the end of the string (would be "ߞ"u) – Kroltan – 11 years ago

2@Kroltan Actually, I'm pretty sure the second part is not true. In Python 2, you had to prepend strings with u to say that they were unicode, but in Python 3, all strings are automatically unicode – murgatroid99 – 11 years ago

@murgatroid99 Ah, sorry. It's been a while since I used python, and my brain remembered about C-style float literals (1453f) – Kroltan – 11 years ago

1Similar as commented above, without unicode print ord('.')**2-ord('f') is slightly shorter. – MLS – 11 years ago

18

APL (6 bytes, 4 chars)

⊃⎕TS

Only works this year though.

Why it works:

      ⎕TS
2014 1 1 11 58 5 811
      ⊃⎕TS
2014

Without relying on the system date, it's 10 bytes (7 characters):

⎕UCS'ߞ'

marinus

Posted 11 years ago

Reputation: 30 224

6Unfortunately, answers that only work for this year are invalid. – Joe Z. – 11 years ago

I don't know APL: is that square box an APL char, or am I missing a font representation (Chrome) ? – Carl Witthoft – 11 years ago

@JoeZ.: The question doesn't say that but I've added one that doesn't rely on it being 2014. – marinus – 11 years ago

4@CarlWitthoft: It's called a quad (), it's supposed to look like that. – marinus – 11 years ago

18

Python 32 10 bytes, 91 85 (66 with math imported by default) bytes pure math

Had some fun writing this:

my_lst = []
for i in range(33, 126):
    for j in range(i, 126):
        if 2014 - 126 < i * j < 2014 - 33:
            if j not in range(48, 58):
                my_lst.append("ord('" + unichr(i) +
                              "')*ord('" + unichr(j) +
                              "')+ord('" + unichr(2014 - i * j) + "')")

for val in my_lst:
    print val, '->', eval(val)

Prints all the possible ways I can write 2014 using Bruno Le Floch's method (32 chars):

ord('!')*ord(':')+ord('d') -> 2014
ord('!')*ord(';')+ord('C') -> 2014
ord('!')*ord('<')+ord('"') -> 2014
ord('"')*ord(':')+ord('*') -> 2014
ord(')')*ord('/')+ord('W') -> 2014
ord('*')*ord('-')+ord('|') -> 2014
ord('*')*ord('.')+ord('R') -> 2014
ord('*')*ord('/')+ord('(') -> 2014
ord('+')*ord(',')+ord('z') -> 2014
ord('+')*ord('-')+ord('O') -> 2014
ord('+')*ord('.')+ord('$') -> 2014
ord(',')*ord(',')+ord('N') -> 2014
ord(',')*ord('-')+ord('"') -> 2014

But this is obviously redundant, so if your interpreter is set to utf-8 by default, then all it takes is:

>>> ord(u'ߞ')
2014

Also, thanks to AmeliaBR (for the idea), I tried my best to implement a pure math version:

from math import*
a,b,c=int(e),round(e),ceil(pi);print int(a**(b*c-(c-b))-a*a**c-a)

Deneb

Posted 11 years ago

Reputation: 86

@JoachimIsaksson A digit is no number ;) – Mega Man – 8 years ago

Here is an optimized math version (42 characters) a=True;a+=a;print(a<<a*a*a)*a*a-(a<<a*a|a) – Phylliida – 8 years ago

ord(',')**2+ord('N') – MLS – 11 years ago

6@MLS Well, that has a digit in it :) – Joachim Isaksson – 11 years ago

2I optimized your math version a bit: a,b=int(e),int(pi);c=a+a;print a**(b*c-c+b)-a*a**c-a, and you can eliminate the math import altogether by making use of the fact that True in Python 2.x is identical to the integer 1 in operation, bringing it down to 50 characters: o=True;a=o+o;b=a+o;c=b+o;print a**(b*c-o)-a*a**c-a – Ponkadoodle – 11 years ago

You can save a character if you use Python 3: ord('ߞ') – asmeurer – 11 years ago

17

R (20 character)

@popojan (he is not allowed to post an answer here yet) has provided the solution within 20 characters.

sum(T+T:exp(T+pi))-T

Output:

> sum(T+T:exp(T+pi))-T
[1] 2014

R (22 character)

Anonymous user has suggested shorter solution.

strtoi("bbc",pi*pi+pi)

2014 is BBC in base 13. pi*pi+pi (=13.0112) is treated by R in this context as the integer 13. Output:

> strtoi("bbc",pi*pi+pi)
2014

R (30 character)

Thanks to @Tomas!

cat(a<-T+T,T-T,T/T,a*a,sep="")

Output:

> cat(a<-T+T,T-T,T/T,a*a,sep="")
2014

R (31 character)

cat(T+T,T-T,T/T,T+T+T+T,sep="")

Inspired from the answer by AmeliaBR. Output:

> cat(T+T,T-T,T/T,T+T+T+T,sep="")
2014

djhurio

Posted 11 years ago

Reputation: 1 113

Wow, +1! And I hoped my roman numerals solution will be the best... :( ;-)

– Tomas – 11 years ago

The variants below can be made shorter: cat(a<-T+T,T-T,T/T,a^a,sep="") (30 chars), paste0(aT+T,T-T,T/T,a^a) (26 chars) – Tomas – 11 years ago

@Tomas, the function paste0 is not allowed, as it contains the symbol 0. Your solution makes 30 characters if using cat. – djhurio – 11 years ago

create file 2014 in current directory and write list.files() - 12 characters – Zbynek – 11 years ago

@Zbynek, I expect your solution not to be valid in the general scope of codegolf rules. – djhurio – 11 years ago

15

Java - 77 75 characters

75 characters if print is added in a class with the main method:

class C{public static void main(String[]a){System.out.print('#'*'<'-'V');}}

It means 35*60-86 which is equal to 2014

True Soft

Posted 11 years ago

Reputation: 1 075

2I like your formula. – Johannes – 11 years ago

7This actually needs to be longer, because the class definition needs to be in it to run. Shortest way I know (with Java 6):class a{static{System.out.println('#'*'<'-'V');}} – Justin – 11 years ago

1@Quincunx, with Java 7, a main method is needed – True Soft – 11 years ago

2@TrueSoft Note I said "with Java 6". You should choose the shortest Java possible. – Justin – 11 years ago

2You can remove 'ln' in println to reduce chars... – laksys – 11 years ago

@laksys, thanks for the tip :) – True Soft – 11 years ago

@Quincunx, a class without main() would throw an error at runtime, and I don't think it's ok to put that as an answer. – True Soft – 11 years ago

Another fun way would have been value of "?=".hashCode(). Not shorter, just fun. – MickJ – 11 years ago

@TrueSoft see http://codegolf.stackexchange.com/a/16099/9498

– Justin – 11 years ago

I can improve this answer (to 72 chars) but I can't find the answer button on this StackExchange.. weird :S – javatarz – 11 years ago

You can shave 4 bytes off the expression if you're willing to use non-printables: 'j'*'' (106*19). – Boann – 11 years ago

Read it and weep: class C{public static void main(String[]a){System.out.print(0xFBCA/' ');}} – Hot Licks – 11 years ago

My solution (http://codegolf.stackexchange.com/a/18051/14156) comes at 69 chars. Beats @HotLicks' solution by 5 chars :)

– javatarz – 11 years ago

@JAnderton - Of course, that's a non-ASCII solution. Different category. – Hot Licks – 11 years ago

1@HotLicks 0x has a digit. – Boann – 11 years ago

@Boann - Drat!!! Forgot about that. – Hot Licks – 11 years ago

14

CJam - 2

KE

K and E are variables preset to 20 and 14.
I created CJam in 2014 so it's ok if it doesn't qualify.

aditsu quit because SE is EVIL

Posted 11 years ago

Reputation: 22 326

12

GolfScript, 10 8 7 chars

This solution contains non-printable characters. As xxd output:

0000000: 2714 0e27 7b7d 2f                        '..'{}/

As base 64:

JxQOJ3t9Lw==

Unpacks the ASCII codes for characters 20 and 14 and prints those numbers without any separation.

To actually generate the number 2014, I'm currently at 8 chars:

0000000: 2713 6a27 7b2a 7d2a                      '.j'{*}*

JxNqJ3sqfSo=

Takes a string containing characters with ASCII values 19 and 106 and multiplies them to get 2014.

Peter Taylor

Posted 11 years ago

Reputation: 41 901

Does it really take 3 characters to output the ascii codes for a string? That's sad :/ – aditsu quit because SE is EVIL – 11 years ago

Printing 20 and 14 without separation is acceptable. – Joe Z. – 11 years ago

3I guess this can be actually shortened to 6 chars with {xy}.* where x and y represent 20 and 14 in ASCII. – Vereos – 11 years ago

@Vereos, I somehow missed seeing your comment earlier. Very nice, and sufficiently different that it's worth posting as a separate answer. – Peter Taylor – 11 years ago

Alright, I will :) – Vereos – 11 years ago

11

Haskell, 23 characters, 24 bytes

main=print$fromEnum 'ߞ'

That's U+07DE N'Ko letter KA

MtnViewMark

Posted 11 years ago

Reputation: 4 779

According to http://codegolf.stackexchange.com/tags/code-golf/info, it has 24 characters.

– Konrad Borowski – 11 years ago

2Methinks that's 23 characters, @GlitchMr, though it may be 24 bytes. – TRiG – 11 years ago

@TRiG: Well, yes. The info page says that "If you use Unicode, byte count should use UTF-8." – Konrad Borowski – 11 years ago

11

Mathematica, 47 bytes

Total@ToCharacterCode@"Happy New Year for all!"

2014

Murta

Posted 11 years ago

Reputation: 339

If you remove the space between All and !, you can make All lowercase. – Joe Z. – 11 years ago

@JoeZ. Yes!.. tks – Murta – 11 years ago

1That's pretty awesome. – BrainSlugs83 – 11 years ago

10

Mathematica, 23 bytes

Tr@ToCharacterCode@"ߞ"

(Using the 2014 unicode char. Credit for Tr goes to alephalpha)

example

Mathematica, 46 bytes (pure math)

a=⌊E⌋;b=⌈E⌉;c=⌈Pi⌉;a^(b*c-(c-b))-a*a^c-a

idea taken from here.

Ajasja

Posted 11 years ago

Reputation: 340

2 bytes "=[LongDash]" where "[LongDash]" is replaced to character and wolfram alpha returns 2014. – Margus – 9 years ago

1That returns a list. To return only the desired string without using any numbers, try First@ToCharacterCode@"ߞ". That's 25 characters, 26 bytes. – Michael Stern – 11 years ago

2@MichaelStern Hmm I would think a List is OK. – Ajasja – 11 years ago

Nope, has to be the number itself. – Joe Z. – 11 years ago

@MichaelStern Tr@ToCharacterCode@"ߞ". – alephalpha – 11 years ago

@MichaelStern Thanks, great idea! JoeZ: Oh well:) – Ajasja – 11 years ago

10

I and others have posted shorter Mathematica solutions to this challenge, but here are two methods that I don't believe have been tried in any of the other examples, in any languages.

Mathematica, 27 characters / 27 bytes

FromDigits["MMXIV", "Roman"]

Mathematica, 37 characters / 37 bytes

(ToString /@ FromDigits /@ {"K", "E"}) <> ""

and the following 58 character variation

FromDigits[Flatten[IntegerDigits /@ FromDigits /@ {"K", "E"}]]

Michael Stern

Posted 11 years ago

Reputation: 3 029

37 chars:(ToString /@ FromDigits /@ {"K", "E"}) <> "" By the way, why does FromDigits["K"] return 20?? – DavidC – 10 years ago

@DavidCarraher Ah, 37 characters indeed, thank you. As for FromDigits["K"], "0"->0, "1"->1, "2"->2, "3"->3, "4"->4, "5"->5, "6"->6, "7"->7, "8"->8, "9"->9, "A"->10 etc. – Michael Stern – 10 years ago

10

Mathematica (24)

Found by randomly generating expression trees. TraditionalForm chops 5 characters for the floor symbol but I think rich text doesn't count.

Floor[π E(Sin@E+E^E)E^E]

Ming-Tang

Posted 11 years ago

Reputation: 5 383

1+1 Very nice! Pi counts as two chars (takes two bytes in UTF8, so it's 25 bytes). You can get it to 22 bytes by ⌊π*E(Sin@E+E^E)E^E⌋ (as you mentioned). – Ajasja – 11 years ago

10

EXCEL, 24 characters:

=COLUMN(T:T)&COLUMN(N:N)

user14011

Posted 11 years ago

Reputation: 161

Why not =COLUMN(T1)&COLUMN(N1)? – Neil – 9 years ago

@Neil because that has digits. – Titus – 8 years ago

you can shorten to 16 bytes by using =COLUMN(BYL:BYL) – Taylor Scott – 8 years ago

1How does this even work? – Timtech – 11 years ago

2@Timtech T:T and N:N define an entire column, and COLUMN returns the column number of the reference passed in (of its top left cell, IIRC). & is string concatenation. – John Dvorak – 11 years ago

Good job there :) – Timtech – 11 years ago

How about the sheet references to shorten it even more? – Konrad Viltersten – 11 years ago

9

Java (68)

Solution 4: 68 chars (Thanks @radiodef))

class C{public static void main(String[]a){System.out.print(+'ߞ');}}

Solution 3: 69 chars (Thanks @Kamran)

class C{public static void main(String[]a){System.out.print(~~'ߞ');}}

Solution 2: 71 chars

class C{public static void main(String[]a){System.out.print('޾'+' ');}}

Solution 1: 72 chars

class C{public static void main(String[]a){System.out.print((int)'ߞ');}}

<3 Unicode.


Solution Derivation Technique: Copy the output from the following line and convert that character back to int for your a working solution.

System.out.println((char)2014));

javatarz

Posted 11 years ago

Reputation: 273

1n->+'ߞ' for 8 bytes (7 characters), since lambdas are appropriate equivalents of a program. – Olivier Grégoire – 8 years ago

I'm pretty sure that 1 is a digit and hence forbidden. – Peter Taylor – 11 years ago

2Mine is better, without any numbers, and has 69 character.

class C{public static void main(String[]a){System.out.print(~~'ߞ');}} – Kamran – 11 years ago

Didn't think of that. Nice solution @Kamran – javatarz – 11 years ago

4By the way instead of the double complement, you can basically cheat and use the useless "positive" operator. System.out.print(+'ߞ'); All it will do is promote to int. – Radiodef – 11 years ago

1Note: This current answer produces text, not a Number object, as the question requested. – djangofan – 11 years ago

@Radiodef Updated the answer! Thanks for the suggestion. – javatarz – 11 years ago

@djangofan not sure if @JoeZ. meant it to be a number specifically. Either way, I don't think your statement is completely true. The only way Java can bit compliment the value is to consider it an Integer (or int). Here's a SSCCE that proves my point: Object o = ~~'ߞ'; System.out.println(o.getClass()); the output to which is class java.lang.Integer – javatarz – 11 years ago

@PeterTaylor Thanks for the note. I removed that solution. The current solution, you'll find, is compliant to requirements (to the best of my knowledge ;)) – javatarz – 11 years ago

@OlivierGrégoire In that case you no longer need the +. Simply o->'ߞ' will be enough, if the return-type is an int. Try it online. But the challenge states "Your task is to make a program", so I would just leave it as is. Maybe changing class C{public static void main to interface C(static void main to save a byte, by going from Java 7 to 8.

– Kevin Cruijssen – 7 years ago

1Tip: you can use enum C{ instead of Class C{ Some IDEs think its a compiler error but it compiles flawlessly. that can result in another byte shaved off – masterX244 – 11 years ago

8

D

ϯ has the numerical value 1007 in Unicode encoding.

as compiler message during compilation (20 chars)

pragma(msg,'ϯ'+'ϯ');

runtime version (45 chars)

import std.stdio;void main(){write('ϯ'+'ϯ');}

mleise

Posted 11 years ago

Reputation: 111

(late comment) Can you do pragma(msg,'ߞ'); and import std.stdio;void main(){write('ߞ');}? NOTE: ߞ IS U+07DE (2014). – Erik the Outgolfer – 9 years ago

Arithmetical results are always widened to at least 32-bit integers, which is why the two character values add up and print as "2014". A single character retains its type and should be printed verbatim. – mleise – 9 years ago

1Couldn't you improve this by ditching the import and just qualifiying the write call (e.g., void main(){std.stdio.write('ϯ'+'ϯ');}) – Travis – 11 years ago

No, the compiler still requires the import. – mleise – 11 years ago

8

JavaScript 59, 44, 36, 29

a=+'';b=''+a+++a++;a+++b+ ++a

Assuming alert can be skipped due to implicit return


a=+'';b=''+a+++a++;alert(a+++b+ ++a)

alert([-~-~'',+'',-~'',-~-~-~-~''].join(''))

Those are l characters not 1
l='length';alert([[,,][l],[][l],[,][l],[,,,,][l]].join(''))

zzzzBov

Posted 11 years ago

Reputation: 2 915

this is nice. +1 – gion_13 – 11 years ago

8

J - 11 bytes - Base arithmetic

+:_bj*p:_bf

Explanation

_bf and _bj are 15 and 19 in infinite base, therefore p:_bf is 15th prime, which is 53. The result is then 19*53 doubled, which is 2014.

J - 31 28 bytes - Math

(((!>:&+:)-(!>:))+:&+:)>.^*_

Explanation

The implementaion of A004126 sequence from OEIS where I searched for the ways to calculate 2014. Basically it's C(2*n+1,3)-C(n+1,3) where n=12.

This means ceiling(exp(signum(infinity))), which is 3

>.^*_

To get 12 we double it two times.

+:&+:

Everything else is a combo of a dyadic fork and monadic hook. You can read about them here.

Other's solution in J

+/(>.^*_)&u:'Happy new year to you!'

Which normally is +/3&u:'Happy new year to you!', it's a shame we need a number to work with strings.

It was fun to remember J :).

swish

Posted 11 years ago

Reputation: 7 484

2Another 11 char J solution: *./a.I.'&j'. – randomra – 10 years ago

it's a shame we need a number to work with strings. You don't. You could do +/a.i.'Happy new year to you!' – ɐɔıʇǝɥʇuʎs – 11 years ago

7

AutoHotkey 31/13

send % ++(z:=true) z-z true z+z

This year special solution

send % A_year

Avi

Posted 11 years ago

Reputation: 261

27 bytes: a:=Asc("")Asc(""), Send %a%. The characters in the Asc functions don't show correctly SE for me but they're the ASCII characters 20 and 14 copied and pasted into AHK. They show up as DC4 and SO (or maybe S0) in SciTE. – Engineer Toast – 8 years ago

7

Golfscript - 11 10 chars

'&~I'{}/-*

computes 38 * 53 (ie an expansion of the prime factorization of 2014: 2 * 19 * 53)


Old Version

'f.'{}/.*\-

This computes 462-102.

'f.'{}/ puts the ascii values of f and . on the stack.
.*      squares the value of the .
\-      swaps the two values, then subtracts

Justin

Posted 11 years ago

Reputation: 19 757

Interestingly, the Befunge version of this Golfscript ('&~I'{}/-*), "&~I"-*.@, is one char longer than my Befunge answer and one character shorter than Golfscript. – Justin – 11 years ago

1Note that 2*9=18; what you meant was 2*19=38. – Kyle Kanos – 11 years ago

7

GolfScript, 10

I can't beat Quincunx's 10-char plain ascii solution but I can match it:

'N,,'{}/*+

(it calculates 44*44+78)

And now a different approach :)

'codegolfing is yummy'{+}*

aditsu quit because SE is EVIL

Posted 11 years ago

Reputation: 22 326

5Yet another 10-char solution: "xr"{`(;}% (free bonus smiley included!) – Ilmari Karonen – 11 years ago

7

Perl 6, 37 characters

This is not my actual solution (the real solution is in PHP, and is shorter), but I decided to make shorter version of Python's solution, because it's a really interesting idea.

say [+] ords 'Happy new year to you!'

So, what does it do? Well, it gets list of character positions (ords function), sums them together ([] is a reduce operator, which takes the exact operator between square brackets, in this case +), and say prints the result with new line. Could be WAY shorter by abusing ~^ prefix operator (which isn't implemented in Rakudo Perl) or Unicode characters, but this is just for fun solution.

