I done did made a spaceship maw!

Question

Introduction:

Inspired by this comment of @MagicOctopusUrn on @Emigna's 05AB1E answer for my "It was just a bug" challenge:

8F9ÝÀNð×ý}».∊ I done did made a spaceship maw! And I was all excited about suggesting a 12-byte edit. – Magic Octopus Urn Jul 17 '17 at 20:10

Which is a 05AB1E (legacy) program resulting in this:

1234567890
1 2 3 4 5 6 7 8 9 0
1  2  3  4  5  6  7  8  9  0
1   2   3   4   5   6   7   8   9   0
1    2    3    4    5    6    7    8    9    0
1     2     3     4     5     6     7     8     9     0
1      2      3      4      5      6      7      8      9      0
1       2       3       4       5       6       7       8       9       0
1      2      3      4      5      6      7      8      9      0
1     2     3     4     5     6     7     8     9     0
1    2    3    4    5    6    7    8    9    0
1   2   3   4   5   6   7   8   9   0
1  2  3  4  5  6  7  8  9  0
1 2 3 4 5 6 7 8 9 0
1234567890

Try it online.

Challenge:

Input: A non-empty string

Output: From outwards going inwards, add one more space between each character every line, similar as done in the output above, equal to the length - 1. So for an input 1234567890 the output would actually be this instead:

1234567890
1 2 3 4 5 6 7 8 9 0
1  2  3  4  5  6  7  8  9  0
1   2   3   4   5   6   7   8   9   0
1    2    3    4    5    6    7    8    9    0
1     2     3     4     5     6     7     8     9     0
1      2      3      4      5      6      7      8      9      0
1       2       3       4       5       6       7       8       9       0
1        2        3        4        5        6        7        8        9        0
1         2         3         4         5         6         7         8         9         0
1        2        3        4        5        6        7        8        9        0 
1       2       3       4       5       6       7       8       9       0
1      2      3      4      5      6      7      8      9      0
1     2     3     4     5     6     7     8     9     0
1    2    3    4    5    6    7    8    9    0
1   2   3   4   5   6   7   8   9   0
1  2  3  4  5  6  7  8  9  0
1 2 3 4 5 6 7 8 9 0
1234567890

Why? The length of 1234567890 is 10. So we start by outputting 10 lines: the first line without spaces; second with one space delimiter; third with two; etc. And then (without have the middle line with length - 1 spaces duplicated), we go back to the initial input while going down.

Challenge rules:

• Input is guaranteed to be non-empty (a length >= 1). (For single char inputs we simply output that character.)
• Any amount of trailing/leading spaces/newlines are allowed, as long as the output itself (wherever on the screen) is correct. (Empty line(s) in between output lines also isn't allowed.)
• Input will only contain printable ASCII characters excluding whitespaces (code-point range [33, 126])
• I/O is flexible. Input may be taken as STDIN, argument, or function parameter. May be a list/array/stream of characters instead of string. Output may also be a list/array/stream of characters instead of strings; may be printed to STDOUT; returned as newline-delimited string; etc.

General rules:

• This is code-golf, so shortest answer in bytes wins.
  Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.
• Standard rules apply for your answer, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.
• Default Loopholes are forbidden.
• If possible, please add a link with a test for your code.
• Also, adding an explanation for your answer is highly recommended.

Test cases:

Input: @
Output:
@

Input: test
Output:
test
t e s t
t  e  s  t
t   e   s   t
t  e  s  t
t e s t
test

Input: ?!
Output:
?!
? !
?!

Input: Spaceship
Output:
Spaceship
S p a c e s h i p
S  p  a  c  e  s  h  i  p
S   p   a   c   e   s   h   i   p
S    p    a    c    e    s    h    i    p
S     p     a     c     e     s     h     i     p
S      p      a      c      e      s      h      i      p
S       p       a       c       e       s       h       i       p
S        p        a        c        e        s        h        i        p
S       p       a       c       e       s       h       i       p
S      p      a      c      e      s      h      i      p
S     p     a     c     e     s     h     i     p
S    p    a    c    e    s    h    i    p
S   p   a   c   e   s   h   i   p
S  p  a  c  e  s  h  i  p
S p a c e s h i p
Spaceship

Input: 05AB1E
Output:
05AB1E
0 5 A B 1 E
0  5  A  B  1  E
0   5   A   B   1   E
0    5    A    B    1    E
0     5     A     B     1     E
0    5    A    B    1    E
0   5   A   B   1   E
0  5  A  B  1  E
0 5 A B 1 E
05AB1E

Input: )}/\
Output:
)}/\
) } / \
)  }  /  \
)   }   /   \
)  }  /  \
) } / \
)}/\

Answer 1

Japt, 8 6 bytes

Takes input as an array of characters, outputs an array of strings.