Perl 6 is a quite an interesting language, even if it's not as good as Perl 5 in most code golf tasks (because of mandatory whitespace in many situations, and generally less DWIM). However, in this case, because of builtin sum and ords, it wins with Perl 5.

Konrad Borowski

Posted 11 years ago

Reputation: 11 185

say ord "ߞ" is shorter but certainly less whimsical. – Brad Gilbert b2gills – 10 years ago

At first I thought you meant your solution was in Perl and was 6 characters long. And then I was like, "no, that can't be right." – Joe Z. – 11 years ago

7

R using roman numbers, 29 characters

as.numeric(as.roman('MMXIV'))

Tomas

Posted 11 years ago

Reputation: 2 333

@plannapus yeah I know crazy idea :) Well, but quite normal in ancient times :) – Tomas – 11 years ago

probably a "legacy" function :) – plannapus – 11 years ago

4Nice! There are 28 characters in as.double(as.roman('MMXIV')). – djhurio – 11 years ago

6

C#, 60 characters

class a{static void Main(){System.Console.Write(- -'ߞ');}}

Thanks to mleise for the original answer for D!

Note: space between hyphens is important

user12487

Posted 11 years ago

Reputation:

1 is not allowed – Random – 11 years ago

I came up with 'ϯ'+'ϯ' but I believe this is 1 char shorter. – Jodrell – 11 years ago

2if an exit code is acceptable class a{static int Main(){return - -'ߞ';}} is just 42 chars. – Jodrell – 11 years ago

7No need for "- -'ߞ'", could just do +'ߞ'. So: class a{static void Main(){System.Console.Write(+'ߞ');}} which is 56 bytes – David_001 – 11 years ago

1If we want to get without using the ASCII characters this is simple, int i; i = " ".Length; Console.WriteLine(i + "" + ((i-i)) + "" + --i + "" + ++i*i); – Vara Prasad.M – 11 years ago

System.Console.Write(DateTime.Now.Year) has the added advantage that it will solve similar future contests as well :) – Julia Hayward – 11 years ago

@JuliaHayward But it will fail this contest next year... – Spook – 11 years ago

1@JuliaHayward and it will also fail this contest this year... (Reread the OP). – BrainSlugs83 – 11 years ago

1OK, tongue-in-cheek comment failed utterly – Julia Hayward – 11 years ago

1VS 2010 crashes when I try this with a fresh new Console Application... – Otiel – 11 years ago

6

Ruby — 8 characters

p ?ߞ.ord

where ߞ is Unicode character U+07DE — N'Ko letter ka.

This is what it looks like when I copy and paste the above line and run it in my Terminal. Notice the character does not display:

enter image description here

O-I

Posted 11 years ago

Reputation: 759

I understand what you're trying to do, but help me out... How do I test this? Copy & pasting your code doesn't work. If I copy & paste the little "07DE" Unicode char then I actually see \U+FFDF in irb, but that char has an ord of 85. – Darren Stone – 11 years ago

I tested it by copying the symbol from the site listed above and running it in pry. I don't think Stack Exchange recognizes the symbol by default (so simple copy & paste of the above won't work), but Ruby 2.0+ should. – O-I – 11 years ago

2This script prints nothing. – tobyink – 11 years ago

1How did you enter it? It works for me. Also, what version of Ruby are you using? – O-I – 11 years ago

Interesting. The N'Ko alphabet reads right to left. Interspersing it with Roman characters seems to shuffle characters depending on where you edit/paste. Has anyone else been able to get this to run, or am I the only one? – O-I – 11 years ago

1p ?ߞ.ord would meet the requirement of printing. – steenslag – 11 years ago

1this works for me – mpapis – 11 years ago

@steenslag I must have been snoozing to miss the print requirement. I thought returning 2014 was sufficient. Corrected. Thanks for pointing that out! – O-I – 11 years ago

6

Perl 6, 11 characters:

say 'ߞ'.ord

snoopy

Posted 11 years ago

Reputation: 161

6

Python 3 (17 bytes)

print(ord("ߞ"))

Python 2 (50 bytes)

s,t=str,True;print s(t+t)+s(t-t)+s(t/t)+s(-~t<<t)

razpeitia

Posted 11 years ago

Reputation: 161

1Those are actually 16 and 49 bytes respectively. The trailing newline doesn't count. – nyuszika7h – 10 years ago

Python 2 version can be shortened to t=True;print't+t'+'t-t'+'t/t'+'-~t<<t', where the ' have to be changed to backticks. (I don't know how the enter real backticks that are shown as such). – Reinstate Monica – 11 years ago

1@WolframH wrap the code-block in an extra backtick. Like so: t=True;print`t+t`+`t-t`+`t/t`+`-~t<<t` where the initialization and end of the code block are done by use of: \``. Alternatively, replace every \`` in the code with\``: t=True;print\t+t`+`t-t`+`t/t`+`-~t<<t`` – Justin – 11 years ago

6

JavaScript:

alert(+!![]+!![]+[+[]]+ +!![]+(+!![]+!![]+!![]+!![]));

each +!![] is 1 (![] is false, !false is true and +true is 1)

+[] is 0, and [0] is "0"

so this turns into 1+1+"0"+1+(1+1+1+1)

Zaq

Posted 11 years ago

Reputation: 1 525

6

guess this is already beaten but I like the approach:

<?php
$three=round(pi());
$one=pi()/pi();
$two=$three-$one;
$four=$three+$one;
$zero=$one-$one;
echo $two.$zero.$one.$four;
?>

Thorsten Staerk

Posted 11 years ago

Reputation: 261

5

Vim 7.4, 18 bytes

:h os_v<CR>$bbbyiwZZp

Here, <CR> means a literal newline. Uses the help page os_vms.txt which contains the number 2014 on the first line.

How it works:

:h os_v<CR>            This opens the help page for os_vms.txt, the line the cursor lands on contains '2014'.
           $bbb        Move the cursor to the '2014' (end-back-back-back)
               yiw     Copy it (yank-in-word)
                  ZZ   Close the help page
                    p  Paste the copied word

If numbers were allowed we could do:

i2014

Loovjo

Posted 11 years ago

Reputation: 7 357

It's 2010 for me instead – user41805 – 8 years ago

@KritixiLithos Weird, it works for me. What help page does :h os_v open for you? – Loovjo – 8 years ago

1It opens os_vms.txt says Vim version 7.3 and last change was made in 2010 Jul 8 – user41805 – 8 years ago

What version of Vim are you using? – Loovjo – 8 years ago

I'm using Vim version 7.3 – user41805 – 8 years ago

Perhaps it is the difference in OS (I'm using macOS El Capitan) – user41805 – 8 years ago

@KritixiLithos I'm using 7.4 (also Capitan), that's probably why. I'll update the answer accordingly. – Loovjo – 8 years ago

2If numbers were allowed you could just do i2014. :P – Joe Z. – 8 years ago

@JoeZ. Oh right. I'm stupid :P – Loovjo – 8 years ago

5

Javascript (29 chars)

t=!'',a=t+t+'';a+!t*t+t*t+a*a

Not the shortest but some boolean logic

Rob Fox

Posted 11 years ago

Reputation: 201

That was my first idea too haha. This is the best I could get: a=!'';a+a+""+(+!a)+(+a)+(a+a+a+a) (33 chars) – Benno – 11 years ago

@Benno (+!a) is pretty clever, didn't know it works like this – Rob Fox – 11 years ago

Yeah, it seems to treat it as an integer, only when in brackets though! Without the brackets, it reverts to 2falsetruetruetruetruetrue ;) – Benno – 11 years ago

5

T-SQL, 50 40

My original entry seems too straightforward. How's this?

PRINT RIGHT(CHECKSUM(',,.'),LEN('````'))

(Disclaimer: Given Steve Matthews's comment, the above may be dependent on configuration.)

Here's the SELECT version in SQL Server 2012.

Original entry:
This may look obscene in more ways than one, but it's valid.

DECLARE @ INT=\PRINT CONCAT(-~-~@,@,-~@,-~-~-~-~@)

Try it in SQL Server 2012. Here is a version using SELECT.

Explanation: "\" is a valid currency symbol. (Do a find for "String to" here.) If you assign just a currency symbol to an INT variable, you store 0. Also, "@" is a valid variable name. "~" is bitwise NOT, and "-" is negative. If you negate a NOT-ed INT, you get the INT plus 1. So, repeat "-~" until you make @ into the digit you need. Then CONCAT() your digits.

Muqo

Posted 11 years ago

Reputation: 499

Running PRINT RIGHT(CHECKSUM(',,.'),LEN('````')) on MS SQL Server 2008 R2 produces the response "1200" – Steve Matthews – 9 years ago

Can I suggest instead something like PRINT ASCII('')*ASCII('j') which is just 27 bytes (note that the character that isn't rendered here is the DC3 CHAR(19) in the first set of quote marks. – Steve Matthews – 9 years ago

@Steve I actually ran the checksum one on the same version, too, but you touch on a good point that maybe the checksum algorithm could vary based on configuration. I should add a disclaimer. Also, I like your better 27-byte solution. You should post it as an answer so people can vote it up. – Muqo – 9 years ago

PRINT UNICODE(N'ߢ') has 20 bytes – Jan Drozen – 6 years ago

@JanDrozen Very nice, but you must've meant 'ߞ'. – Muqo – 6 years ago

5

Javascript, 37 bytes

((_=+!![])<<''+_+''+_)-(_<<_+++_+_)-_

It's not code golf until someone bitshifts.

$ node
> ((_=+!![])<<''+_+''+_)-(_<<_+++_+_)-_
2014

It is actually Javascript, I promise.

((_=+!![])    // create 1 and save in _
  <<          // left bitshift by 11 to get 2048
    ''+_+''+_ // create 11 from '1' + '1'
  )           
  -           // subtract (2048 - 32) === 2016
  (
    _<<       // bitshift by 5 to get 32
  _+++_+_     // create 5 from 1 + (++1) + 2
)-_           // subtract 2 to get 2014

Dan Prince

Posted 11 years ago

Reputation: 1 467

2That looks so much like Brainfuck. – Joe Z. – 10 years ago

4

TI-BASIC, 12 bytes

A completely new approach.

iPart(π+iPart(e)sinh(π+√(π

This could probably be golfed further, using a 1-byte token in place of e, but I have spent far too long on this today...

Khuldraeseth na'Barya

Posted 11 years ago

Reputation: 2 608

4

Bash 28

echo $((`printf %d \':`#yG))

Similar to the Ruby and Python solutions, but uses base62, now without literal 6 and 2 (but pretty long...)! Using base58 as recommended by @DigitalTrauma along with removing quotes around the printf format string, Thanks!

Better 17 (Thanks @user13955 and @DigitalTrauma!)

tr a-l /-:<<<dbcf

"It's shorthand for tr abcdefghijkl /0123456789:. Not very geeky, I'm afraid." -user13955 Also updated to use a heredoc instead of echo, thanks @DigitalTrauma!

Dom Hastings

Posted 11 years ago

Reputation: 16 415

3Not a valid solution since 2 and 6 are forbidden. – jub0bs – 11 years ago

haha, Oh dear... – Dom Hastings – 11 years ago

1user13955 suggested this edit, might be worth considering: echo dbcf|tr a-l /-: It's shorthand for tr abcdefghijkl /0123456789:. Not very geeky, I'm afraid. – Justin – 11 years ago

I have a solution in pure bash/ksh. i.e. it does not use any external program like tr. However, I lack the 10 reputation to post this. ;-) – Henk Langeveld – 11 years ago

1Pure bash|ksh 110 bytes: sum(){ (IFS=+;echo $(($*)));}&&d(){ echo $((n=n+n));}&&false||n=$?&&sum $(d;d;d;d;echo $((n=n+n+n+n));d;d;d;d) – Henk Langeveld – 11 years ago

1I verified that the unicode solution works in ksh93. – Henk Langeveld – 11 years ago

As the question doesn't seem to preempt showing any other characters in addition to 2014, how about 'date' for 4 characters? HNY – David DelMonte – 11 years ago

@DavidDelMonte, I think that answer has been suggested a few times, but it has to be 2014 specifically, otherwise, you'd be on to a winner! – Dom Hastings – 11 years ago

1Use a bash here-string to shave 3 chars of the tr solution: tr a-l /-:<<<dbcf – Digital Trauma – 11 years ago

1And no need for the quotes around printf format string: echo $((\printf %d "'>"`#wu))` – Digital Trauma – 11 years ago

1And use base 58 and drop one more char: echo $((\printf %d ':`#yG))` – Digital Trauma – 11 years ago

@DigitalTrauma Amazing! Updated, thank you! – Dom Hastings – 11 years ago

2@DigitalTrauma Pure bash 18: echo $[$[$#xd]#bbc] ... without fork! – F. Hauri – 11 years ago

@F.Hauri Good one! – Digital Trauma – 11 years ago

4

Javascript: 47 characters

Not the shortest, but another solution:

$ node
> [!+[]+!+[]]+[+[]]+[+!+[]]+[!+[]+!+[]+!+[]+!+[]]
"2014"

Source

Javascript: 6 characters

Your task is to make a program that prints the number 2014 without using any of the characters 0123456789

Ok, here you go: 6 characters.

$ node
> "²⁰¹⁴"
'²⁰¹⁴'

Yeah, only for ASCII lowers. :-)

Will I win? :-D

Ionică Bizău

Posted 11 years ago

Reputation: 231

4

Ruby:

p eval("#{""=~//}x#{"\a".ord}de")

Here is how it works inside IRB shell:

>> p eval("#{""=~//}x#{"\a".ord}de")
2014

tuxdna

Posted 11 years ago

Reputation: 141

4

TI-Basic, 49 41 31

π/π+π/π→B:B^B^B→C:C^C(C/B)-CB-B

Explanation

  • π/π+π/π→B Store 2 in B
  • :B^B^B→C Store 16 in C
  • :C^C(C/B)-CB-B Display 2014

Timtech

Posted 11 years ago

Reputation: 12 038

I'm up voting on the assumption this works; I have no way to test it. – Michael Stern – 11 years ago

@MichaelStern Explanation added :) – Timtech – 11 years ago

:π/π+π/π→B:B^B^B→C:Disp C^C*(C/B)-C*B-B would be 2 characters shorter. – Michael Madsen – 11 years ago

@MichaelMadsen Thanks, updated! – Timtech – 11 years ago

8 bytes can be saved with various tweaks: iPart(e→B:BBBB:Ans^B(Ans/B)-AnsB-B – Khuldraeseth na'Barya – 7 years ago

Another 23-byter: iPart(e→B:BBBB^(BBB)-BBBBB-B – Khuldraeseth na'Barya – 7 years ago

That can be 21 without assignment to B, using Ans instead. I would advise at least fixing your current solution, as it currently outputs a number well over 2014. That should be C^B instead of C^C. – Khuldraeseth na'Barya – 7 years ago

4

PHP: 54 chars

Slightly different approach, albeit long, using concatenation, and not using ordinal values:

<?=floor(M_E).floor(M_EULER).ceil(M_EULER).ceil(M_PI);

zamnuts

Posted 11 years ago

Reputation: 263

<?= echo date('Y') ?> – Surabhil Sergy – 11 years ago

1@SurabhilSergy that is not a valid answer, the output will change in 2015. – zamnuts – 11 years ago

4

J (18)

This one doesn't use any character codes. Uses the idea that the sum of the sequence of natural numbers from 1 -> 63 = 2016.

<:<:+/i.*:+~+~p:%_

cardinaliti

Posted 11 years ago

Reputation: 71

You could save two bytes <:<:+/i.*:+~dyad – FrownyFrog – 7 years ago

4

Multiboot x86 Assembly (250 bytes):

[BITS N]
%define L(x) mov dword [eax],'zaza'-x
O equ 'A'<<`\xe`
F equ 'bab'-'aaa'
M equ `\xFF\xAF\xAA\xFA`-`\xFD\xFF\xFC\xDE`
C equ -(M+F)
h:
dd M
dd F
dd C
dd h+O
dd h+O
dq 'a'-'a'
dd s+O
s:
mov eax,'\'<<`\r`
L('HBJB')
add eax,'e'-'a'
L('IBFB')
hlt

Compile with:

nasm src.S -o 2014.bin -f bin -DN=32

(If someone has a suggestion for replacing the N macro, I'm all ears)

tecywiz121

Posted 11 years ago

Reputation: 1 127

1You can also submit the machine code as its own answer, provided final compiled binary doesn't have any bytes from 0x30 to 0x39 in it. – Joe Z. – 11 years ago

4

PHP - 13 bytes

<?=m_n_^_o_k;

A fairly trivial ASCII-only solution.

Other variants:

<?=Q__Q^cone;
<?=VonV^d__b;
<?=PAAP^bqpd;
<?=BEAU^pupa;

etc.

primo

Posted 11 years ago

Reputation: 30 891

BEAU^pupa LOL. – Joe Z. – 11 years ago

<?=date('Y'); in any year ) – Dmitry Dubovitsky – 11 years ago

@DmitryDubovitsky <?=date(Y); would also work, but it won't always print 2014, as the problem requires. – primo – 11 years ago

4

05AB1E, 4 bytes

ToRÀ

Try it online!

T        # 10
 o       # 2**x (1024)
  R      # reverse (4201)
   À     # rotate left (2014)
         # implicit output

Grimmy

Posted 11 years ago

Reputation: 12 521

1Boring alternative: ŽGMR. – Kevin Cruijssen – 5 years ago

4

Golfscript, 6 chars

{xy}.*

Inspired from Peter Taylor's answer.

This solution involves non-printable characters too.

Where x and y represent 20 and 14 in ASCII (the non-printable characters we were talking about before).

Vereos

Posted 11 years ago

Reputation: 4 079

4

Windows Calculator - 5 characters

Inspired by this answer to a different question.

Open the Windows Calculator in Programmer View (Hex mode) and type:

DFEC±

This is what the result looks like.

enter image description here

me and my cat

Posted 11 years ago

Reputation: 1 107

5If you change the size to Word, it will be an almost-valid answer that will output only 2014 – Ismael Miguel – 10 years ago

I don't think this is a programming language... – cat – 9 years ago

4

Japt, 3 bytes (2 chars)

Japt is newer than this competition (created in 2015), but was not created specifically to answer it.

That's right. 2 chars. Explanation:

#   // Char-code of next character
 ߞ  // Character with char-code of 2014
    // Implicit output

Try it online!

ETHproductions

Posted 11 years ago

Reputation: 47 880

Does this mean I can undelete my Microscript answer? – SuperJedi224 – 9 years ago

@SuperJedi224 There's a list in the main post of "invalid but interesting answers". I think newer languages fall into this category. – ETHproductions – 9 years ago

4

Emotinomicon, 14 bytes

ߞ

Try it online!

Explanation:

  ߞ       explanation
              begin quote string
    ߞ           
              end quote string
              pop N and output as a number

ߞ is U+7DE. 0x7DE is 2014.

Erik the Outgolfer

Posted 11 years ago

Reputation: 38 134

Okay, thanks! In your code, do you convert the quote string to a number when it's outputting? – MilkyWay90 – 6 years ago

@MilkyWay90 Emotinomicon pushes the character code of each character in the string. – Erik the Outgolfer – 6 years ago

4

The Shakespeare Programming Language, 219 bytes

I am using drsam94's compiler.

.
Ajax,.
Puck,.
Act I:
Scene I:
[Enter Ajax and Puck]
Ajax:
You is the difference between a fat fat fat fat fat fat fat fat fat fat fat cat and the sum of a fat fat fat fat fat cat and a fat cat!Open thy heart!
[Exeunt]

Explanation

.

Everything from the first line to the first period is the title, parsed as a comment.

Ajax,.
Puck,.

These are characters from Shakespeare's plays, and descriptions (also comments)

Act I:
Scene I:

Act I and Scene I, used for gotos (not used here)

Ajax:

The character speaking.

You is the difference between

Assigns the difference of the next two values to the character being spoken to.

a fat fat fat fat fat fat fat fat fat fat fat cat

Every adjective multiplies by 2, a noun is either 1 or -1 depending on its connotation (in this case it's 1). 2^11 * 1 = 2048.

the sum of a fat fat fat fat fat cat and a fat cat

The sum of the next two values. 32 + 2 = 34, so 2048 - 34 = 2014

Open thy heart!

Prints the value of the character being spoken to as a number.

Oliver Ni

Posted 11 years ago

Reputation: 9 650

3

PHP, 27 bytes

not in any way competitive to xfix´s solution, but here are a few versions with 27 bytes each:

<?=hexdec($c=hexdec(e)),$c;   # e->14->20, e->14
<?=ord(U)-ord(A),hexdec(e);   # 85-65,14
<?=($c=ord(","))*$c+ord(N);   # 44*44+78
<?=($c=ord("."))*$c-ord(f);   # 46*46-102

The first one already has been posted by brother Filip; but the others have not.


This one has 37 bytes, but I like it (inspired by the Calculator solution)

<?=dechex(hexdec(dfeb)^hexdec(ffff));

or 13 bytes with

<?=sqpu^AAAA;

But that idea has already been used by primo

Titus

Posted 11 years ago

Reputation: 13 814

3

R, 39 31 bytes:

x=T+T;x^(x*x*x+x)*x-x^(x*x)*x-x

R, also 39 31 bytes:

x=T+T;z=x*x;x^(z*x+x)*x-x^z*x-x

Thanks Scrooble!

More entertaining version: 46 bytes

z=pi;x=z*z;y=exp;j=z/y(z);floor(y(x)/(x-j-j))

Not especially efficient, but I had a lot of fun messing around with this. I'm sure there's a shorter way using just those two numbers

Long-form, subbing in the variables: floor(exp(pi*pi)/((pi*pi) - pi/exp(pi) - pi/exp(pi))

In real-person numbers: floor(19333.69 / (9.869604 - 0.1357605 - 0.1357605)) = floor(2014.328)

Punintended

Posted 11 years ago

Reputation: 396

1Save 8 bytes by getting 2 a shorter way. – Khuldraeseth na'Barya – 7 years ago

Save a few in the entertaining one by eliminating some assignment. – Khuldraeseth na'Barya – 7 years ago

And some more – Khuldraeseth na'Barya – 7 years ago

3

Rockstar, 34 32 bytes

X was up equalizing a word
Say X

Say hello to rockstar! (No I didn't make this one)

Explanation:

This first line:

X was up equalizing a word

Uses Rockstar's Poetic number literals. (As opposed to regular literals, which use numbers).

This means that the length of every word after was indicates the digit in that position. So here we have a 2 length (up), a 10 length (equalizing) a 1 length (a) and a 4 length (word). The length is % 10, so equalizing becomes a 0, and the result is that the variable X has the value 2014.

Then of course we print it with Say

Skidsdev

Posted 11 years ago

Reputation: 9 656

3

C++, 50 bytes

#include<iostream>
int main(){std::cout<<'U'^'A';}

zeeshan mughal

Posted 11 years ago

Reputation: 141

You should provide compile-ready code in C++. – Joe Z. – 11 years ago

Also, use four spaces before each line for blocks of code. – Joe Z. – 11 years ago

i added "iostrean but it disappeared, actually am new so don't know how to" – zeeshan mughal – 11 years ago

5This is supposed to be code golf, i.e. shortest code possible. Remove unnecessary whitespace, etc – Doorknob – 11 years ago

@DoorknobofSnow thanx, after your edition i can still see few extra spaces – zeeshan mughal – 11 years ago

Rather verbose. int('U'-'A') prints 20, int('O'-'A') 14. Even shorter: ~~'U'-'A' also is 20. Result: #include <iostream> int main(){std::cout<<~~'U'-'A'<<~~'O'-'A';}. – MSalters – 11 years ago

Even more shorter: 'U'^'A'. – MSalters – 11 years ago

@MSalters Did you try compiling this? g++ on all standard versions gives an error: no match for ‘operator^’. – LegionMammal978 – 8 years ago

Doesn't work! – NieDzejkob – 7 years ago

3

LiveScript, 18 bytes

The temporary solution

new Date!.getYear!

Unicode

\ߞ .charCodeAt!

Over Excitement

x=!Happy
Happy = -> console.log it
New = -> +it
Year = ->++x and Year
Year.valueOf = -> x

Happy New Year!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Brigand

Posted 11 years ago

Reputation: 1 137

4I initially assumed that you mean LiveScript, as in, JavaScript in first Netscape 2 beta. – Konrad Borowski – 11 years ago

1@GlitchMr, that's where the name came from :-) – Brigand – 11 years ago

Only the "Unicode" solution is valid. The "temporary" solution violates the rule "... independently of any external variables such as the date or time" – pppery – 5 years ago

... and the "Over Excitement" solution is not a serious contender, – pppery – 5 years ago

3

C, 37 Characters

main(){printf("%d%d",'d'-'P','\xE');}

shiju

Posted 11 years ago

Reputation: 31

You could knock off 3 bytes by renaming main to f since we don't require main to be used. – MD XF – 8 years ago

3

MATLAB (no char codes), 47 chars

p=pi,q=p^p;e=exp(p);floor(q*q+q*e-q-q-q-p-e-e)

Christopher Creutzig

Posted 11 years ago

Reputation: 383

I played with a similar approach in Mathematica (which has a much larger set of mathematical constants built-in). How long did it take you to develop that solution. – Michael Stern – 11 years ago

Just playing around, maybe five minutes, probably less. I’m pretty sure this is far from the most compact formula. – Christopher Creutzig – 11 years ago

3

JSFuck, 1267 bytes

In Javascript, here is the alert(2014) ! (Try in browser Console).

[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]][([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]]((![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]+(!![]+[])[+[]]+(![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+[!+[]+!+[]]+[+[]]+[+!+[]]+[!+[]+!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]])()

This sample uses only six different characters to write and execute code. This was generated by https://github.com/aemkei/jsfuck.

Cybermaxs - Betclic

Posted 11 years ago

Reputation: 131

1Even though it's the longest answer rather than the shortest, +1 for JSFuck. – Joe Z. – 11 years ago

3

Python 2, 68 bytes

Not really short, but it abuses the fact that Python accepts booleans where an integer is required, because bool is a subclass of int.

import string;d=string.digits;T=True;print d[T+T]+d[:T+T]+d[T+T+T+T]

nyuszika7h

Posted 11 years ago

Reputation: 1 624

+1 for the first non-cheating program in this question that doesn't depend on ASCII or UTF-8 (unless I missed something) – Konrad Borowski – 11 years ago

False can be shortened to d>d. On the other hand, d[d>d]+d[T] can be shortened to d[:T+T], so that optimization is not really necessary ;-). Also, from string import*;d=digits;saves one character. – Reinstate Monica – 11 years ago

@WolframH Noted. I'll update it later. – nyuszika7h – 11 years ago

3

MathGolf, 2 bytes

ID

Try it online!

Explanation

I   Pushes 20
 D  Pushes 14

The stack is printed in full on termination.

maxb

Posted 11 years ago

Reputation: 5 754

3

bash 35

I want something that doesn't use ASCII or UNICODE.

[ ];x=$?;y=$[x+x];echo $y$?$x$[y+y]

If you don't mind some error messages mixed in (28 characters):

[;x=$?;echo $x$?$[x/x]$[x+x]

You can get rid of the error messages if you don't mind corrupting a file (32 characters):

[ 2>x;x=$?;echo $x$?$[x/x]$[x+x]

Stephen Montgomery-Smith

Posted 11 years ago

Reputation: 231

1That doesn't use ASCII? That's a bit hard. – Joe Z. – 11 years ago

@JoeZ. My program would work just as well if the system used ebcdic. And as you know, a multitude of ebcdic systems use bash. :-) – Stephen Montgomery-Smith – 11 years ago

Maybe 34 bytes: :;y=$[x=!$?,x+x];echo $y$?$x$[y+y] Try it online!

– Isaac – 5 years ago

Hmmm, Just 29 bytes: echo $[x=y=!x,y+=y]$?$x$[y+y] Try it online!

– Isaac – 5 years ago

3

VB.NET, 59 bytes

MsgBox(((Asc(vbTab) + Asc(vbTab)) & Asc("~")) / Asc(vbTab))

takes the ascii values of a Tab twice (18) concats the ascii value of "~" (126), giving "18126" and then divides the lot by ascii of a Tab (9) = 2014

Alternatively, you can do

MsgBox Asc("j") * vbKeyPause

i.e. ascii of "j" (106) * value of the constant vbKeyPause (19), for a total of 28 characters (less than half the original).

Fozzedout

Posted 11 years ago

Reputation: 121

The exact same code works for VB6 too. – Rob – 11 years ago

user14566 suggested this edit: `27 bytes: MsgBox(Asc("") & Asc(""))

=20 =14` – Justin – 11 years ago

2You can run this in the immediate window of VBA as ?Asc("j")*vbKeyPause, which shortens it up a bit. – Gaffi – 11 years ago

3

newLISP - 61 characters

I can't seem to play golf in Lisp -- is it just too wordy?

(int(apply string(map(fn(c)(find c'(b c a e d)))'(a b c d))))

cormullion

Posted 11 years ago

Reputation: 569

3

Javascript, 6 characters (8 bytes)

I never saw any rule saying we had to produce the number 2014 in the absence of any other output.
(Nor anything about not outputting to an error, but that's more obvious.)

new`—`

For me, on Firefox Nightly, this produces TypeError: "\u2014" is not a constructor, which contains the number 2014.

(If it isn't obvious, this happens because the em dash, —, is U+2014. Or, in other terms, it's the unicode character that can be represented by the hexadecimal number 2014.)

NO_BOOT_DEVICE

Posted 11 years ago

Reputation: 419

3

C# - 64 chars

class P{static void Main(){System.Console.Write('!'*'>'-' ');}}

pretty printed

class P 
{ 
    static void Main() 
    { 
        System.Console.Write('!' * '>' - ' ');
    } 
}

shamp00

Posted 11 years ago

Reputation: 1 221

What if we use class P { static void Main() { System.Console.Write(2014); } } – Amit Ranjan – 11 years ago

@Amit, you can't use numbers in this challenge... – shamp00 – 11 years ago

2if an exit code is acceptable class a{static int Main(){return '!'*'>'-' ';}} is just 47 chars. – Jodrell – 11 years ago

1I like this one, my countdown numbers skills sucked so I ended up with ('d' + 'e').ToString() + Math.Ceiling(Math.PI); – NibblyPig – 11 years ago

3

Clojure, 9 bytes

Inspired by the Matlab answer, converts char \u075e to an int:

(int \ߞ)

OpenSauce

Posted 11 years ago

Reputation: 153

3

Haskell, 69 bytes

How do you get a number without using any digits in the source? Lots of people had already done it with characters or strings, so I decided to use pi, predefined in most languages. From pi, you can get the numbers 3 and 4 easily using the ceiling and floor functions. Then you can use some combination of addition, subtraction, multiplication, and maybe division to get 2014. Just by experimenting around, it would be easy to figure out a function that takes in 3 and 4 and returns 2014 (such as 4^4 * 4 + 3^3*3^3 + 4*(3^4) - 4*4*4 + 4 - 3 = 2014). This one's 70 characters:

main=print$(\x y->y^y*y+x^x*x^x+y*x^y-y*y*y+y-x)(floor pi)$ceiling pi

Now, that's fine, but writing a function like that isn't much different than just repeatedly writing floor(pi) and ceiling(pi). Is it doable with only one pi? Well, in Haskell, functions can be treated as Monads with an instance defined in Control.Monad.Instances:

instance Monad ((->) r) where
        return = const
        f >>= k = \ r -> k (f r) r

So you can use the bind function to pass one value into two different functions: g (f x) (h x) can be rewritten f >>= flip (g.h). id >>= f can be used to pass the one value twice into the same function: id >>= (^) for example is a function that returns x to the x power. The resulting program at 207 characters is more obfuscated than golfed, but it was fun to write:

import Control.Monad.Instances
main=print.((id>>=(^)>>=flip((+).(id>>=(+)>>=flip((+).(id>>=(-)>>=flip((+).(id>>=div))))))).floor>>=flip((-).(id>>=(^)>>=flip((*).(round.sqrt.fromInteger>>=(*)))).ceiling))$pi

user3175123

Posted 11 years ago

Reputation: 81

3

x86 - 16 bytes (Assembled)

This little snippet moves the stack so it overlaps the video memory, to then push the individual numbers straight to the screen (They even blink! Surely a sign of good times to come).

Code: (Note: '0'-'9' -> 0x30-0x39)

B890A8 8ED0 2C5C 50 2C04 50 48 50 40 40 50

Assembled from:

mov ax, 0xA890
mov ss, ax
sub al, 0x5c
push ax
sub al, 3
push ax
dec ax
push ax
inc ax
inc ax
push ax

Build'n run:

nasm -f bin -o 2014.com 2014.asm
dosbox 2014.com

Robert Sørlie

Posted 11 years ago

Reputation: 1 036

@TeunPronk but that's the generation code, not the submission -- the submission is the binary – cat – 9 years ago

1I think it shouldn't have any characters [0..9] in your code – Teun Pronk – 11 years ago

3

Sclipting, 3 characters (6 bytes)

This outputs the string "2014".

꼣갱꽀

Timwi

Posted 11 years ago

Reputation: 12 158

That's not 3 bytes though. – daniero – 11 years ago

I didn’t say it was. – Timwi – 11 years ago

Well I can see that obviously, but the question actually asks for a byte count. – daniero – 11 years ago

Byte count stands at 12, I believe. – cjfaure – 11 years ago

1No, it’s 6 bytes. – Timwi – 11 years ago

3

Pure bash 18

Without fork!

echo $[$[$#xd]#bbc]
2014

F. Hauri

Posted 11 years ago

Reputation: 2 654

1How about: printf %x \'— Just 13 characters (15 bytes). – Isaac – 5 years ago

@Isaac Awesome! I learn today this printf %d \'A newer seen before! – F. Hauri – 5 years ago

3

Pyth, 4 bytes

C"ߞ

Pretty straightforwards, just convert that character to an integer and print.

isaacg

Posted 11 years ago

Reputation: 39 268

While this answer is now technically the shortest, I can't accept it because it was written in a language that didn't exist at the time of writing the question. – Joe Z. – 11 years ago

@JoeZ. I understand. No worries, the rules make sense. – isaacg – 11 years ago

3

Racket, 18 bytes

(~a(+ #xa #xa)#xe)

Matthew Butterick

Posted 11 years ago

Reputation: 401

3

Excel VBA, 51 bytes

MsgBox Len("aa") & Len("") & Len("a") & Len("four")

As it's 2015 you could add an extra character onto "four" for an extra byte.

Wightboy

Posted 11 years ago

Reputation: 339

3

C, 33 30 bytes

Numerical Solution 1

f(){printf("%d",'<'*'#'-'V');}

// 2014 = 60 * 35 - 86

C, 86 83 bytes

Numerical Solution 2

#define A ((int)'}')
#define B (((int)'r')-((int)'d'))
f(){printf("%d",A*B+A+A+B);}

// A = 125
// B = 14
// 2014 = 125*14 + 125 + 125 + 14

C, 53 50 bytes

ASCII Art 1

f(){printf("┌┐ ┌┐ ┐ ┐┌\n┌┘ ││ │ └┤\n└┘ └┘ ┴  ┴");}

Result

┌┐ ┌┐ ┐ ┐┌
┌┘ ││ │ └┤
└┘ └┘ ┴  ┴

C, 94 91 bytes

ASCII Art 2

f(){printf("╔═╗ ╔═╗ ╗ ╦ ╦\n  ║ ║ ║ ║ ║ ║\n╔═╝ ║ ║ ║ ╚═╣\n║   ║ ║ ║   ║\n╚═╝ ╚═╝ ╩   ╩\n");}

Result

╔═╗ ╔═╗ ╗ ╦ ╦
  ║ ║ ║ ║ ║ ║
╔═╝ ║ ║ ║ ╚═╣
║   ║ ║ ║   ║
╚═╝ ╚═╝ ╩   ╩

Khaled.K

Posted 11 years ago

Reputation: 1 435

You could shorten all your mains to f, saving 3 bytes each, and your submission will still be valid. – MD XF – 8 years ago

3

BASIC v2.0 (Commodore 64), 24 bytes

PRINT ASC("&")*(ASC("V")-ASC("!"))

The Commodore BASIC tokens are single-byte representations of BASIC keywords. This should result in storing the above line as 24 bytes instead of 34.

I was aiming to construct an equation based on character codes, so I was looking for ideal characters in PETSCII. To minimize the number of operations in the equation, it seemed like a good idea picking a pair of divisors of 2014.

However, none of the combinations were perfect, because either one of the divisors were too large, too small or the character code of a number.

So I ended up using 38 which is CHR$("&") and 53, but instead of directly using the latter which is CHR$("5"), I used the difference of 86 and 33. These are the character codes for CHR$("V") and CHR$("!") respectively.

Tested in VICE and FC64.

Zsolt

Posted 11 years ago

Reputation: 171

3

Java 8, 33 bytes

()->Integer.parseInt("bbc",'\r');

Shaun Wild

Posted 11 years ago

Reputation: 2 329

3

Jelly, 3 bytes

⁽¥Æ

Try it online!

Erik the Outgolfer

Posted 11 years ago

Reputation: 38 134

2

><>, 7 4 bytes

"nߞ

Try it online!

Explanation

"nߞ      : Put the string nߞ onto the stack.            Stack: [110, 2014]
 n       : Print the top item of the stack as a number. Stack: [110]
  ߞ      : Error out.

Teal pelican

Posted 11 years ago

Reputation: 1 338

Huh, this worked really well in Runic too. One byte shorter than the solution I came up with a couple weeks ago. Not sure why I didn't try that before.

– Draco18s no longer trusts SE – 6 years ago

2

05AB1E, 6 bytes (non-competing)

T·žvÍ«

Uses the CP-1252 encoding. Try it online!

Explanation:

T       # Push 10
 ·      # Multiply by 2
  žv    # Push 16
    Í   # Subtract 2
     «  # Concatenate
        # Implicit output

Oliver Ni

Posted 11 years ago

Reputation: 9 650

+1 from me. Here a 6-byte alternative: Txs4+J (Push 10; Duplicate and double copy (10,20); swap; Add 4; Join together).

– Kevin Cruijssen – 6 years ago

5-byter 'ߞÇ. Uses default ASCII encoding (so both ߞ and Ç are 2 bytes each), because ߞ doesn't exist in 05AB1E's codepage.

– Kevin Cruijssen – 6 years ago

2

Brain-Flak, 50 bytes

((((((()()()()()){}){})){}{}()){()()({}[()])}{}())

Try it online!

Brain-flak is great for restricted source challenges because there are only 8 valid character to begin with: brackets. (e.g. []{}()<>).

This was made possible with the help of @ASCII-only's integer metagolfer, which is currently hosted online at brain-flak.github.io/integer

James

Posted 11 years ago

Reputation: 54 537

1

Using the integer metagolfer in WheatWizard's brain-flak optimizer I found ((((((()()()()()){}){})){}{}()){()()({}[()])}{}()) which is 4 bytes shorter.

– 0 ' – 8 years ago

The challenge requires languages in which 0123456789 are valid tokens. Does Brain-Flak satisfy this requirement? – Dennis – 8 years ago

2

EXCEL: 148 bytes

=POWER(ROW()+ROW(),(ROW()+ROW()+ROW())*(ROW()+ROW()+ROW())+ROW()+ROW())-(POWER(ROW()+ROW(),ROW()+ROW()+ROW())*(ROW()+ROW()+ROW()+ROW())+ROW())-ROW()

only works in A1.

tuskiomi

Posted 11 years ago

Reputation: 3 113

2

Brain-Flak, 46 + 3 = 49

Try it online

(([()]([(()()())]((((({}){}){}()){}){})))()())

This one uses the -A flag for +3 bytes. It pushes the ASCII values for 2014 to the stack which outputs as 2014 in ASCII mode.

Post Rock Garf Hunter

Posted 11 years ago

Reputation: 55 382

The challenge requires languages in which 0123456789 are valid tokens. Does Brain-Flak satisfy this requirement? – Dennis – 8 years ago

2@Dennis yes @lt flags use decimal literals – Post Rock Garf Hunter – 8 years ago

2

Sinclair ZX81 15 bytes 10 bytes

 PRINT CODE "=";CODE ":"

As the ZX81 has a non-ASCII compatible character set, the character code for = is 20 and for : it is 14 - simples.