£qYçÃê

Try it

---

Explanation

£          :Map each element at (0-based) index Y
 q         :  Join input with
  Yç       :   Space repeated Y times
    Ã      :End Map
     ê     :Palindromise

---

Original, 8 bytes

I/O is a string. Uses the -R flag. Includes trailing spaces on each line.

¬£múYÄÃê

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Explanation

             :Implicit input of string U
¬            :Split
 £           :Map each character at 0-based index Y
  m          :  Map original U
   ú         :    Right pad with spaces to length ...
    YÄ       :     Y+1
      Ã      :End map
       ê     :Palindromise
             :Implicitly join with newlines

Answer 2

R, 105 99 85 84 79 bytes

-6 thanks to @Kevin Cruissen and @Giuseppe

-14 from changing to a regex based method

-1 thanks to @Giuseppe

-5 thanks to @digEmALl

function(w,n=nchar(w)-1)write(trimws(Map(gsub,"",strrep(" ",n-abs(n:-n)),w)),1)

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Answer 3

05AB1E, 10 9 bytes

Saved 1 bytes thanks to Adnan

εINð×ý}û»

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Explanation

ε            # apply to each in input
 I           # push the input
  Nð×        # push <index> spaces
     ý       # merge the input on the spaces
      }      # end loop
       û     # palendromize
        »    # join on newlines

Answer 4

Python 2, 72 70 68 66 65 bytes

^{-2 bytes thanks to Kevin Cruijssen
-3 bytes thanks to ovs}

w=input();c=s=-1
while c:print(' '*~c).join(w);s*=w[:c]>'';c+=s|1

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Answer 5

JavaScript (ES6), 53 bytes

Takes input as an array of characters.

f=(s,p=i='',o=s.join(p)+`
`)=>s[++i]?o+f(s,p+' ')+o:o

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Answer 6

Charcoal, 10 bytes

Ｅθ⪫θ× κ‖Ｏ↓

Try it online! Link is to verbose version of code. Explanation:

Ｅθ          Map over characters of input string
  ⪫θ        Join characters of input string using
    ×       a literal space repeated 
      κ     current index number of times
            Implicitly print each result on its own line
       ‖Ｏ↓  Reflect vertically with overlap

Answer 7

Canvas, 8 bytes

┐² ×＊］──

Try it here!

The 7 byte version was too good for this challenge..

Answer 8

Ruby, 54 49 bytes

->a{(-(z=a.size-1)..z).map{|i|a*(?\s*(z-i.abs))}}

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Takes input as an array of characters, outputs array of strings.

Answer 9

Japt, 9 8 bytes

-1 byte from @Shaggy

ÊƬqXîÃê

---

ÊƬqXîÃê        Full program, implicity input U
ÊÆ              Rage from 0 to U length and map
  ¬             split U at ""
   qXîà     join U using " " times range current value
        ê       horizontal mirror

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Answer 10

PowerShell, 66 54 bytes

-12 bytes thanks to mazzy

0..($x=($a=$args).count-1)+$x..0|gu|%{$a-join(' '*$_)}

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Takes input via splatting, which on TIO manifests as separate command-line arguments for each character.

We first set $a=$args as the input argument. Then we set $x equal to the .count of that array -1. We then need to loop through the letters to construct the spaceship. That's done by constructing a range from 0 to $x, then $x back down to 0, then using Get-Unique to pull out just the appropriate range.

Each iteration, we take our input arguments and -join them together with the corresponding number of spaces. Each of those strings is left on the pipeline, and an implicit Write-Output gives us newlines for free when the program completes.

Answer 11

05AB1E (legacy), 9 bytes

εINúíJ}û»

Input as list of characters.

Try it online or verify all test cases.