Shaun Bebbers

Posted 11 years ago

Reputation: 1 814

1You've used a 1 in your answer. – caird coinheringaahing – 8 years ago

There is no way around making a ZX81 BASIC program without using line numbers. You may take out the line number and run it in direct mode if you wish. – Shaun Bebbers – 8 years ago

This is perhaps another reason why retrocomputing @ Stack Exchange should allow one-liners and code-golf therem, but apparently this would not constitute retro computing. Or something. – Shaun Bebbers – 8 years ago

Correction on my last comment: there not therem. – Shaun Bebbers – 8 years ago

2

Lean Mean Bean Machine, 53 bytes

\\\
O))\ \
#)) o )
 ))u ))
 ))  ))
 ))  )u
 ))  ~
~~~

I like this.

Skidsdev

Posted 11 years ago

Reputation: 9 656

2

><>, 7 bytes

aa+nen;

Try it online!

aa                      +                           n                                    e                 n                                    ;
^^                      ^                           ^                                    ^                 ^                                    ^
Push 10 to stack twice, add top two items in stack, print top item in stack as a number, push 14 to stack, print top item in stack as a number, stop.

hakr14

Posted 11 years ago

Reputation: 1 295

26 bytes: eaa+n< – Jo King – 7 years ago

2

JavaScript, various solutions: 131, 44, 43, 30, 28, and 16 characters (16 bytes)

Original answer:

JS-fuck inspired JavaScript, 131 characters:

(!![]<<(!![]<<!![])<<!![]<<(!![]<<!![])<<!![]<<(!![]<<!![])<<!![]<<(!![]<<!![]))-((!![]<<!![])<<!![]<<(!![]<<!![])<<!![])-!![]-!![]

Shifty truth edition:

(true<<(true<<true)<<true<<(true<<true)<<true<<(true<<true)<<true<<(true<<true))-((true<<true)<<true<<(true<<true)<<true)-true-true

Addenda

Edit: I'm having too much fun with this... combining type coercion with hex strings, 44 characters.

a=+[];(a+'xade')-(a+'x'+(+!a+!a+!a)+a+a)
a=+[];(a+'xade')-(a+'x'+(++a+a+a)+--a+a)

a is 0, 0xade is 2782. We need to subtract 768 to get 2014. 768 is 0x300. (a+'x'+(+!a+!a+!a)+a+a) and (a+'x'+(++a+a+a)+--a+a) are two ways of producing "0x300", so the final result is "0xade" - "0x300", which JavaScript coerces back to numbers, resulting in 2014.

Here is a radix 36-based parseInt solution, 43 characters:

(a=+[]);parseInt(++a+'jy',a+++a+++''+(a+a))

First, we initiate a variable a at 0 (clearly this requires non-strict mode), increment it to 1, concatenate with 'jy' - 1jy happens to be 2014 in radix 36. The quickest way call parseInt at this radix is to generate the string "36" and abuse type coercion again: a++ + a++ results in 3, with a set to 3 as well, which means (a+a) is 6, so a+++a+++''+(a+a) results in "36", resulting in 2014.

After coming up with these two solutions I started looking at other JavaScript answers (thanks for the tip, Scrooble!), to see if combining ideas from other people gives interesting results.

Zaq's approach can be shortened with the hex string trick to 28 characters:

-~[]+!![]+[+[]]+ +(+[]+'xe')

How it works: -~[]+!![]+[+[]] results in "20", +[]+'xe' results in "0xe". +"0xe" is 14, so "20" + +"0xe" becomes "20" + 14, which becomes "2014".

Now here's a fun fact: 20 in hexadecimal is 0x14! Oh, and 14 is 0xe. So +('0x' + 0xe) produces 20. Combining this with the above results in a 30 character solution:

_=+[]+'x';+(_+ +(_+='e'))+[+_]"

Finally, initially inspired by Dan Prince's answer I came up with what might be the shortest possible JavaScript solution abusing hex-strings, at 16 characters:

+[]+'xfbc'>>!![]

0xfbc is 4028. Shift right by one, and we have 2014. If anyone knows of a shorter way to generate 0 or 1, let me know.

Edit2: having exhausted the hexadecimals, we should of course also look at binary and octal notation!

// +'0b11111011110'
+(a=+[],a+++'b'+(a+(((a+=[a]+a+a+(+[])))+a)))
// +'0o3736'
+(a=-~[],a=a+++a+++''+(a+a),+[]+'o'+((+a+1)+a))

Job

Posted 11 years ago

Reputation: 121

2Welcome to the site, and nice first post! – Khuldraeseth na'Barya – 7 years ago

Thanks. Do you know of any ways to show all answers on one page so I can quickly check for duplicates next time? ;) – Job – 7 years ago

1@Job the stack snippet in the question body lists by shortest solutions and the shortest solutions by language. I've never been able to see them on mobile/in the app, though, so your mileage may vary. – Giuseppe – 7 years ago

1

@Job You can do a search with inquestion. For just about all questions, there'll be just one page of results. The 17005 is this question's ID, found in the URL.

– Khuldraeseth na'Barya – 7 years ago

1Thanks for the tips! Added some more solutions :) – Job – 7 years ago

2

Pyt, 27 bytes

ɳąḞḞ⬠⬠⬠π⎶⁻⦋ĐąžΠ²+ĐŚřƩ½*-⁻⁻Ɩ

Try it online!

Not exactly a serious contender, just had some fun.

ɳ             push '0123456789' as string
 ą             convert to array of digits [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
  ḞḞ            for each item in array, replace with xth fibonacci # (2x) [1, 1, 2, 3, 8, 34, 377, 17711, 9227465, 225851433717]
   ⬠⬠⬠          for each item in array, replace with xth pentagonal # (3x) [1, 1, 1820, 66045, 240027425, 29321506727800, 6947548864499411875070L, 165405818231059923692911546880492501L, 898044801648686628863443901192030771814779461710865094720L, 115670237695821250427139838385782853032222541808893547195455834936957002151009052998969975100L]
       π⎶⁻           push pi, round, and decrement (2)
          ⦋         get the 2th element of that list (1820)
           Đ         Duplicate 1820
            ąž        make an array of digits and remove zeroes [1, 8, 2]
              Π        multiply together (16)
               ²+       square and add (2076)
                 ĐŚ      Duplicate and sum digits (15)
                   řƩ     make a range from 1 to 15 and sum all (120)
                     ½*    multiply by 1/2 (60)
                       -    subtract  (2016.0)
                        ⁻⁻   decrement (2x)   (2014.0)
                          Ɩ   cast to integer (2014)
implicit output

drham

Posted 11 years ago

Reputation: 515

2

Julia 0.6, 9 bytes

Int('ߞ')

Try it online!

Just for completeness' sake. Here's 2018 (same trick, different character):

Int('ߢ')

Try it online!

And just for fun, here's a function using bit shifting and arithmetic instead of using character codepoints (depends on this being Julia version 0.6, which seems an appropriately golf-y hack):

Julia 0.6, 47 bytes

(l=VERSION.minor,o=true)->o<<(l+l-o)-o<<~-l-o-o

Try it online!

Here, o=true evaluates as 1 during arithmetic. VERSION is an inbuilt constant containing the current Julia version, and VERSION.minor is 6 in this case. We left shift 1 by 6+6-1=11, giving 2048, then subtract 1<<(6-1)=32 and 1 and 1 from it, to give 2014.

2018 version would be:

(l=VERSION.minor,o=true)->o<<(l+l-o)-o<<~-l+o+o

sundar - Reinstate Monica

Posted 11 years ago

Reputation: 5 296

2

JavaScript (ES6), 52 46 bytes

t=-~'';console.log(`${++t}${t-t}${t/t}${t*t}`)

Try it online!

Will log through console.log the number 2014 as a string.

Thanks to Jacob for multiple optimizations saving 6 bytes

Explanation

t=-~'';

In JavaScript, ~~ will convert the proceeding value to a number, in this case, true equates to 1.

Set the value of t to 1 by using ~ on an empty string, which would equate to -1, then take the opposite of that number, 1.

For more info about tilde in JavaScript, see this article.

console.log(` ... `)

Logs the template string ... with ${} expressions available, where ... includes:

${++t}

Sets w to t+t, which would be 2, which would return the number 2. Added to string.

Set t to itself + 1, and display the final result, 2

${t-t}

Displays t-t, which would be 0, which would return the number 0.

${t/t}

Takes the value of t and divides by itself, returning 1.

${t*t}

Takes the value of w*w*w*w-w (or w ^ 4 - 1), where w (as previously set) is 2, and subtracts w from it, and returns the result. Added to string.

Takes the value of t*t (or t ^ 2), where t (as previously set) is 2.

The added expressions equate to 2014, which ... is in the log.

r2d2292

Posted 11 years ago

Reputation: 63

Technically you don't need the ~~ before the true – Jo King – 7 years ago

t=-~'';console.log(\++t{t-t}t/t{t*t}`)` – Jakob – 7 years ago

2

Fortran: (43 27)

print*,z'FBC'/len('hi');end

Thanks to Hristo Iliev, the above is about 40% smaller! z'FBC' returns the decimal form of that hex value (which is 4028), len returns the length of hi (i.e.,2).


Original answer:

print*,ichar(',')*ichar(',')+ichar('N');end

Converts the string , and N to ASCII values: 44 & 78 respectively: 44**2 + 78 = 1936 + 78 = 2014.

Kyle Kanos

Posted 11 years ago

Reputation: 4 270

Shorter version using hexadecimal literals: print*,z'FBC'/len('hi');end. – Hristo Iliev – 11 years ago

@HristoIliev: Totally forgot about printing hex via z! Thanks a bunch! – Kyle Kanos – 11 years ago

2

PHP (21 chars)

<?=ord('').ord(''); //These are not empty strings ;)

If you don't believe it, see the proof.

totymedli

Posted 11 years ago

Reputation: 361

1If it contains non-printables, you should provide a hex dump or list them. – mbomb007 – 9 years ago

That looks like 19 characters to me. – Joe Z. – 11 years ago

1(Oh wait, nonprintables.) – Joe Z. – 11 years ago

2

Clojure (177 characters)

In the true Lisp-ish spirit that "too many parentheses are never enough" I present:

(Integer. (clojure.string/join [(+ (second (range))  (second (range))) (first (range)) (second (range)) (+ (second (range)) (second (range)) (second (range)) (second (range)))]))

How it works:
The function range produces a lazy sequence of numbers. If no starting point and ending point are specified the range starts at zero and extends infinitely in the positive direction; however, because it's a lazy sequence the numbers are not produced until needed. Thus, applying the first function to the result of the range function without arguments produces the value 0, which is the first element in the sequence 0 to positive infinity. Applying the function second to such a range produces the value 1. From there it's a simple matter of producing enough 1's and summing them up to get 2 and 4, then converting them (implicitly) into strings to join then together, then converting the resulting string back to an integer. (I find it amusing that this is actually longer than some of the Brainf*ck answers - and to add to the horror, it's also legible :-).

Share and enjoy.

:-)

Bob Jarvis - Reinstate Monica

Posted 11 years ago

Reputation: 544

Do you need all that whitespace? – cat – 9 years ago

I suppose that you don't need to convert back to integer, instead add an output function. – Paŭlo Ebermann – 11 years ago

2

Lost, 57 23 22 bytes

<^/*(
 )/@+
">>v
^?%<<

My first Lost answer. Thought I'd start with an easy one.

Byte-count more than halved (-35 bytes) thanks to @JoKing.

Try it online or verify that it's deterministic.

General explanation about Lost:

Let me start with an explanation of Lost itself. Lost is a 2D path-walking language. Most 2D path-walking languages start at the top-left position and travel towards the right by default. Lost is unique however, in that both the start position AND starting direction it travels in is completely random. So making the program deterministic, meaning it will have the same output regardless of where it starts or travels, can be quite tricky.

A Lost program of 2 rows and 5 characters per row can have 40 possible program flows. It can start on any one of the 10 characters in the program, and it can start traveling up, down, left, or right.

In Lost you therefore want to lead everything to a starting position so it follows the designed path you want it to. In addition, you'll usually have to clean up the stack when it starts somewhere in the middle.

Program explanation:

The 22-bytes program is similar as the previous 23-bytes program below, but with a smarter path to save that byte:

v<<<<<>>>>>
>%?"^ <"*+@

Let me start with an explanation of the 23-bytes program:

The "^ <" will push the character-codepoints for the three characters in the string, being 94 32 60 respectively. The * multiplies the top two, and + adds the top two of the stack, so it becomes 94+(32*60), which results in 2014.

The @ will terminate the program, but only if the safety is 'off'. When the program starts the safety is always 'on', otherwise the program starting at the exit character immediately terminates without doing anything.
The % will turn the safety 'off'. So as soon as the % is encountered and the safety is 'off', the program can be terminated with an @.

The ? is to clean up the stack if it started somewhere in the middle.

And finally the v<<<<<>>>>>, > and use of ^ < in the string are to lead the program path towards the correct starting position for it to correctly print 2014. Note that the top line could have been v<<<<<<<<<<, but that the reversed part >>>>> will wrap-around to the other side, making the path shorter and therefore the performance slightly better. The byte-count remains the same anyway, so why not.


Now for the 22-bytes solution, and how it actually is the same as the 23-bytes solution, but with a different path.

The arrows are still used to lead the path into the given direction. The / are used as a mirror. So if we go from right to left and encounter the /, it will continue downwards; if we go from the top to the bottom and encounter the /, it will continue towards the left; etc.

The ( will pop the top value on the stack and push to to the scope, and the ) will do the reversed: it pops from the scope, and pushes it back to the stack.

So regardless of where we start and in which direction we travel, the path leads towards the first < of the bottom row. From there, the program flow travels in this order:

%?^        Direction changed upwards
" <^" <    Direction changed towards the left
(*/        Direction changed downwards
/          Direction changed towards the left
) +@

So it will:

  • Turn the safety 'off' with %;
  • Clean the stack with ?;
  • Push the character-codepoints for " <^", which are 32 60 94 respectively;
  • Pop the 94 and store it in the scope with (;
  • Multiply the 32 60 with *, resulting in 1920;
  • Push the 94 from the scope back onto the stack with );
  • Add the 1920 94 together with +, resulting in 2014;
  • And then terminates the program with @, implicitly outputting the top of the stack.

Kevin Cruijssen

Posted 11 years ago

Reputation: 67 575

1

Why not calculate the 2014 code point and skip the -A flag? 23 bytes

– Jo King – 6 years ago

@JoKing Ah, didn't thought about that.. Thanks a lot for halving the byte-count! :) – Kevin Cruijssen – 6 years ago

122 bytes. How it actually works is a bit weird... – Jo King – 6 years ago

@JoKing Oh, smart! That 23-byter was pretty obvious and I can't believe I missed it now. But that 22-byter is very smart and not something I would have thought of myself. Well done! It's only my first Lost answer, so hopefully I will get better at it. Btw, out of curiosity, is there a reason the language is lacking a divide and modulo operator? – Kevin Cruijssen – 6 years ago

shrugs Minimalism? – Jo King – 6 years ago

2

Python 51

Using true = 1 and false = 0

t=True
print str(t+t)+str(t-t)+str(+t)+str(t+t+t+t)

tasegula

Posted 11 years ago

Reputation: 141

clever. 40 chars in PHP: $t=true;echo $t+$t.$t-$t.$t.$t+$t+$t+$t; – zamnuts – 11 years ago

Damn just wrote that while reading the answers well done, – Noelkd – 11 years ago

2

C, 31 bytes -- without a multi-character literal

main(){printf("%o",'\xe'*'J');}

treamur

Posted 11 years ago

Reputation: 581

Save 3 bytes by shortening main to f, since we don't require main to be used. – MD XF – 8 years ago

2

Python, 30 chars

s=int('RZ',ord('$'));print s+s

2014 => 2 * 1007 => RZ in base 36 => ascii code for $ character

In interpreted mode, without the print statement it is 24 chars:

s=int('RZ',ord('$'));s+s

jur

Posted 11 years ago

Reputation: 171

2

Julia, 13 characters

('x'-'e')*'j'

In Julia, most arithmetic operations, when applied to a single character, convert this character to its ASCII integer value. x, e and j are respectively 120, 101 and 106, therefore (120-101)*106 is 19*106=2014.

julia> ('x'-'e')*'j'
2014

Edit: 11 characters, thanks to Glen O

A different choice of characters allows us to skip parentheses:

'.'*'.'-'f'

plannapus

Posted 11 years ago

Reputation: 8 610

Just thought I'd point out that a different sequence can save you a few characters. For instance, '.'*'.'-'f' is only 11 characters. – Glen O – 11 years ago

@GlenO thanks! I added it as an edit. – plannapus – 11 years ago

2

Bash, 29 bytes

Bash without using external programs:

echo $((x=++y+y))$?$y$((x+x))

David Yaw

Posted 11 years ago

Reputation: 931

Reduce to 25 bytes by using: echo $[y=++x+x]$?$x$[y+y]. – Isaac – 5 years ago

2

Keg, 2 bytes

ߞ

Keg auto pushes any characters that aren't instructions to the stack, and ߞ has a unicode value of 2014, which then gets printed.

Try it Online!

EdgyNerd

Posted 11 years ago

Reputation: 1 106

2

05AB1E, 22 10 8 7 6 bytes

T·žvÍJ

Try it online!

How it works:

  • T pushes 10, · doubles it, we get 20.
  • žv pushes 16, Í subtracts 2, we get 14.

Lastly, we concatenate them using J!

facepalm42

Posted 11 years ago

Reputation: 405

1

Hi, welcome to PPCG! See here for an existing 6- and 5-byte 05AB1E answer. But to golf your approach a bit more: 1. you can remove all « and only have a single J (join) at the end. 2. You could save values in between with © and use it later on with ® (i.e. žh¦¦©нžhнžh¦н®¦¦нJ). 3. There are builtins for the numbers 0, 1, and 2 if you don't change them later on, which are ¾, X, and Y respectively, so an alternative 6-byter could be Y¾XY·J (push 2; push 0; push 1; push 2 and double it; join all values on the stack together).

– Kevin Cruijssen – 5 years ago

(this last one doesn't really look like your initial approach anymore, but just stating it as example). And if you haven't seen it yet, tips for golfing in 05AB1E might be interesting to read through. :)

– Kevin Cruijssen – 5 years ago

Digits aren't allowed though. Otherwise just Ž7æ (compressed 2014) or 2014 itself would be enough. :) – Kevin Cruijssen – 5 years ago

@KevinCruijssen Oh, how silly. I forgot. – facepalm42 – 5 years ago

I've found a 10 byte solution now. I don't think there might be any room for improvement. – facepalm42 – 5 years ago

+1 from me for effort. :) PS: žz could be (256), (26), or (255). – Kevin Cruijssen – 5 years ago

Actually, I found a 8 byte solution. I changed 0 and 1 to 10 and reversed it. – facepalm42 – 5 years ago

2

~-~! (No Comment), 41

Pretty basic solution.

'=~~~~~:''=~~,','@'':@''-~~:@''-~:@''+~~:

Pretty good for just 8 unique characters, eh? xD So this could theoretically be stored in 123 bits, or ~15.4 bytes.

cjfaure

Posted 11 years ago

Reputation: 4 213

2

k [16 chars]

(*/"i"$".,")-@""
2014

Explanation

Get the ASCII value of ",.".

"i"$".,"
46 44

Find the product

*/"i"$".,"
2024

Get the data type of char.

@""
10h

On running the complete code (2024-10)

(*/"i"$".,")-@""
2014

nyi

Posted 11 years ago

Reputation: 448

212 chars: +/&" ~~~~h'"; 6 chars, 7 bytes, unicodey: \i$"ߞ"` – zgrep – 8 years ago

2

><> (9 bytes ASCII)

In pure ASCII,

'd!:'*+n;

This pushes d, !, and : to the stack, then multiplies the numerical values of top two entries, and adds the value of the last entry before outputting the value on top of the stack as a number and ending.

Using Unicode this can be reduced to 6 bytes:

'ߞ'n;

Simply outputs the numerical value of ߞ and ends.

TalkTakesTime

Posted 11 years ago

Reputation: 51

1You could shorten 'ߞ'n; to 'n;ߞ, I believe. – Addison Crump – 9 years ago

2

C#, 4 characters, 5 bytes

+'ߞ'

Note: you need LINQPad to run it, not Visual Studio. LinqPad is good for CodeGolfing in C#.

Cœur

Posted 11 years ago

Reputation: 401

1It's 4 characters, yes, but 5 bytes. – Joe Z. – 10 years ago

@JoeZ. ok, updated to reflect the number of bytes. Still way better than previous 63 and 64 bytes solutions. – Cœur – 10 years ago

2

J (13)

#.a.i.'_!!! '

Interprets the ASCII value of _!!! (95 33 33 33 32) as a binary number (it's weird that this is possible, I agree). This produces 2014.

J (15)

This one doesn't use any character strings. It's based on the weird coincidence that the sum of the first 46 primes is 4028: double 2014.

-:+/p:i.<:+:_bn

If anyone knows of a shorter way than <:+:_bn to represent 45 (preferably without strings), please let me know.

ɐɔıʇǝɥʇuʎs

Posted 11 years ago

Reputation: 4 449

2

awk (28)

There's definitely a need for an "awky" answer... ;-)

BEGIN{print++I+I--I++I++I*I}

...oookaaayyy... the last * may be a + too. But please don't call it an "awkf*ck" solution then... ;-)

BEGIN{print++I+I--I++I++I+I}

I think, I prefer the later version now because of less different characters...

(tested with gawk and mawk)

user19214

Posted 11 years ago

Reputation:

2

Insomnia, 7

Each line is one program doing the same thing: print 2014 to output stream.

e}u#Hi-
e}u#Hs-
e}u#H}-
e}g#*i-
e}g#*s-
e}g#*}-
e}gKHi-
e}gKH}-
e}gKxi-
e}gKxs-
e}gKx}-
e}u#dK-
e}u#eK-
e}u#fK-
e}gKdK-
e}gKeK-
e}gKfK-

n̴̖̋h̷͉̃a̷̭̿h̸̡̅ẗ̵̨́d̷̰̀ĥ̷̳

Posted 11 years ago

Reputation: 5 683

2

JavaScript, 24 bytes

A bit long, but no idea how this way got left out...

alert("ߞ".charCodeAt())

Explanation

The character ߞ is obtained by doing String.fromCharCode(2014) . Thus the code is actually just converting that character back to its character code and alerting it.

Thanks to hsl for this shorter version

Optimizer

Posted 11 years ago

Reputation: 25 836

That code doesn't work. Did you mean alert("ߞ".charCodeAt())? – NinjaBearMonkey – 10 years ago

@hsl String.charCodeAt is present only in Firefox, it seems. But I'll use charCodeAt since its multi browser and shorter . Thanks! – Optimizer – 10 years ago

2

Python 2 (19 bytes, ASCII only, CPython-specific)

print hash("w_'qe")

Tested only on 64-bit, but I assume/hope that since 2014 is small and positive the results would be the same on 32-bit? Originally tested on Python 3, but ProgramFOX confirms it also works on Python 2.

Python 3 (31 bytes, ASCII only)

print(ord("\N{NKO LETTER KA}"))

Quite fond of this one, even though better solutions exist. The equivalent Python 2 code is no shorter, as it required a u string prefix.

Uri Granta

Posted 11 years ago

Reputation: 2 675

1I tested on Python 2.7, and it works fine there; so you can save one character. – ProgramFOX – 10 years ago

I found the same python 3 version, but shorter (16 bytes) as I didn’t restrict myself to ASCII :print(ord('ߞ')) – Frédéric Grosshans – 9 years ago

2

CMD - 42 bytes

set/aa=f
set/a%a%xAAA-%a%xFF-%a%xFF-%a%xCE

The 'trick' is that when using the /a switch on the set command, letters (and other invalid characters) are evaluated as 0. I then just use hexadecimal to evaluate 2014. The 0 is needed because in CMD hexadecimal must be expressed with the leading 0x. There is almost definitely a shorter way to get to 2014...

%a%xAAA - %a%xFF - %a%xFF - %a%xCE = 2730 - 255 - 255 - 206 = 2014

unclemeat

Posted 11 years ago

Reputation: 2 302

2

Python (30 chars)

(10 + 9) * 106 = 2014

(ord('\t')+ord('\n'))*ord('j')

Brobin

Posted 11 years ago

Reputation: 201

2

Hassium, 77 Bytes

Really excited about this one. It gets Math.pi and divides it by itself in variable a (1), then uses increment and basic math operators to get it to 2014.

use Math;func main(){a=Math.pi;a/=a;print(++a)print(a-a)print(a/a)print(a*a)}

Run online and see expanded here

Jacob Misirian

Posted 11 years ago

Reputation: 737

2

Milky Way 1.0.0, 22 bytes

<^a:::+;:l+:>h<::++-<-

Explanation

<          <     <   # rotate the stack leftward
 ^                   # pop the TOS without outputting
  a                  # logical not on the TOS
   :::  :   ::       # duplicate the TOS
      +       ++     # push the sum the top two stack elements
       ;             # swap the top two stack elements
         >           # rotate the stack rightward
          h          # push the TOS to the power of the second stack element
                - -  # push the difference of the top two stack elements

The stack defaults to ["", 0].


Stack Visualization

["", 0]                # default stack

[0, ""]                # <
[0]                    # ^
[1]                    # a
[1, 1, 1, 1]           # :::
[1, 1, 2]              # +
[1, 2, 1]              # ;
[1, 2, 1, 1]           # :
[1, 2, 1, 10]          # l
[1, 2, 11]             # +
[1, 2, 11, 11]         # :
[11, 1, 2, 11]         # >
[11, 1, 2048]          # h
[1, 2048, 11]          # <
[1, 2048, 11, 11, 11]  # ::
[1, 2048, 33]          # ++
[1, 2015]              # -
[2015, 1]              # <
[2014]                 # -

By default, if nothing has been output manually, the bottom stack item is output on termination of the program.


Milky Way (current version), 8 bytes

XZ*W+U+!

Explanation

X         # push 20 to the stack
 Z        # push 100 to the stack
  *       # push the product of the TOS and STOS
   W      # push 10 to the stack
    + +   # push the sum of the TOS and STOS
     U    # push 4 to the stack
       !  # output the TOS

Zach Gates

Posted 11 years ago

Reputation: 6 152

2

Jolf, 3 bytes

(It's almost 2016. Language obviously postdates question.)

@ߞ
@  Get charcode of next character
 ߞ charcode 2014

Conor O'Brien

Posted 11 years ago

Reputation: 36 228

2

JavaScript, 9 bytes

btoa`ÛMx`

This Base-64 encodes ÛMx to make 2014.

ericw31415

Posted 11 years ago

Reputation: 2 229

2

Lua, 32 bytes

print(#'XX'..#''..#'X'..#'XXXX')

This makes use of the length operator # used on string literals to get numbers, and the lengths are concatenated (with ..) to print 2014

PiGuy

Posted 11 years ago

Reputation: 401

2

Fourier, 12 bytes

Non-competing: Fourier is newer than the challenge

I know I'm two years too late, but it seemed like a fun challenge to do in Fourier.

^^ovvo^o^^^o

The command ^ increments the value of the accumulator (which starts at zero) and v decrements the value of the accumulator.

Try it online!

Beta Decay

Posted 11 years ago

Reputation: 21 478

1

Vim 8.0, 15 bytes

:h u
ggf:wywZZp

I didn't see a vim answer yet, so I figured I'd add one. This opens up a helpfile, so it is specifically vim 8.0, since it might not work with a future version that updates that file.

James

Posted 11 years ago

Reputation: 54 537

Clever! In my case :h followed by 9wywZZp works. So down to 10 symbols/bytes – defhlt – 8 years ago

@defhlt OK, good to know! Although technically that doesn't work because it uses the digit 9. You could do f:w in place of 9w for only one byte more. Which version of vim do you have? – James – 8 years ago

Also, !!date +\%Y is 12 symbols (assuming you are reading this from 2014) – defhlt – 8 years ago

You are totally right! I use nvim 0.1.6-dev. – defhlt – 8 years ago

1

JavaScript, 81 76 bytes

l="length";alert(("hi"[l]<<"javascript"[l])-"wow"[l]*"hello death"[l]-true);

Hristiyan Dodov

Posted 11 years ago

Reputation: 191

1

C, 24

(Using GCC-4.9.2)

f(){printf("%i",'Þ');}         (Properly formatted version on Pastebin)


IMPORTANT NOTE: There is a U+0007 in-front of the Þ character but stackexchange removes it for some reason. Make sure you edit it back in before compiling my code. Here is a pastebin of the code that does include the unicode characters needed.

Albert Renshaw

Posted 11 years ago

Reputation: 2 955

1

SmileBASIC, 10 bytes

?&HFBC>>!.

&HFBC is hexadecimal for 2014*2, which is right shifted by not(0.0)

?ASC("ߞ") looks shorter, but it's actually the same length when saved in UTF-8, and about 100000x more boring.

12Me21

Posted 11 years ago

Reputation: 6 110

1

√ å ı ¥ ® Ï Ø ¿, 8 bytes

TTX''_o

Try it online!

The rest of the code in the TIO link is the Python interpreter (because I can't be bothered to ask Dennis to add √ å ı ¥ ® Ï Ø ¿

caird coinheringaahing

Posted 11 years ago

Reputation: 13 702

1

Braingolf, 3 bytes

Try it online!

The ordinal of ߞ is 2014, # pushes the ordinal of the next character to the stack, and Braingolf implicitly outputs the last item on the stack.

Skidsdev

Posted 11 years ago

Reputation: 9 656

Braingolf is your language, right? – MD XF – 8 years ago

@MDXF Indeed it is – Skidsdev – 8 years ago

1

Charcoal, 5 bytes

I²⁰¹⁴

Try it online!

Language was created after January 1, 2014, but as Charcoal uses the superindices ⁰¹²³⁴⁵⁶⁷⁸⁹ to represent the numbers, the answer is valid. :-)

Charlie

Posted 11 years ago

Reputation: 11 448

1

Lua, 29 bytes

b=("").byte print(b"?"..b"?")

NB: the two question marks are substitutes for characters that are not appearing properly in the post. See the tio link below for proof.

Try it online!

As an interesting point, although this is not the case with Lua, a language with an implementation of pi to at least 3137 digits would be able to print pi and find '2014' at digits 3133-3136!

MCAdventure10

Posted 11 years ago

Reputation: 103

1

J, 21 bytes

,":,.$,:~}.,:,:'golf'

Try it online!

               'golf'  One dimensional array
           ,:,:        Itemize twice (1x1x4 array)
         }.            Drop first element (0x1x4)
      ,:~              Append to itself as distinct items (2x0x1x4)
     $                 Get dimensions (2 0 1 4)
   ,.                  Flatten items, essentially prints 2014 vertically.
                       (so there are no spaces)
,":                    To strings, flatten.    

20 bytes

#.(#_),,~(,~,~#_),%_
#.(#_),,~(,~$,._),%_

15 bytes

do'bbbc',~":_bd

11 bytes

,":_bk,:_be

FrownyFrog

Posted 11 years ago

Reputation: 3 112

1

Python, 41 bytes

print(int(ord("j")/len("aa") * ord("&")))

Try it online!

John

Posted 11 years ago

Reputation: 11

2Welcome to the site! The aim of this question (and code golf in general) is to get the shortest functional code. You can remove the spaces around the * to start with. – caird coinheringaahing – 7 years ago

1

Pyt, 9 bytes

π!⬡⁻⁻⁻△⁻⁻

Try it online!

FantaC

Posted 11 years ago

Reputation: 1 425

1

LibreLogo (Paper Format: Tabloid), 55 bytes

The document must be in Tabloid Format for this method to work.

Code:

print ''.join(set(str(pagesize.pop()))).replace('.','')

Result:

enter image description here

Explanation:

pagesize                                           ; Returns [792.0, 1224.0] (Tabloid Format)
pagesize.pop()                                     ; Returns 1224.0
str(pagesize.pop())                                ; Returns "1224.0"
set(str(pagesize.pop()))                           ; Returns {u'2', u'0', u'1', u'.', u'4'}
''.join(set(str(pagesize.pop())))                  ; Returns "201.4"
''.join(set(str(pagesize.pop()))).replace('.','')  ; Returns "2014"

Grant Miller

Posted 11 years ago

Reputation: 706

1

Canvas, 7 bytes

AA+q⁷┤t

Try it online!

AA       | Push 10 to stack twice
   +      | Add top two items in stack
    q     | Print top item in stack on current line
      ⁷    | Push 16 to stack
       ┤   | Decrement top item in stack twice
        t | Print top item in stack on current line, disable implicit output

hakr14

Posted 11 years ago

Reputation: 1 295

1

Perl 5 + Perligata, 25 bytes

Byte count uses the new rule that command-line switches for choosing appropriate modules don't count.

perl -MLingua::Romana::Perligata -e'MMXIVimum egresso scribe.'

Tested in Strawberry 5.26.0 with Perligata 0.601 (with " instead of ' in the above code).

msh210

Posted 11 years ago

Reputation: 3 094

1

jshell, 5 bytes

How to make Java an useful code golf language? Simple, just remove the need to declare classes, methods, make things automatically print and so on.

+'ߞ'

Konrad Borowski

Posted 11 years ago

Reputation: 11 185

1

Stax, 4 bytes

ü◘♥┐

Run and debug (ha) it online!

Obligatory Stax answer. This unpacks to 2014. Implicit print.

I haven't yet found a shorter version.

Khuldraeseth na'Barya

Posted 11 years ago

Reputation: 2 608

1

C# (.NET Core), 42 bytes

System.Console.Write((int)'ϯ'+(int)'ϯ');

// Btw. it's now 2018 ^^ so
System.Console.Write((int)'ϱ' + (int)'ϱ');

Try it online!

Hille

Posted 11 years ago

Reputation: 349

1

CJam, 2 bytes

KE

K is predefined as 20, E is predefined as 14. The stack gets automatically printed after the program.

Try it online!

lolad

Posted 11 years ago

Reputation: 754

1

ANSI C - 95 47 52 characters

#include <stdio.h>
main() { printf("%i", (('a' + 'a')/'a') * ('\a' + '\f') * ('<' - '\a') ); }

This program uses characters to initialise integers and multiplies: 2 * 19 * 53.

#include main(){printf("%i",'\aÞ');}

This program initialises an integer using charaterbytes and prints it. '\aÞ' is the bitpattern 00000111 11011110 this is also the bitpattern of 2014.


Disclaimer: this was made on a windows system with visual studio. This code depends on a lot of things, including - How your compiler endodes the characters you input. Þ has an ascii value of 222 (or its negative equivalent), this may vary depending on your system. The notation int a = 'abcd'; is in itself evil and depends on how memory is handled on your system - this includes endian issues. int a = '\0A'; a is 65 on my system but may be 16640 on your system.

main(){printf("%i",('C'-'A')*('T'-'A')*('v'-'A'));}

I went back to Version one and multiplied 2 * 19 * 53. This version uses only one byte at a time so it is endian compatible. Also it uses only characters in the range of [0 - 127] to be compatible to all systems.

Johannes

Posted 11 years ago

Reputation: 199

You don't actually need to include stdio.h, most compilers will give a warning but include it for you. – nyuszika7h – 11 years ago

This code yields 7 for me with tcc and 508830 with gcc. clang gives an error: character too large for enclosing character literal type. – nyuszika7h – 11 years ago

@nyuszika7h ... 7 is equivalent with \a - this could be a problem with passing to the printf function, it would be interesting for me to see if int a = '\aÞ' is 2014 using tcc. 508830 looks very strange to me - i would guess some endian thing but n * 256 + 7 can never be that number. So this illuminates how string this code depends on the system. – Johannes – 11 years ago

1

Racket: 20 (19 chars)

(char->integer #\ߞ)

ߞ is a unicode character that has 2014 as it's code.

This abuses the fact that every top level form gets its evaluation printed to stdout. This is quite unique amongst LISPs which usualy only have this behaviour in the REPL and not when running programs.

Scheme: 29 bytes (28 chars)

(display(char->integer #\ߞ))

Sylwester

Posted 11 years ago

Reputation: 3 678

So 29 bytes, then? – Joe Z. – 11 years ago

1@JoeZ. Yes. I was just about to update it :) – Sylwester – 11 years ago

At least in Racket, you don’t need to call display — the REPL will print the result of char->integer automatically — which would save you another 9 chars. – Matthew Butterick – 10 years ago

@MatthewButterick Unlike Scheme and CL #!racket actually display every top level result to stdout even when running a compiled program. It's quite annoying but I can abuse that. thanks :) – Sylwester – 10 years ago

Still beat it, I’m afraid – Matthew Butterick – 10 years ago

1

maybe not the shortest, but one of the more readable ones in Smalltalk:

Transcript show: Date today year.

Joachim Tuchel

Posted 11 years ago

Reputation: 131

This doesn't work.. (lol) – Albert Renshaw – 8 years ago

6

see the comments. You can't use current Year.

– Wasi – 11 years ago

1

Solution 1

Octave/Matlab (55 chars)

a=pi;b=a*a;disp(ceil(a^a^a/a/a/a-b*b*a-a^a*b+b*b-b-b));

Solution 2

PHP (9 chars without tags, 12 with them Actually 2022 because of the new lines involved)

<!--Comment
  previous
  2013 lines -->
<?=__LINE__; <!-- This should be on line 2014 -->

Vereos

Posted 11 years ago

Reputation: 4 079

That would be 2013 newlines followed by <?=__LINE__ for 2024 chars, not 9. – Peter Taylor – 11 years ago

@PeterTaylor I didn't write 9 chars to win the challenge (since there are lots of shortest answers!), but because the actual code is that <?=__LINE__;?>, which I thought would be funny :) Nvm, I'll edit that. – Vereos – 11 years ago

If it doesn't work without the newlines, they're part of the "actual code". – Peter Taylor – 11 years ago

I guess you're right, edited. – Vereos – 11 years ago

1In PHP, you can skip ?> at end of the program. But interesting idea with __LINE__, even if it's ridiculous for such huge number. – Konrad Borowski – 11 years ago

1

Game Maker Language, 22

show_message(ord("ߞ"))

Timtech

Posted 11 years ago

Reputation: 12 038

1

C - 44 characters (85 with headers)

What, no one is abusing strings yet?

#include<stdio.h>
#include<netinet/in.h>
main(){printf("%u",ntohs(*(int*)"\a\xde"));}

Interestingly, this is a special case where neither character is printable, but their special code doesn't involve a number.

If we want no warnings, it needs to become 55 (96) characters:

#include<stdio.h>
#include<netinet/in.h>
int main(){return!printf("%u",ntohs(*(int*)"\a\xde"));}

Brendan Long

Posted 11 years ago

Reputation: 111

1

Python, 14 characters

print ord('ߞ')

Short way ;)

mroman

Posted 11 years ago

Reputation: 1 382

Does it work without the u before the string? – Joe Z. – 11 years ago

TypeError: ord() expected a character, but string of length 2 found – boothby – 11 years ago

1@JoeZ. this is valid Python 3 – Peter Gibson – 11 years ago

2In Python 3: SyntaxError: invalid syntax (Python 3 needs brackets around stuff being printed). – Joe Z. – 11 years ago

1

C/C++ 39

main(){printf("%d%d",':'-'&',':'-',');}

ASCII for: ':' = 58, '&' = 38, ',' = 44. Using that, 58-38 = 20 and 58-44 = 14.

tasegula

Posted 11 years ago

Reputation: 141

1

120 characters in Squeak Smalltalk trunk (4.5).
I did not search the shortest, but kind of graphical solution:

((Text string:'Happy\New year'withCRs attribute:TextEmphasis narrow)asMorph borderWidth:Float one+Float one)bounds area

It depends on font, margins, and so is quite fragile, but at least for me it worked.
In Squeak 4.4, it works with lowercase 'happy\new year'.

aka.nice

Posted 11 years ago

Reputation: 411

1

C#, 28 bytes

You don't need to cast to an int as Hille does, so it becomes

Console.WriteLine('ϱ'+'ϱ')

Teun

Posted 11 years ago

Reputation: 11

1

JavaScript, 49 Chars

A mathematical JavaScript version making use of only PI and E as source numbers.

(m=Math).pow(e=m.E,e*(p=~~m.PI))/m.sqrt(p)+e+e|""

... mmmm PIE.

Oh and just in case implicit returns are vetoed (56 Chars with alert):

alert((m=Math).pow(e=m.E,e*(p=~~m.PI))/m.sqrt(p)+e+e|"")

Pebbl

Posted 11 years ago

Reputation: 151

1

Symbolic Python, 31 bytes

_=-~-~-~(_==_)
_=`""`[_::_]

Try it online!

Symbolic Python bans numbers anyway.

Explanation:

_=-~-~-~(_==_)   # Set _ to 4
_=               # Set _ to
  `""`         # From the representation of some unprintables 
                    # Which is '\x12\x10\x11\x14'
           [_::_]   # From the 4th character, take every 4th character
                    # Output the contents of _ implicitly

A more interesting solution at 34 bytes:

_=-~(_==_)
_=`_`+`_-_`+`_/_`+`_*_`

Try it online!

_=-~(_==_)               # Set _ to 2
_=`_`+`_-_`+`_/_`+`_*_`
# '2'+'2-2'+'2/2'+'2*2' = '2'+'0'+'1'+'4' = '2014'

Jo King

Posted 11 years ago

Reputation: 38 234

Crazy that someone else is actually using this stupid language I made, haha – FlipTack – 6 years ago

1

C++ - 63 bytes

I'm not sure if this method has been used, but I designed this myself anyway:

#include<iostream>
int main(){std::cout<<int('&'*(','+'\t'));}

user10766

Posted 11 years ago

Reputation:

You can use int instead of toascii for all of those to save a lot of characters. – Joe Z. – 11 years ago

@JoeZ. OK, I didn't think of that. How can I calculate the bytes? – None – 11 years ago

Save your program as a text file, and then view how many bytes it is in the file manager. – Joe Z. – 11 years ago

2 is not allowed. – Danko Durbić – 11 years ago

Oops, I'll fix that. – None – 11 years ago

@DankoDurbić Fixed. – None – 11 years ago

I only count 62 bytes (using http://www.charactercountonline.com/). Also, can \t be replaced with the literal tab character?

– Justin – 11 years ago

@Quincunx Literal tab character? – None – 11 years ago

@hosch250 is that not what \t stands for? (tab. #9 in ascii: http://www.asciitable.com/)

– Justin – 11 years ago

@Quincunx Yes, I can use plain 9. However, I can have no numbers in my source code, so I cannot use 9 instead. TAB does not work. – None – 11 years ago

1

Clojure - 22

(apply *(map int"j#"))

(note: the # is ASCII character 19, Stack Overflow doesn't seem to like this but it's valid Clojure source...)

Clojure - 36

(dec(reduce +(nnext(range(int\@)))))

mikera

Posted 11 years ago

Reputation: 1 233

1

vba (immediate window), 38 26 13

using regular ascii characters (no funny typing needed)

?&ha+&ha&&&he

26

?val("&hfbc")/-(true+true)

38

?year((cdbl(asc("ê"))*cdbl(asc("²"))))

find a date that can be represented as a number, and select the year from that (in this case, Jan, 13, 2014)

have to use cdbl, as it assumes signed int, and overflows

SeanC

Posted 11 years ago

Reputation: 1 117

How do you write that in the Immediate window? (I assume that is what you mean by “direct window”.) If I copy-paste it I get “?year((cdbl(asc("e^"))*cdbl(asc("^(2)"))))”. (Copy-pasting “ê” and “²” from charmap.exe results “?” both.) And of course, that way the calculation not gives 2014. – manatwork – 11 years ago

I used ?chr(234),chr(178) to get the characters, or you can hold down the ALT key and type 234 (and 178) and release the ALT to get each character – SeanC – 11 years ago

With Alt+234 I get “r”, with Alt+178 I get “¦”. Of course, it works with the chr() function. Anyway, nice trick to use year() this way. – manatwork – 11 years ago

ok.. I was thinking back to DOS days - now it's 0234 and 0178, but I found another shorter way now – SeanC – 11 years ago

Thanks, it works this way. Although here appears “ȩ” and “¸”, the calculation is correct. – manatwork – 11 years ago

1

Clojure, no unicode tricks (49 characters/bytes)

Uses the fact that * called with no args evaluates to 1:

(let[b(inc(*))j(+(* b b b)b)](+(* b j j j)j b b))

Using the same trick and doing string concatenation instead of arithmetic, the lowest I could get was 51 chars:

(let[n(*)t(+ n n)z(+)f(+ t t)](print(str t z n f)))

OpenSauce

Posted 11 years ago

Reputation: 153

1

Ruby 1.9, 10 bytes 

p 'ߞ'.ord

Timtech

Posted 11 years ago

Reputation: 12 038

These are 8 bytes in UTF8. – schmijos – 8 years ago

nice! 7 chars if you are in the irb command prompt 'ߞ'.ord – Eduard Florinescu – 11 years ago

@EduardFlorinescu Thanks, I know. – Timtech – 11 years ago

1

Python, 23

print ord("<DC3>")*ord("j")

<DC3> should be replaced with ASCII symbol 19 (device control 3).

flornquake

Posted 11 years ago

Reputation: 1 467

1

SAS, 34 characters/bytes

data a;x=put(' ',hex.);put x;run;

That puts it to the log, it's 6 longer if you need it to the output window. Note I'm not seeing the second character there; it is backwards-P, which is hex 14.

There should be a shorter solution with %sysfunc(putc(..., but I can't get that to work properly.

Joe

Posted 11 years ago

Reputation: 283

1

Edited: bash 81 chars!

Just for fun:

wc -c < <(echo {,}{,,}{,}{,,,}{,}{,,,}film dbugjkqstvxz{,}{,,} 'Happy New Year!')

there is no numbers, all letters are used and this print exactly:

2014

( This method could reasonably be used until 2016: by just adding one or two exclamation point after the wish:

   wc -c < <(echo {,}{,,}{,}{,,,}{,}{,,,}film dbugjkqstvxz{,}{,,} 'Happy New Year!!')
   2015

;-)

bash 27 chars

.;v=$?;echo $v$?${#v}$[v+v]

This will output:

bash: .: filename argument required
.: usage: . filename [arguments]
2014

Ok, this will generate some unwanted output, but 2014 is printed and is a valid token!

The two following sample are error free (a little longer but near golfed)

v=$(echo {V..v});echo $[${#v}#vu]
2014

or

printf -vv "%d" $?xfbc;echo $[v>>${#?}]
2014

or even:

echo $[$[$[${#?}$?-${#?}]$?>>${#?}]#Iy]
2014

Inspired by comment from GammaFunction:

echo $[$[a-a]xfbd>>${#?}]

F. Hauri

Posted 11 years ago

Reputation: 2 654

You don't need to set a var in the 0xfbc solution: echo $[$?xfbc>>++j] works just fine (19 bytes). – GammaFunction – 6 years ago

Nice! Late to post but you could! Unfortunely you have to ensure $? to be 0 and this could not be reused... But impressive! – F. Hauri – 6 years ago

1@GammaFunction Post edited ;-) – F. Hauri – 6 years ago

1

@, 9 chars

-Σ*{~~}82

Explanation (syntactically invalid)

-       2  Subtract the result by 2(2014)
 Σ         Summation of all ASCII codes in the string(2016)
  *    8   Duplicate the string 8 times
   {~~}    Define the string "~~"

There is no Try It Online for @.

If the current year is 2016, it would be perfect(7 chars):

Σ*{~~}8

user85052

Posted 11 years ago

Reputation:

1

Python 3, 16 bytes (15 characters)

print(ord('ߞ'))

Try it online!

Explanation

ord returns the decimal Unicode of a character, and the decimal Unicode of ߞ happens to be 2014.

Python 2?

I tried doing the same thing in Python 2 (print ord('ߞ')), which would be 1 byte less, but this doesn't work. Why? Well, in Python 3, len('ߞ') returns 1. However, in Python 2, len('ߞ') returns 2. And since ord only takes a string of length 1 (or a char, but Python doesn't have chars), Python 2 doesn't really like that: TypeError: ord() expected a character, but string of length 2 found

Sagittarius

Posted 11 years ago

Reputation: 169

1

C#, 25 bytes (24 characters)

Console.Write((int)'ߞ');

Try it online!

Explanation

The decimal Unicode of ߞ is 2014, so you can just cast it to an int and 2014 is printed.

Sagittarius

Posted 11 years ago

Reputation: 169

1Welcome! Though admittedly, the answer is simple, in general it is best to add an explanation or link to an online interpreter. Code-only answers are usually automatically flagged as low-quality, meaning that those answers have to be reviewed by someone. – mbomb007 – 5 years ago

@mbomb007 yeah i was thinking about adding a link to tio.run, i'll do that – Sagittarius – 5 years ago

1

Javascript, 45 characters

_=> new Date().getFullYear()-new Date().getDate()

Very Temporary!!

Another Day, another very Temporary answer :-)

f=new Date().getFullYear()-new Date().getDay()

rew

Posted 11 years ago

Reputation: 21

Welcome to Code Golf! Submissions should be either a full program or a function, so I would recommend prepending _=> to your solution to turn it into an anonymous function. – Stephen – 5 years ago

1

Wren, 27 bytes

Just like most other answers, convert to code points and print. However this uses control characters in the source code.

System.printAll("".bytes)

Try it online!

Explanation

                ""        // An unprintable chain containing 0x14 (20 in decimal) and 0x0e (14 in decimal)
                  .bytes  // Convert them to a list of their decimal codes [20, 14]
System.printAll(        ) // Print them all without a separator (2014)

user85052

Posted 11 years ago

Reputation:

1

W j, 4 bytes

ë‘"C

Explanation

ë‘"  % Push a list
   C % Convert to list of ord codes [20,14]

flag:j % Join without a separator
```