Explanation:

ε     }    # Map each character in the input to:
 I         #  Take the input
  Nú       #  Prepend each with the 0-indexed amount of spaces
           #   i.e. ["t","e","s","t"] & 3 → ["   t","   e","   s","   t"]
    í      #  Reverse each item
           #   i.e. ["   t","   e","   s","   t"] → ["t   ","e   ","s   ","t   "]
     J     #  Join them together to a single string
           #   i.e. ["t   ","e   ","s   ","t   "] → "t   e   s   t   "
       û»  # Palindromize the list, and join by newlines
           #  i.e. ["test","t e s t ","t  e  s  t  ","t   e   s   t   "]
           #   → "test\nt e s t \nt  e  s  t  \nt   e   s   t   \nt  e  s  t  \nt e s t \ntest"

Answer 12

MATL, 25 22 13 bytes

zZv"Gtz@he!1e

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Thanks to Luis Mendo for suggesting a 5 byte golf, which then inspired me to shave off 4 more bytes!

Explanation, with example input 'abc':

         # Implicit input, 'abc'
z        # find number of nonzero elements (length of string)
         # stack: [3]
Zv       # symmetric range
         # stack: [[1 2 3 2 1]]
"        # begin for loop, iterating over [1 2 3 2 1] as the loop indices
G        # push input
         # stack: ['abc']
tz       # dup and push length
         # stack: ['abc', 3]
@        # push loop index, i (for example, 2)
         # stack: ['abc', 3, 2]
h        # horizontally concatenate
         # stack: ['abc', [3, 2]]
e!       # reshape to matrix of 3 rows and i columns, padding with spaces, and transpose
         # stack: [['abc';'   ';'   ']]
1e       # reshape to matrix of 1 row, leaving last value on stack
         # stack: ['a  b  c  ']
         # implicit end of for loop
         # implicit end of program, display stack contents

Answer 13

Haskell, 60 59 bytes

(init<>reverse).(scanl(?)<*>tail)
a?_=do u<-a;u:[' '|' '<u]

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Explanation

For a string (eg. "abc") we apply first

scanl (?) <*> tail

which is the same as

\str -> scanl (?) str (tail str)

This repeatedly applies (?) (appends a space to each character in the range [33..]) to the str until there are that many strings as str has characters: ["abc","a b c ", "a b c "]

Now we only need to concatenate the result (minus the last element) with its reversed counter part:

init<>reverse

Answer 14

Java (JDK 10), 115 bytes

s->{for(int l=s.length(),i=-l;++i<l;)System.out.printf(s.replaceAll(".","%-"+(i<0?l+i:l-i)+"s")+"%n",s.split(""));}

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• -2 bytes thanks to Kevin Cruijssen

Answer 15

Jelly, 9 bytes

jⱮLḶ⁶ẋƲŒḄ

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Returns a list of lines; output prettified over TIO.

Answer 16

Pyth, 12 bytes

Just my mandatory Pyth submission. I am quite proud of this so an explanation will likely come soon.

+P_=jRQ*L;_U

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+P_=jRQ_.e*d

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Answer 17

K (oK), 25 24 bytes

Solution:

,/'(1+a,1_|a:!#x)$\:+,x:

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Explanation:

Port of my K4 solution:

,/'(1+a,1_|a:!#x)$\:+,x: / the solution
                      x: / save input as x
                     ,   / enlist
                    +    / flip
                 $\:     / pad ($) right by each-left (\:)
   (            )        / do this together
              #x         / count length of input,           e.g. 3
             !           / range 0..length,                 e.g. 0 1 2
           a:            / save as a
          |              / reverse it,                      e.g. 2 1 0
        1_               / drop first,                      e.g. 1 0
      a,                 / join to a,                       e.g. 0 1 2 1 0
    1+                   / add 1,                           e.g. 1 2 3 2 1
,/'                      / flatten (,/) each (')

Notes:

• -1 byte thanks to ngn

Answer 18

Stax, 10 bytes

Ç·9ƒù▌╘Ä┘e

Run and debug it

Outputs with trailing whitespace on each line.