user85052

Posted 11 years ago

Reputation:

1

Spice, 145 97 bytes

Improvement using multiplication to get the 9 from 2*2*2+1, as we already had those values.

;t;z;o;n;i@LEN i z;ADD i i i;LEN i o;PUT i i i;LEN i t;MUL t t i;MUL t i i;ADD o i n;OUT t z o n;

Un-golfed explanation

;t;z;o;n;i@ - Declare vars
LEN i z;    - Get the length of [], 0, and store in z
ADD i i i;  - Adding implicitly uses the first element, or 0 if there is none, so we insert 0 into i
LEN i o;    - Store length of [0], 1, in o
PUT i i i;  - Insert 0th element of i into i at position i[0] (we're increasing the array size)
LEN i t;    - Store length of [0, 0], 2, into t
MUL t t i;  - Multiply t, 2, by itself and store in i
MUL t i i;  - Multiply t, 2, by i, 4, and store in i
ADD o i n;  - Add o, 1, to i, 8 and store in n
OUT t z o n;- Write to console - "[2] [0] [1] [9]"

Original

;t;z;o;n;i@LEN i z;ADD i i i;LEN i o;PUT i i i;LEN i t;PUT i i i;PUT i i i;PUT i i i;PUT i i i;PUT i i i;PUT i i i;PUT i i i;LEN i n;OUT t z o n;

Un-golfed explanation

In Spice, all variables are double arrays. Importantly, variables that have no assigned value are either treated as an empty list [] or 0 depending on the operation. The built-in LEN will give the length of an array and we can therefore produce numbers:

;t;z;o;n;i@ - Declare vars
LEN i z;    - Get the length of [], 0, and store in z
ADD i i i;  - Adding implicitly uses the first element, or 0 if there is none, so we insert 0 into i
LEN i o;    - Store length of [0], 1, in o
PUT i i i;  - Insert 0th element of i into i at position i[0] (we're increasing the array size)
LEN i t;    - Store length of [0, 0], 2, into t
PUT i i i;  - Now repeat until there are 9 elements...
PUT i i i;
PUT i i i;
PUT i i i;
PUT i i i;
PUT i i i;
PUT i i i;
LEN i n;     - ... and store in n
OUT t z o n; - Write to console - "[2] [0] [1] [9]"

For the original 2014 version, you save bytes for less PUTs - 95 bytes. So this solution will improve next year!

Slord6

Posted 11 years ago

Reputation: 71

1

Python, 52 49 chars

from math import*
print(int((e*pi+e)**pi+e/e+e))

Works in Python 2 and Python 3.

cdlane

Posted 11 years ago

Reputation: 351

1

JavaScript 45

alert(parseInt('bbc','twentyonefour'.length))

wolfhammer

Posted 11 years ago

Reputation: 1 219

1

Bash - 10 (or 8)

Well there have been a couple of answers that have been disqualified because they rely on the year. When golfing, one side goal is to see how close we can get to breaking the rules as currently written without breaking the letter of the rules (I include the clarifications by Joe Z in the 66 existing comments on the rules). The question very specifically states that I can not depend on 2014 being the current year. I instead rely on it being 8:14pm in my timezone.

date +%H%M 

When I ran it, it output 2014 exactly, thus it satisfies it No, it has to be 2014 exactly. comment. (Due to context people seem to misread it as ... 2014 always, but that was not what was written, even if that were perhaps what was intended.) This lets me beat the current Bash record, at least until this loophole is closed. This interpretation may seem too cheaty since all the existing popular answers assume that the rules really meant always. Indeed some of them exploit this and export something that isn't exactly 2014, but instead contains 2014. I am fine with that interpretation too since Bash can do:

cat /*/*

This is a mere 8 characters, which will concatenates a bunch of files including /dev/urandom/, and it generally takes my machine under a minute to find 2014 in /dev/urandom. Although my rule twisting golfing code of honour won't let me pick this solution since it violates the letter of Joe Z's clarification, the only objection Joe Z raised to the random approach in the 66 comments was that it was too long. At 8 characters this answer is actually shorter than my rules-lawyer answer.

gmatht

Posted 11 years ago

Reputation: 676

1Normally entries that explore edge cases are popular. This is the only answer they obeys the letter of the rules that is down voted (all other down voted answers rely on year=2014). Anyone care to comment on what rubs them wrong about this answer? – gmatht – 11 years ago

It follows the letter of the rules in a way that's almost universally considered boring and unoriginal. Additionally, it was posted almost three months after the original problem, meaning that it's way back on the 4th page where barely anybody will see it, let alone vote it up. – Joe Z. – 11 years ago

For that matter, I've edited the question again to make my intentions for the problem even clearer. Is "independently of any external variables" good enough? Even then, this answer isn't the shortest in either category, so I still won't accept it. – Joe Z. – 11 years ago

Thanks. For the record, when I commented above this answer had been voted down to -2, so the context was more "would someone like to comment on why they are voting it down?" rather than "why isn't it upvoted?". It also wasn't intended as a criticism of Joe Z's question specification. – gmatht – 11 years ago

1

Python, 55 bytes (no math import and no char or unicode trickery!)

x=False;a=x**x;b=a+a;c=b+b;print c**c*(c+c)-b**(c+a)-b

Uses the fact that zero to the zeroth power is defined as one and False can be implicitly casted to 0. Hence a, b and c will contain 1, 2 and 4 respectively.

Arne

Posted 11 years ago

Reputation: 121

Arne, True implicitly casts to 1, so you can start with a=True and save 8 characters. Also, please specify Python 2. – isaacg – 11 years ago

1

Marbelous 14

CB
CE
CF
CD
~~

How it works

the first 4 lines are language literals, in hexadecimal. Their values are 203, 206, 207 and 205. They will fall down by one cell on each tick. If you perform an 8-bit binary not on those values (which is exactly what ~~ does) you get the following values: 52, 49, 48 and 50. These values happen to be the ascii values of 4, 1, 0 and 2 respectively. The literals then fall off the board which causes their corresponding ascii character to be printed to STDOUT.

overactor

Posted 11 years ago

Reputation: 3 500

1

C, 27 Bytes

main(){printf("%d",'\aÞ');}

Just a reminder that multi-character constants do exist :)

Alternatively, three bytes more:

main(){printf("%x",' i'-'U');}

Gerwin

Posted 11 years ago

Reputation: 126

main is not needed, you can shorten it to f and save 3 bytes, it'll still be a valid submission. – MD XF – 8 years ago

>

  • int is not needed. 2. return doesn't print anything.
  • < – Dennis – 10 years ago

    start="3">

  • '^GÞ' (character codes 7 and 222) would require only one multi-character constant.
  • < – Dennis – 10 years ago

    My compiler does not agree :( – Gerwin – 10 years ago

    That's odd. 7 * 256 + 222 = 2014, so it should work. What do you get? – Dennis – 10 years ago

    6178782, it seems like my compiler thinks of ^ as a separate character. – Gerwin – 10 years ago

    No, ^G is caret notation for BEL character; it's a single character with char code 7. You have to type the unprintable character somehow, depending on your OS and editor. – Dennis – 10 years ago

    My compiler tells me it's '\aÞ'. Thanks anyway. – Gerwin – 10 years ago

    1

    Lua - 30 bytes

    b=#" "print(b..b-b..b/b..b+b)

    # is the length operator, so b = 2.

    Seeker14491

    Posted 11 years ago

    Reputation: 81

    1Would b/b work? – Lynn – 10 years ago

    @nooodl Good suggestion; indeed b/b can replace b-#" " and save 3 characters. – Seeker14491 – 10 years ago

    1

    (Java, 553 bytes as .class, 112 bytes as it stands, 84 bytes after renaming the class to 'm' and removing whitespace.)

    This probably isn't the kind of answer you're looking for, but there are a bunch of strings that share a hashcode of 2014.

    public class make2014 {
        public static void main(String[] args){
            System.out.println("={".hashCode());
        }
    }
    

    John P

    Posted 11 years ago

    Reputation: 401

    1Consider adding the language name (Java, I assume) and byte count like the other answers do. – NinjaBearMonkey – 10 years ago

    Thanks, I forgot to do that. I didn't think my file size would matter much - the minimum file size of a .class is far greater than most of the attempts here. – John P – 10 years ago

    I got the .java down to 84 bytes without changing functionality. I see other people shaved off 9 bytes by printing special characters to produce 2014 instead of using hashcodes... I kind of thought it would be cheating to do it like that, since you're really printing 2014 as a number in a different format. Oh well. – John P – 10 years ago

    1

    Xojo, 27 chars (all ASCII)

    MsgBox Str(&hFBC/(&hC-&hA))
    

    silverpie

    Posted 11 years ago

    Reputation: 139

    1

    TinyMUSH, 16

    We need more MUD language entries.

    \encrypt($"#&,.)
    

    Muqo

    Posted 11 years ago

    Reputation: 499

    1

    C++ 30

    main(){cout<<('&')*(']'-'(');}
    

    bacchusbeale

    Posted 11 years ago

    Reputation: 1 235

    Why do you need the brackets around '&'? Does main(){cout<<'&'*(']'-'(');} not work? – Joe Z. – 10 years ago

    1

    x86 machine code, 19 bytes

    B8 3A 0E 2C 08 CD 10 2C 02 CD 10 04 01 CD 10 04 04 CD 10

    Assembly code equivalent:

    mov ax, 0E3Ah; ah = 0Eh (bios teletype), al = 3Ah (ascii semicolon)
    sub al, 08h; ascii 2
    int 10h
    
    sub al, 02h; ascii 0
    int 10h
    
    add al, 01h; ascii 1
    int 10h
    
    add al, 04h; ascii 5
    int 10h
    

    Yeah, I know: it logs 2015 rather than 2014.

    But seeing that this challenge is old and now the year is 2015, it seemed more appropriate to use the current year (it's my excuse for not "going home" :) )

    Note: This was tested using DOSBOX

    SirPython

    Posted 11 years ago

    Reputation: 178

    1You have numbers in your source. – Elliot A. – 9 years ago

    @ElliotA. Read the challenge: "without using any of the characters 0123456789"; numbers = characters representing numbers. – SirPython – 9 years ago

    1

    JavaScript (19)

    Obvious cheating, but these expression ran in REPL print strings "2014" and "2015":

    ''+'ߞ'.charCodeAt() // 2014
    ''+'ߟ'.charCodeAt() //2015
    

    TIL: .charCodeAt implicitly converts it's first argument to 0.

    Ginden

    Posted 11 years ago

    Reputation: 197

    1

    Vitsy, 5 4 Bytes, 3 Characters

    When in Rome...