Explanation:

%R|pmx{]n(m Full program, unpacked, implicit input
%           Length of input
 R          1-based range
  |p        Palindromize
    m       Map:
     x{   m   Map over characters of input:
       ]        Character -> string
        n(      Right-pad to length given by outer map value
              Implicit flatten and output

Answer 19

Pascal (FPC), 143 135 bytes

var s:string;i,j,l:word;begin read(s);l:=length(s);repeat i:=i+1;for j:=1to l do write(s[j],'':l-abs(l-i)-1);writeln until i=l*2-1 end.

Try it online!

I will probably win only against Lenguage...

Answer 20

PHP, 88 89 bytes

for(;++$i<2*$e=count($a=str_split($argn));)echo join(str_pad("",~-$e-abs($i-$e)),$a),"\n";

requires PHP 5 or later for str_split. Run as pipe with -nR or try it online.

Answer 21

K4, 23 bytes

Solution:

,/'(1+a,1_|a:!#x)$\:$x:

Example:

q)k),/'(1+a,1_|a:!#x)$\:$x:"Spaceship"
"Spaceship"
"S p a c e s h i p "
"S  p  a  c  e  s  h  i  p  "
"S   p   a   c   e   s   h   i   p   "
"S    p    a    c    e    s    h    i    p    "
"S     p     a     c     e     s     h     i     p     "
"S      p      a      c      e      s      h      i      p      "
"S       p       a       c       e       s       h       i       p       "
"S        p        a        c        e        s        h        i        p        "
"S       p       a       c       e       s       h       i       p       "
"S      p      a      c      e      s      h      i      p      "
"S     p     a     c     e     s     h     i     p     "
"S    p    a    c    e    s    h    i    p    "
"S   p   a   c   e   s   h   i   p   "
"S  p  a  c  e  s  h  i  p  "
"S p a c e s h i p "
"Spaceship"

Explanation:

Has trailing whitespace on each line.

,/'(1+a,1_|a:!#x)$\:$x: / the solution
                     x: / save input as x,                 e.g. "abc"
                    $   / string,                          e.g. (,"a";,"b";,"c")
                 $\:    / pad ($) right by each-left (\:)
   (            )       / do this together
              #x        / count length of input,           e.g. 3
             !          / range 0..length,                 e.g. 0 1 2
           a:           / save as a
          |             / reverse it,                      e.g. 2 1 0
        1_              / drop first,                      e.g. 1 0
      a,                / join to a,                       e.g. 0 1 2 1 0
    1+                  / add 1,                           e.g. 1 2 3 2 1
,/'                     / flatten each

Answer 22

C (gcc), 131 129 111 bytes

i;x;f(k,j)char*k,*j;{x=strlen(k)-1;for(i=0;i<x-~x;i+=puts(""))for(j=k;*j;)printf("%c%*s",*j++,i<x?i:2*x-i,"");}

Try it online!

-20 bytes thanks to ceilingcat!

#import<string.h>
i;x;f(k,j)char*k,*j;{x=strlen(k)-1;for(i=0;i<x-~x;i+=puts(""))for(j=k;*j;)printf("%c%*s",*j++,i<x?i:2*x-i,"");}

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Or, if length can be accepted as a parameter:

C (gcc), 105 102 bytes

-1 byte thanks to ceilingcat!

i;x;f(k,x,j)char*k,*j;{for(i=!x--;i<x-~x;i+=puts(""))for(j=k;*j;)printf("%c%*s",*j++,i<x?i:2*x-i,"");}

Try it online!

Answer 23

C#, 113 105 98 bytes

s=>{for(int l=s.Length,i=-l;++i<l;)WriteLine(Join("",s.Select(c=>$"{c}".PadRight(i<0?l+i:l-i))));}

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Answer 24

Scala, 82 bytes

for(i<-(0 to a.size)union(-a.size to 0))println(a.map(_+" "*Math.abs(i)).mkString)

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Scala has lot of shortcuts that are helping me here and that is quite readable! Try Scala

Answer 25

8086 machine code, 56 53 bytes

00000000  bf 35 01 57 ba 01 00 52  be 82 00 b3 ff ac 59 51  |.5.W...R......YQ|
00000010  aa 3c 0d 74 07 b0 20 e2  f7 43 eb f1 b0 0a aa 59  |.<.t.. ..C.....Y|
00000020  00 d1 e3 08 38 cb d6 08  c2 51 eb dc c6 05 24 5a  |....8....Q....$Z|
00000030  b4 09 cd 21 c3                                    |...!.|
00000035