    'Nߞ

    Get the character with the value 2014 and then print it as a number. Simple.

    More Interesting Version (12 10 9 Bytes):

    "ca-^b-N-

    My language supports hexadecimal, too. ;)

    "         Capture the entire source as string by looping around the source.
     ca-      Push 2 to the stack
        ^     45^2
         b-   -11
           N  Output as a number.
            - Only here for character value 45.
    

    Addison Crump

    Posted 11 years ago

    Reputation: 10 763

    Am I right that this language is newer than the question? Besides, I believe this question is already 'closed'(winner chosen, and even an edit at the start discouraging more replies) – Sanchises – 9 years ago

    @sanchises You're absolutely right - I'll pull my edit request. I'd still like to add it to the list, though, even if marked as a new language.. :D – Addison Crump – 9 years ago

    Just put it under 'invalid' I guess, there's a section for that at the end. – Sanchises – 9 years ago

    Changed the edit suggestion. :P Forgot about the 'newer than question' thing, but I should've considered that. Thanks, @sanchises – Addison Crump – 9 years ago

    1

    Perl 5, 8 28 bytes

    say 38*53

    Seems to do it.

    Oh, without cheating ?

    $z=ord("!")*ord("=");say++$z
    

    Dale Johnson

    Posted 11 years ago

    Reputation: 509

    D'oh. I thought it was without any of those numbers. – Dale Johnson – 9 years ago

    1

    T-SQL 27 bytes

    PRINT ASCII('')*ASCII('j') 
    

    Note that the character that isn't rendered here is the DC3 (CHAR(19)) in the first set of quote marks. It's unicode U+009F which, it would appear, doesn't copy and paste here too well but I can assure you it works in SQL Management Studio.

    Steve Matthews

    Posted 11 years ago

    Reputation: 121

    1

    Quetzalcoatl, 11 4 5 bytes

    Noncompeting because this language is from 2016.

    ::ord('ߞ')
    

    The box should be replaced by Unicode character 2014.

    Edit

    This is for an old version of Quetzalcoatl. New version:

    'ߞ'O
    

    NoOneIsHere

    Posted 11 years ago

    Reputation: 1 916

    This language is new though, this year. – NoOneIsHere – 9 years ago

    There is no ASCII character 2014... it has to be Unicode to go that high. – mbomb007 – 9 years ago

    If Quetzalcoatl is newer than the challenge, you're answer is non-competing and should say so in its body. Also, I'm not aware of any encoding in which ߞ would be a single byte. – Dennis – 9 years ago

    1

    SMBF, 15 bytes

    \x00 is a literal NUL byte. This program adds 5 to each of /,+- and prints.

    <[+++++.<]\x00/,+-
    

    Only my Python interpreter can accept non-printable ASCII. Change the data line to this, and substitute the code you want to run with the non-printable values escaped (on line 169):

    data = bytearray(b'the above code goes here')
    

    mbomb007

    Posted 11 years ago

    Reputation: 21 944

    1

    Retina, 24 bytes (newer than challenge)

    Note the trailing space on lines 2 and 3. Language is newer than the challenge.

    
    xx  x xxxx 
    +`(x)* 
    $#+
    

    Try it online

    mbomb007

    Posted 11 years ago

    Reputation: 21 944

    1

    Mathematica, 10 bytes

    N[E,E^E^E]
    

    Prints the decimal expansion of the number e to over 3.8 million decimal places. The first occurrence of 2014 in that decimal expansion starts at the 3180th decimal place.

    Greg Martin

    Posted 11 years ago

    Reputation: 13 940

    1

    VBA, 21 characters

    ?cells(,"BYL").column
    

    Write and run the above code in the Immediate Window. Basically, the code converts column name BYL to its column index (2014).

    Anastasiya-Romanova 秀

    Posted 11 years ago

    Reputation: 1 673

    For future reference, this may be rewritten as ?[BYL:BYL].Column – Taylor Scott – 7 years ago

    1

    Straw, 13 bytes (non-competing)

    Non-competing because the language is 2 years newer than the question...

    (…………………σ)«$>
    

    « sum the codepoint of all characters in a string, $ convert from unary to decimal and > is the print operator.

    Try it online

    TuxCrafting

    Posted 11 years ago

    Reputation: 4 547

    1

    Actually, 15 bytes

    This language was created long after this challenge was made, but I thought I'd still try my hand at it. This answer avoids all numerals, including Actually's ² for a*a. Golfing suggestions welcome. Try it online!

    ╜⌐u;*⌐úl¬¬τu;*-
    

    Ungolfing

    ╜    Push register 0 (initialized to 0).
    ⌐u   Add 2 and increment. Returns 3.
    ;*   Duplicate and multiply. Equivalent to squaring. Returns 9.
    ⌐    Add 2 again. Returns 11.
    úl   Pushes the lowercase alphabet and gets its length. Returns 26.
    ¬¬   Subtracts 2 twice. Returns 22.
    τ    double(). Returns 44.
    u    Increment. Returns 45.
    ;*   Square. Returns 2025.
    -    Subtract. Returns 2025 - 11 == 2014.
    

    Sherlock9

    Posted 11 years ago

    Reputation: 11 664

    0

    Pushy, 6 bytes

    `��`j#
    

    Contains control characters, so here's a hexdump:

    0000-0006:  60 14 0e 60 6a 23
    

    The first unprintable is the literal DC4 byte (\x14), and the second is SHIFT-OUT (\x0e).

    First these bytes are pushed as charcodes, so the stack is [20, 14]. The j operator concatenates these and # outputs the result: "2014".


    10-byte solution:

    `<:;>`KT-"
    

    Uses char-code manipulation and the builtin T (10).

    `<:;>`       Push string as char-codes: [60, 58, 59, 62]
         KT-     Take 10 from each: [50, 48, 49, 52]
            "    Interpret as char-codes and print: results in "2014"
    

    FlipTack

    Posted 11 years ago

    Reputation: 13 242

    0

    Pyke, 3 bytes, noncompetitive

    Try it here!

    Where ߾ is 0xDFBE

    Loads ord(0xDFBD-0x20) as an integer and implicit prints it

    Blue

    Posted 11 years ago

    Reputation: 26 661

    How does it work? – Pavel – 8 years ago

    @Pavel explanation added – Blue – 8 years ago

    0

    tcl, 16

    puts [scan ߞ %c]
    

    Can be seen on: http://rextester.com/live/SVXB29034

    sergiol

    Posted 11 years ago

    Reputation: 3 055

    0

    Groovy, casting to int, 8 bytes

    (int)'ߞ'
    

    Matias Bjarland

    Posted 11 years ago

    Reputation: 420

    0

    C, 25 bytes

    f(){printf("%d",L'ߞ');}
    

    24 characters, but one character is UTF-8 encoded. Still the shortest C answer! How it works:

    U+07DE ߞ NKO LETTER KA
    

    7DE in decimal is 2014.

    MD XF

    Posted 11 years ago

    Reputation: 11 605

    0

    Python 3, 16 Bytes :

    print(ord('ߞ'))
    

    2017 version, 16 Bytes :

    print(ord('ߡ'))
    

    MrGeek

    Posted 11 years ago

    Reputation: 231

    0

    Python - 23 Bytes

    print ord('&')*ord('5')
    

    Mark Bell

    Posted 11 years ago

    Reputation: 109

    2The 5 is a number. – pppery – 7 years ago

    0

    Whitespace, 19 bytes

    Visible representation:

    SSSTTTTTSTTTTSNTNST
    

    Just pushes 2014 onto the stack and prints it. Whitespace's lack of any visible characters makes this pretty easy.

    Valid as numbers are completely valid tokens in whitespace, they just don't do anything.

    CensoredUsername

    Posted 11 years ago

    Reputation: 951

    0

    Common Lisp, 15 characters

    (char-code #\ߞ)
    

    Try it online!

    Renzo

    Posted 11 years ago

    Reputation: 2 260

    0

    Ruby (8 bytes, 7 chars)

    'ߞ'.ord
    

    The question mark is ߞ represented in two bytes UTF8.


    Short Ruby

    schmijos

    Posted 11 years ago

    Reputation: 103

    Duplicate of O-I's Ruby solution posted 3.5 years earlier.

    – manatwork – 8 years ago

    @manatwork Duplicate answers are allowed.

    – Martin Ender – 8 years ago

    I didn't said they aren't. Neither downvoted or flagged. (Just for the record, I never agreed with that rule. And never will.) But I think would be more enjoyable to avoid duplicated solutions. Especially on a question that already has 263 answers. – manatwork – 8 years ago

    Hm... hard to find the old solutions. But actually his solution is 9 bytes because the codepoints representations need 2 bytes. – schmijos – 8 years ago

    Btw: Having seen the solution of @o-i : ?ߞ.ord would then be only 7 bytes, right? – schmijos – 8 years ago

    1Initially O-I's solution was also 'ߞ'.ord, but then be updated because the requirement says to “prints the number 2014”. The general rule (which can be overridden by each challenge) is that solutions must handle input and output either themselves explicitly or benefit the interpreter's service if it has such thing like ruby's -n or -p. Code that expects input to be readily available in the memory or just leaves the value they produce in the memory are called snippets and generally are not accepted as solutions. – manatwork – 8 years ago

    BTW, looks like neither Timtech found O-I's solution and posted his own after just 1 week. I assume there were considerably fewer solutions that time.

    – manatwork – 8 years ago

    0

    Clojure - 35 characters ASCII only

    (print(-(*(int\#)(int\<))(int\V)))
    

    Based on True Soft's answer

    Joshua

    Posted 11 years ago

    Reputation: 231

    0

    Lua, 27 bytes

    Should work in Lua 5.1, Lua 5.2, and Lua 5.3.

    x="ɅɅ"print(x:byte()..#x)
    

    Try it online!

    This is mean to be saved with the UTF-8 encoding. The first byte of the string is 201, and its length is four. Lua is mostly encoding agnostic, so as long as these things are true in whatever encoding, it works.

    With only ASCII, 28 bytes:

    x=""io.write(x:byte(y,#x))
    

    Note: the string must contain ASCII 20 and ASCII 14 (which are not printable characters). y here is an undefined variable, so it is nil, which byte defaults to 1 in the first parameter.

    tehtmi

    Posted 11 years ago

    Reputation: 446

    0

    Aceto, 10 bytes

    IIppIpPiIp
    

    Try it online!

    Uses int(Pi) to it's advantage

    11 bytes (previous answer)

    IIppIpIIIIp
    

    Try it online!

    Simply increments from zero 2, 0, 1, and 4 times, then prints each time

    Fun Version

    Piddd++DsJiPidIIJi*p
    

    Try it online!

    Uses int(Pi) to base equations off of

    Lame Version

    'ߞop
    

    Try it online!

    Converts the codepoint to number, which is 2014

    FantaC

    Posted 11 years ago

    Reputation: 1 425

    0

    Implicit, 3 bytes

    Try it online!

         implicit push command
    `    character
     ߞ   U+07DE (2014 in decimal)
         implicit integer output
    

    MD XF

    Posted 11 years ago

    Reputation: 11 605

    0

    Triangularity, 18 bytes

    .. ..
    ."ߞ".
    o    
    

    Try it online!

    Mr. Xcoder

    Posted 11 years ago

    Reputation: 39 774

    0

    Pyt, 16 bytes

    áŁ!⁺²Đ⁺⁺!₀⁻⁻⇹ᴇ+₅
    

    Explanation:

    á                               Push stack into list (pushes empty list)
     Ł                              Get length of top of stack (0)
      !                             0!=1
       ⁺²                           (1+1)^2=4
         Đ                          Duplicate top of stack
          ⁺⁺!                       (4+2)!=720
             ₀⁻⁻                    720/10-2=70
                ⇹                   Swap top two items on stack (4 is on top)
                 ᴇ                  10^4=10000
                  +₅                (10000+70)/5=2014
    

    Try it online!

    mudkip201

    Posted 11 years ago

    Reputation: 833

    0

    Brainf*ck

    >++++++++++[<+++++>-]<.--.+.+++.
    

    More readable version:

    > Move pointer pos over
    ++++++++++ Add 10
    [ Start loop
    <+++++>- Add 5, move over & subtract 1
    ] End loop
    <.--.+.+++. Do some other stuff
    

    Yes, I know this is an old post, but I'm really bored and want to get enough rep to comment because I don't have access to my other account.

    Wobbly

    Posted 11 years ago

    Reputation: 9

    Welcome to PPC...Jk – FantaC – 7 years ago

    0

    Brainfuck, 23 Bytes

    -[>+<-----]>-.--.+.+++.
    

    Try it online!

    Dust

    Posted 11 years ago

    Reputation: 131

    0

    PHP, 25 bytes

    <?=IntlChar::ord("ߞ");?>

    Agnius Vasiliauskas

    Posted 11 years ago

    Reputation: 125

    This requires the IntlChar library; and that´s a lot younger than the question. Nice idea, though. – Titus – 7 years ago

    Thanks. Can be solved without using IntlChar library with preg_replace('#\D#','',json_encode('—')). Pick your number from a unicode table :-) – Agnius Vasiliauskas – 7 years ago

    0

    SNOBOL4 (CSNOBOL4), 42 bytes

    	&UCASE 'N' @X ARB 'T' @Y
    	OUTPUT =Y X
    END
    

    Try it online!

    @ assigns the index of the match and (space) concatenates them.

    I know, it's 2018, so I should go home...

    Giuseppe

    Posted 11 years ago

    Reputation: 21 077

    0

    Python 3, 16 bytes

    lambda:ord('ߞ')
    

    Try it online!

    Dat

    Posted 11 years ago

    Reputation: 879

    0

    T-SQL, 32 bytes

    Based on the idea of Steve Matthews, but avoiding unprintable characters:

    SELECT -~(ASCII('=')*ASCII('!'))
    

    Alternative (but rather obvious) solution, 23 bytes:

    PRINT UNICODE(N'ߞ')
    

    Razvan Socol

    Posted 11 years ago

    Reputation: 341

    0

    Objective-C, 27

    NSLog(@"%i",'&'*('V'-'!'));
    

    Albert Renshaw

    Posted 11 years ago

    Reputation: 2 955

    0

    x86, 15 bytes

    No numbers in the source code. Returns in eax. Uses (252*4 - 1) * 2.

       0:   31 c0                   xor    %eax,%eax
       2:   fe c8                   dec    %al
       4:   48                      dec    %eax
       5:   48                      dec    %eax
       6:   48                      dec    %eax
       7:   d1 e0                   shl    %eax
       9:   d1 e0                   shl    %eax
       b:   48                      dec    %eax
       c:   d1 e0                   shl    %eax
       e:   c3                      ret  
    

    If we permit numbers in the source but not binary, we have mov $2014,%ax/ret for 5 bytes.

    qwr

    Posted 11 years ago

    Reputation: 8 929

    0

    Ahead, 5 bytes

    ezpz

    'ߞO@
    
    ' push next cell to stack
    ߞ U+7DE (2014 decimal)
    O output as number
    @ die
    

    Try it online!

    snail_

    Posted 11 years ago

    Reputation: 1 982

    0

    Z80Golf, 10 bytes

    00000000: 080a 0b0e 767e 23e5 ee3a                 ....v~#..:
    

    Try it online!

    Disassembly

    start:
      ex af,af'  ; db $3a ^ '2' ($08)
      ld a,(bc)  ; db $3a ^ '0' ($0a)
      dec bc     ; db $3a ^ '1' ($0b)
      ld c,$76   ; db $3a ^ '4' ($0e)
                 ; halt         ($76)
      ld a,(hl)
      inc hl
      push hl
      xor $3a
    

    Essentially the Hello World trick in Z80Golf.

    In short, hl serves two purposes: data address for a and return address for putchar (which is at $8000 and accessed by going all the way through zeroed memory, instead of call $8000).

    The instructions in the data section have to be effective no-ops (not touching hl and sp should suffice), and the last one should be 2-byte in order to shadow $76 (halt). I carefully selected the xor value so that the resulting binary has no digits ($30 to $39).

    Z80Golf, 10 bytes, 2018 edition

    00000000: 1416 171e 767e 23e5 ee26                 ....v~#..&
    

    Try it online!

    Disassembly

    start:
      inc d      ; db $26 ^ '2' ($14)
      ld d,$17   ; db $26 ^ '0' ($16)
                 ; db $26 ^ '1' ($17) ; rla
      ld e,$76   ; db $26 ^ '8' ($1e)
                 ; halt         ($76)
      ld a,(hl)
      inc hl
      push hl
      xor $26
    

    Same principle, but this time we can't use ld c,$76 since it gives $36 for the xor value. So I moved to e which starts with 1e. Also, different starting address gives two different interpretations of the data section:

    • $16 $17: ld d,$17
    • $17: rla (Rotate the register A to the left)

    So I had to check both are effective no-ops in this program.

    Bubbler

    Posted 11 years ago

    Reputation: 16 616

    0

    Lua 5.3.1, 31 bytes

    It's an old question, but I may as well join in on the fun!

    For those not familiar with Lua, the # operator returns the length of an array or string, and the .. operator is for string and number concatenation. The // operator is integer divide, and is used so that there is no trailing decimal in the numbers caused by Lua treating the result of regular divisions as a float.

    2014 in 31 bytes: t=#"aa"print(t..t-t..t//t..t*t) = print(2..2-2..2/2..2*2)

    2015 in 36 bytes: t=#"aa"print(t..t-t..t//t..t*t+t//t) = print(2..2-2..2//2..2*2+2/2)

    2016 in 33 bytes: t=#"aa"print(t..t-t..t//t..t*t+t) = print(2..2-2..2//2..2*2+2)

    2017 in 38 bytes: t=#"aa"print(t..t-t..t//t..t*t+t+t//t) = print(2..2-2..2//2..2*2+2+2/2)

    2018 in 33 bytes: t=#"aa"print(t..t-t..t//t..t*t*t) = print(2..2-2..2//2..2*2*2)

    The solutions for other years are pretty similar. Here's a function that can do any number:

    function f(y)
        t=#"a"
        s=""
        for i=t, #(y.."") do
            n=t-t
            for j=t,(y..""):sub(i,i) do
                n=n+t
            end
            s=s..n
        end
        return s
    end
    

    And here's the golfed version of the function at 108 bytes:

    function f(y)t=#"a"s=""for i=t,#(y.."")do n=t-t for j=t,(y..""):sub(i,i)do n=n+t end s=s..n end return s end

    GalladeGuy

    Posted 11 years ago

    Reputation: 101

    0

    Objective C

    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    [formatter setDateFormat:@"yyyy"]; 
    NSLog(@"%@",[formatter stringFromDate:[NSDate date]]);
    

    Milap Kundalia

    Posted 11 years ago

    Reputation: 119

    NSLog(@"%i",'&'*('F'-'A')); – Albert Renshaw – 8 years ago

    1

    From the comments: Gelatin: “Is it acceptable to use the current year?” Joe Z.: “No, it has to be 2014 exactly.”

    – manatwork – 11 years ago

    Because the question is a code-golf question, please add the character count. – ProgramFOX – 11 years ago

    1What happened to you, Smalltalk ? You look...different. – bug – 11 years ago

    @AlbertRenshaw that just prints 190. – Cœur – 7 years ago

    1@Cœur sorry meant this NSLog(@"%i",'&'*('V'-'!')); – Albert Renshaw – 7 years ago

    Should be noted that OP's source code just prints 2018 ;) – Albert Renshaw – 7 years ago

    0

    You never said we couldn't put it on an external page!

    Javascript - 19 Chars

    location='//x.vu/u'
    

    PS. It took 2 tries to get a shortened URL without numbers :P

    Cilan

    Posted 11 years ago

    Reputation: 724

    Yes, but sadly your code is far from being the shortest. :P – Joe Z. – 11 years ago

    1@Joe Z. Right, you could include an HTML script src instead :P – Cilan – 11 years ago

    location.href.match(/-(\d+)-/).pop() – Alf Eaton – 11 years ago

    location='http://goo.gl/miVwHe' would be shorter in my opinion. – Konrad Borowski – 11 years ago

    @xfix Thanks for the tip, I even removed 'http:' :) – Cilan – 11 years ago

    You can take out those two slashes at the start too. ;) – cjfaure – 11 years ago

    @Trimsty I wish, but unfortunately not ;( – Cilan – 11 years ago

    @TheWobbuffet Hm. That's really weird, I really thought it'd work! Sorry. – cjfaure – 11 years ago

    0

    ;# - 203

    ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;#;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;#;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;#;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;#
    

    seadoggie01

    Posted 11 years ago

    Reputation: 181

    This language is invalid according to the community consensus on what counts as a programming language – MilkyWay90 – 6 years ago

    @MilkyWay90 Um, this is from just under a year ago... I don't think there was a consensus back then. Either way, it's not like i even got an upvote, so let's just leave it, eh? – seadoggie01 – 6 years ago

    The consensus was made in 2014. You can take it up with Meta, but until then this is invalid

    – MilkyWay90 – 6 years ago

    0

    GTB, 38

    π/π→A:A++B:A+A→C:C*C→D~B*C*C+B*C-C-A-A
    

    Compile assuming : at front

    Timtech

    Posted 11 years ago

    Reputation: 12 038

    π is 2 bytes and is 3, bringing the byte count to 49. – Joe Z. – 11 years ago

    @JoeZ. All characters at http://tibasicdev.wikidot.com/83lgfont are 1 byte.

    – Timtech – 11 years ago

    0

    K (ngn/k), 10 bytes

    "&"*-/"U "
    

    Try it online!


    and 2018 just because this is so late

    K (ngn/k), 11 bytes

    -"^"-*/"@!"
    

    Try it online!


    EDIT: I'm unsure when this language was created, it's a variant of k which has existed for a long time, but the gitlab link seems to indicate that it may be only a year or so old (judging by commit info), so this answer may be invalid as a result

    Thaufeki

    Posted 11 years ago

    Reputation: 421

    The non-competing rule has been abolished – MilkyWay90 – 6 years ago

    0

    C# (56 characters)

    Class P{static void Main(){Console.Write(','*','+'N');}} 
    

    Merin Nakarmi

    Posted 11 years ago

    Reputation: 247

    This doesn't print anything. – shamp00 – 11 years ago

    26 characters = 4 bytes?? I don't think so... – jub0bs – 11 years ago

    Sorry. I just included the logic only. Now I included the whole program. – Merin Nakarmi – 11 years ago

    You need System.Console to use Console. – shamp00 – 11 years ago

    using System; will be on the header. So.... – Merin Nakarmi – 11 years ago

    0

    Aheui (esotope), 8 chars (24 bytes)

    반밝따바뱟해망어
    

    Try it online!


    It's too easy for Aheui since it never use any kind of digits at all.

    Explanation:

    # An Aheui code starts with default stack "아".
    반: push 2, move cursor right by 1(→).
    밝: push 7, →
    따: mul(push 14), →
    바: push 0, →
    뱟: push 2, move cursor right by 2(→→).
    해: end.
    망: print as integer, →
    어: move cursor left by 1(←).
    

    Note: Print instruction moves cursor in reverse direction if current storage is empty.

    cobaltp

    Posted 11 years ago

    Reputation: 401

    0

    TI-BASIC, 7 bytes

    int(₁₀^(³√(tan(cosh(cos(π
    

    A significant improvement from the previously winning 12-byte TI-BASIC answer. Using one-byte functions allows the greatest number of chances to achieve a certain value within a given byte count.

    lirtosiast

    Posted 11 years ago

    Reputation: 20 331

    0

    Perl, 24 bytes

    print-ord(A)+ord for U,O
    

    Pure ascii, no nonprinting characters or utf8-only characters used. Uses the 21st and 15th letters of the alphabet to print 20, 14.

    user2905252

    Posted 11 years ago

    Reputation: 21

    0

    HaykamScript, 11 bytes

    s[⛉,☄]i
    

    Explanation

    s       - string
      [     - executed parameters
        ⛉   - constant for 201
        ,
        ☄   - constant for 4
      ]
    i       - convert to integer
    

    Other Years

    It's pretty simple to make any other year with the same amount of bytes, Unicode codepoints 0x2600 to 0x26FF represent integers 0 to 255 in my language.

    For example, to make the year this was posted:

    s[⛉,☈]i
    

    haykam

    Posted 11 years ago

    Reputation: 784

    0

    BAT (windows batch), 7 characters

    echo %*
    

    save as a.bat and invoke as a 2014

    is there any restriction on using command line parameters? – Einacio

    I don't think so, but echo $1 still has a number in it. – Joe Z.

    not a so valid answer, but noone was posting an answer in this wonderful language

    Einacio

    Posted 11 years ago

    Reputation: 436

    Does BAT have an equivalent to sh’s $@ for “all parameters”? – Zev Eisenberg – 11 years ago

    @ZevEisenberg that's what i used, altought it seems someone didn't like it – Einacio – 11 years ago

    0

    k 11 & 17 chars

    this 11-char one is from a colleague

    @:[:']*.(.)
    

    this 17-char one is the best i could come up with on my own; it's a variant on ASCII abuse:

    .,/$-/"i"$$`zz`fl
    

    and just for interest, here are a few others of mine:

    ."c"$"RPQT"-"e"$" " / ascii (only 2.x)
    ."c"$-/"e"$("RPQT";" ") / ascii (all versions)
    
    -_-(s*(exp acos@-`=`)xexp x)-(s xexp s:x*x)%x:+/``=`` / port of David Carraher's solution above
    
    .,/$#:'(``;();`;````) / another approach
    

    Aaron Davies

    Posted 11 years ago

    Reputation: 881

    @David Carraher my latest improvements on my port of your algo--two implementations, both 39 chars:

    -_-(x*p*p:exp acos@-#`)-f*x*x*x:f*f:#``
    f+(x*_p*p:exp acos@-#`)-f*x*x*x:f*f:#``
    
    

    (i don't have the rep to comment on your post yet) – Aaron Davies – 11 years ago

    0

    PHP (27) - not shortest ASCII PHP but more readable

    <?=hexdec($e=hexdec(E)).$e;
    

    brother Filip

    Posted 11 years ago

    Reputation: 31

    0

    Bash, 15 bytes

    echo "^T "|od -x
    

    (^T is one character.)

    Kevin Fegan

    Posted 11 years ago

    Reputation: 121

    How about: printf %x \'— 13 characters. – Isaac – 5 years ago

    0

    Bat (Windows batch), 13 bytes (characters)

    echo.^T |od -x
    

    (^T is one character.)

    Kevin Fegan

    Posted 11 years ago

    Reputation: 121

    0

    PYTHON

    print(str(len('Happy new year to me')) + str(len('Happy new year')))
    

    Oliver Ni

    Posted 11 years ago

    Reputation: 9 650

    This has a 1 in it. – Joe Z. – 11 years ago

    oh whoops let me fix it – Oliver Ni – 11 years ago

    1Must str('Happy new year') be wroted as str(len('Happy new year'))? – AMK – 11 years ago

    sorry. I fixed it. – Oliver Ni – 11 years ago

    0

    PHP, 22 bytes

    echo ord('').ord('')
    

    Edit

    SE is stripping the characters. Working version here: http://codepad.org/unzjXNY2.

    MichaelRushton

    Posted 11 years ago

    Reputation: 244

    this produces "00" when I run it. Please explain. – Darren Stone – 11 years ago

    SE is stripping the characters. Added a codepad example. – MichaelRushton – 11 years ago

    You can swap out echo with <?=, to make it 2 characters shorter. – cjfaure – 11 years ago

    0

    Forth, 29 bytes

    hex fbc 'B' '!' / / decimal .
    

    Try it online!

    nonForgivingJesus

    Posted 11 years ago

    Reputation: 129

    0

    bc, 7 bytes. Try it Online!!

    K*ZZ+Y

    bc, 8 bytes. Try it Online!!

    K*A*A+E

    Which needs 14 bytes to run in bash:

    bc<<<"K*A*A+E"

    In bc the upper (single) letters maintan their meaning as a number in 10-36 range in any input base.

    A previous approach changed the input base:

    echo ibase=D\;BBC|bc

    Make numeric base 13 (D) and print BBC in that base --> 2014.

    Isaac

    Posted 11 years ago

    Reputation: 173

    0

    *nix shell (POSIX/bourne) 41 bytes

    a=.. c=. d=....;echo ${#a}${#b}${#c}${#d}

    Other solutions

    printf %x \'— # 13 characters Try it online!
    echo $[x=++y+y]$?$y$[x+x] # 25 characters Try it online!

    Isaac

    Posted 11 years ago

    Reputation: 173

    0

    C# .NET 75 bytes

    public class p{public static void Main(){System.Console.Write((int)'ߞ');}}
    

    Just displaying the integer value of the unicode character ߞ
    Try online (also has 2015-2019)

    canttalkjustcode

    Posted 11 years ago

    Reputation: 131

    0

    Python, 8 bytes

    ord('ߞ')
    

    Cheap answer to convert the UTF-16 char to its value.

    GetHacked

    Posted 11 years ago

    Reputation: 111

    Exact copy of MadTux's Python solution posted more than 5 years earlier. (Hint: the Leaderboard script embedded in the challenge description is the easiest way to search for the existing solutions in your chosen language, to see whether anybody got the same idea before.)

    – manatwork – 5 years ago

    Oof, thanks. I looked at the leaderboard, but the Python result I found there was longer than 8 bytes. – GetHacked – 5 years ago

    0

    Flobnar, 17 14 bytes

    <+\@:!
    +<>.!..
    

    Try it online!

    Explanation:

       @       Start, going left
    
      \        Push to the stack the value from the bottom row
      >
    
       .!..   Several print statements we will get back to
    <   :!    Add the not of the top of the stack to itself
    +         This is !0+!0 = 2
    
          .   Print the 2
    
         .    Print the result of the print (0)
    
       .!     Print the result of the not of the print (1)
      \       Continue forward after pushing the zero to the stack
    
    <+   :!   Add the same 2 from the beginning to itself
    +<        (!0 + !0)+(!0 + !0) = 4
              And print implicitly as the last value
    

    Jo King

    Posted 11 years ago

    Reputation: 38 234

    0

    ><>, 7 bytes

    aa+nen;
    

    You can try it on The Online ><> interpreter.

    Explanation

    a        # push 10
     a       # push 10
      +      # push sum of top two values (10 + 10 = 20)
       n     # output top value as number
        e    # push 14
         n   # output top value as number
          ;  # halt program
    

    This doesn't print the following:

    20
    14
    

    because n outputs the top value as a number without a newline.

    Alternate Solution (9 bytes)

    This one actually puts 2014 on the stack as a single number and outputs it.

    cbde**+n;
    

    I basically just tried random values for this one :P

    Sagittarius

    Posted 11 years ago

    Reputation: 169

    0

    k4, 20 bytes

    */(-)."j"$("Ud";"/")
    

          "j"$("Ud";"/") / convert "Ud" and "/" to underlying integer representation -> (85 100;47)
      (-).               / subtract 47 from 85 and 100 -> 38 53
    */                   / multiply over
    

    scrawl

    Posted 11 years ago

    Reputation: 1 079

    0

    Triangular, 12 bytes

    tE**%Cdd.`>/
    

    Try it online!

    Y'know, I was just about to post a 14-byte solution; luckily I went back to double-check and had a hunch.

    Ungolfed:

        t 
       E * 
      * % C 
     d d . ` 
    > /
    
    -- Actual Execution Order --
    
    t*C`          The first multiplication does nothing.
                  12 is pushed twice, then direction changes and both are multiplied to get 144.
    
    E*d>/d%       Push 14, then multiply 14*144=2016. Decrement twice and print.
    


    The 14-byte I was going to post:
    t*CE.`*...>dd%
    

    Reinstate Monica

    Posted 11 years ago

    Reputation: 1 382

    0

    Delphi (26bytes & 26 chars)

    ord('-')*ord('/')-ord('e')
    

    Ascii values
    - : 45
    / : 47
    e : 101
    45*47 = 2115 - 101 = 2014

    Teun Pronk

    Posted 11 years ago

    Reputation: 2 599

    0

    ABC, 11 bytes

    aacncacaaac
    

    Explanation

    a increments the accumulator, c outputs it and n sets it to 0.

    Sagittarius

    Posted 11 years ago

    Reputation: 169

    0

    MathGolf, 2 bytes

    ID
    

    Try it online!

    Explanation

    I   # push 20
     D  # push 14
        # implicit output
    

    Sagittarius

    Posted 11 years ago

    Reputation: 169

    0

    e-TeX, 21 bytes

    \the\numexpr`*`j\bye

    It contains an invisible control character with code 19 (0x13) before the asterisk. A version with printable ASCII characters needs two more bytes:

    \the\numexpr`^^S*`j\bye
    

    In TeX ` takes the character code of the next token:

    • [0x13] (^^S): 19
    • j: 106

    \numexpr calculates: 19 * 106 = 2014

    The result is a DVI file with "2014" on the first page.

    Variant with 2014 as page number:

    \pageno\numexpr`^^S*`j~\bye
    

    (25 bytes, if ^^S is replaced by the byte with character code 19).

    Heiko Oberdiek

    Posted 11 years ago

    Reputation: 3 841

    0

    Java without the weird unicode charas @ 115

    enum A{A;public static void main(String[]z){int a=A.ordinal(),b=a++;System.out.print(""+(a<<a)+b+a+(a<<(a<<a)));}}
    

    enumerators are pretty handy :)

    masterX244

    Posted 11 years ago

    Reputation: 3 942

    0

    Python, 8 characters

    ord('ߞ')
    

    I think this ought to be valid :P

    Ok, if you want me to use print(),

    15 characters

    print(ord('ߞ'))
    

    MadTux

    Posted 11 years ago

    Reputation: 687

    0

    Microscript, 10 bytes

    Noncompeting, language postdates the question..

    'js'(s';-*
    

    Explanation: 106*(59-40), using the language's equivalent of character literals. I'd do 53*38, but the character corresponding to 53... is the digit 5. And the character corresponding to 19 is, of course, nonprintable, so that wouldn't work.

    SuperJedi224

    Posted 11 years ago

    Reputation: 11 342

    0

    Cardinal, 14 chars

    %n=*+.-d++.
     d
    

    The pointer starts at %, reads in the character ‘d’(ASCII 100), creates a duplicate as inactive value (the bottom of the stack), adds active and inactive values, resulting in 200, adds 1, prints out the result 201, subtracts one, divides by inactive value (100), resulting in 2, adds two, prints out 4. Cardinal pointer stacks can only carry values up to 255 (OEM 437 range), everything above leads to a wrap-around.

    0             100             100             200             201
    0               0             100             100             100
    >n=*+.-d++.    %>=*+.-d++.    %n>*+.-d++.    %n=>+.-d++.    %n=*>.-d++.
     d              d              d              d              d
    ———————————————————————————————————————————————————————————————————————
       201             200               2               3               4
       100             100             100             100             100
    %n=*+>-d++.    %n=*+.>d++.    %n=*+.->++.    %n=*+.-d>+.    %n=*+.-d+>.
    
    print:"201"
    ———————————————————————————————————————————————————————————————————————
              4
            100  
    %n=*+.-d++>
    
      print:"4"
    

    Result:

    Executing program..
    
    2014
    
    Execution complete.
    

    M L

    Posted 11 years ago

    Reputation: 2 865

    0

    C, 24 / 68

    main(){printf("MMXIV");}
    

    Haha, Roman Numerals For The Win!


    Or, for real:

    main(){printf("%i%i%i%i",strlen("aa"),nil,strlen("a"),sizeof(int));}
    

    Albert Renshaw

    Posted 11 years ago

    Reputation: 2 955

    0

    q, 20 17 bytes

    {x+y*z}."j"$"$+."
    

    Alexander Belopolsky

    Posted 11 years ago

    Reputation: 191

    0

    TeaScript, 7 bytes

    'ߞ'c()
    

    Takes the char code of the character with a char code of 2014

    Downgoat

    Posted 11 years ago

    Reputation: 27 116

    0

    Groovy, 48 bytes

    For 2015 change cabe to cabf...

    n={it.each{print(((int)it)-(int)'a')}}
    n('cabe')
    

    K. Klassen

    Posted 11 years ago

    Reputation: 121

    0

    Factor, 10 bytes

    Not gonna beat my winning answer, but as a follow-on to the other "2014th Unicode char" answers:

    CHAR: ߞ .
    

    Prints 2014.

    cat

    Posted 11 years ago

    Reputation: 4 989

    0

    Base64, 9 Bytes

    MjAxNA==

    (You can decode it with: echo MjAxNA== |base64 -d)

    Ronronner

    Posted 11 years ago

    Reputation: 129

    0

    JavaScript, 17 Bytes

    atob("MjAxNA==")
    

    Ronronner

    Posted 11 years ago

    Reputation: 129

    0

    Jelly, 10 bytes (non-competing)

    ⁹⁴×H_⁴Ḥ¤’’
    

    Explanation:

    ⁹            Set the current value to 256.
     ⁴×          Multiply by 16. The current value is now 4096.
       H         Divide by 2. The current value is now 2048.
        _⁴Ḥ¤     Subtract by 16/2. The current value is now 2016.
            ’’   Decrement twice. The current value is now 2014.
    

    Loovjo

    Posted 11 years ago

    Reputation: 7 357

    0

    C (gcc 5.3.1), 49 bytes

    Pure arithmetic! \o/

    main(a){printf("%d",(++a<<(a<<a|a))-(a<<a+a)-a);}
    

    Undefined behaviours.

    Specifically, use this compiler (languages are defined by implementation).

    Without undefined behaviour (which would work on all compilers), 51 bytes

    main(a){a++;printf("%d",(a<<(a<<a|a))-(a<<a+a)-a);}
    

    Explanation

    Basically 2048 - 32 - 2, constructed using powers of 2.

    Leaky Nun

    Posted 11 years ago

    Reputation: 45 011

    0

    Swift 2.2, 28 bytes

    print("\(ENOTDIR)\(EFAULT)")
    

    Falling back on Darwin/glibc error codes from errno.h.

    JAL

    Posted 11 years ago

    Reputation: 304

    0

    Mathematica, 16 bytes

    FromDigits@"JAE"
    

    user48818

    Posted 11 years ago

    Reputation:

    0

    QBIC, 10 bytes - Not Competing

    ?z^s*r+z+t
    

    Calculates 2014 from the pre-initialised variables q-z (1-10) and prints it. Development of QBIC started some two years after 2014...

    Alternative 12-byte version:

    ?(u*y)^r-z-q
    

    steenbergh

    Posted 11 years ago

    Reputation: 7 772

    -4

    C, 29 bytes (Emacs) / 40 bytes (VI)

    Before creating program, execute the shell command

    stty -ixon      ### 11 bytes, with the newline
    

    N.B this is required for most terminal editors, but is not required for emacs

    then write this code:

    main(){printf("%d",'j'*'^S');}
    

    N.B. '^S' is a single XOFF character e.g. in VI use control-V, control-S; in emacs use control-Q, control-S; emacs turns off flow control by default.

    I assume the comment [You can't type ^S in a Linux terminal] below left off an implied [without the stty command or equivalent e.g. emacs default behavior upon startup], otherwise that comment is inaccurate.

    And here is the requested hexdump:

    $ od -a -t x1 x.c
    0000000   m   a   i   n   (   )   {   p   r   i   n   t   f   (   "   %
             6d  61  69  6e  28  29  7b  70  72  69  6e  74  66  28  22  25
    0000020   d   "   ,   '   j   '   *   ' dc3   '   )   ;   }  nl
             64  22  2c  27  6a  27  2a  27  13  27  29  3b  7d  0a
    

    Brian Carcich

    Posted 11 years ago

    Reputation: 27

    2This isn't a valid answer. You have to count the shell command also, since it's a non-standard configuration. Also, if you have unprintables in your code, you should include a hexdump, for extra clarity. – Mego – 8 years ago

    You can't type ^S in a Linux terminal. -1 – MD XF – 8 years ago

    There is more than one way to ^Skin a cat, so these comments are incorrect as written; I clarified my post to address the confusion these folks (and others) may be having. It's still 29 if you use emacs as an editor. MD XF: how do you enter your [U+07DE] character into C-source; also, my compiler throws an error when replacing [main()] with [f()] (excluding the obvious gcc -Df=main hack), but if there is a compiler that accepts [f()], then all C source scores drop by 3. So you need to bump your score by 3, or reduce all other C solutions. – Brian Carcich – 8 years ago