Assembled from:

org 0x100
use16
        mov di, buffer
        push di
        mov dx, 1
        push dx
nextl:  mov si, 0x82
        mov bl, -1
nextc:  lodsb
        pop cx
        push cx
stor:   stosb
        cmp al, 0x0d
        je cr
        mov al, ' '
        loop stor
        inc bx
        jmp nextc
cr:     mov al, 0x0a
        stosb
        pop cx
        add cl, dl
        jcxz done
        cmp bl, cl
        salc
        or dl, al
        push cx
        jmp nextl
done:   mov [di], byte '$'
        pop dx
        mov ah, 0x09
        int 0x21
        ret
buffer:

Test case:

Answer 26

Oracle SQL, 115 bytes

Not a golfing language but...

SELECT TRIM(REGEXP_REPLACE(v,'(.)',LPAD('\1',1+LENGTH(v)-ABS(LEVEL-LENGTH(v)))))FROM t CONNECT BY LEVEL<2*LENGTH(v)

Assuming that the value is in column v of table t:

SQL Fiddle

Oracle 11g R2 Schema Setup:

CREATE TABLE t ( v ) AS
  SELECT 'test' FROM DUAL;

Query 1:

SELECT TRIM(REGEXP_REPLACE(v,'(.)',LPAD('\1',1+LENGTH(v)-ABS(LEVEL-LENGTH(v)))))
FROM   t
CONNECT BY LEVEL<2*LENGTH(v)

Results:

(SQLFiddle prints the values right-aligned in the column for some reason... there are no leading spaces)

| TRIM(REGEXP_REPLACE(V,'(.)',LPAD('\1',1+LENGTH(V)-ABS(LEVEL-LENGTH(V))))) |
|---------------------------------------------------------------------------|
|                                                                      test |
|                                                                   t e s t |
|                                                                t  e  s  t |
|                                                             t   e   s   t |
|                                                                t  e  s  t |
|                                                                   t e s t |
|                                                                      test |

Answer 27

Haskell, 64 60 59 bytes

(""#)
a#s|l<-(:a)=<<s,w<-' ':a=l:[x|w<(' '<$s),x<-w#s++[l]]

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a#s                         -- take a string of spaces 'a' and the input string 's'
 |l<-(:a)=<<s               -- let 'l' be the current line, i.e. the spaces in 'a'
                            -- appended to each char in 's'
  w<-' ':a                  -- let 'w' be 'a' with an additional space   
 =l                         -- return that 'l'
   :[   |w<(' '<$s)   ]     -- and, if 'w' is shorter than 's',
     x  ,x<-w#s++[l]        -- followed by a recursive call with 'w' 
                            -- and by another copy of 'l'

(""#)                       -- start with an empty 'a'

Answer 28

PHP, 148 146 143 141 Bytes

function s($s){for(;$i<strlen($s);++$i)f($i,$s);for(--$i;--$i>=0;)f($i,$s);}function f($i,$s){echo chunk_split($s,1,str_repeat(' ',$i))."
";}

You can test it like this:

<?php
error_reporting(0);

$s = 1234567890;
function s($s){for(;$i<strlen($s);++$i)f($i,$s);for(--$i;--$i>=0;)f($i,$s);}function f($i,$s){echo chunk_split($s,1,str_repeat(' ',$i))."
";}

Output

1234567890
1 2 3 4 5 6 7 8 9 0 
1  2  3  4  5  6  7  8  9  0  
1   2   3   4   5   6   7   8   9   0   
1    2    3    4    5    6    7    8    9    0    
1     2     3     4     5     6     7     8     9     0     
1      2      3      4      5      6      7      8      9      0      
1       2       3       4       5       6       7       8       9       0       
1        2        3        4        5        6        7        8        9        0        
1         2         3         4         5         6         7         8         9         0         
1        2        3        4        5        6        7        8        9        0        
1       2       3       4       5       6       7       8       9       0       
1      2      3      4      5      6      7      8      9      0      
1     2     3     4     5     6     7     8     9     0     
1    2    3    4    5    6    7    8    9    0    
1   2   3   4   5   6   7   8   9   0   
1  2  3  4  5  6  7  8  9  0  
1 2 3 4 5 6 7 8 9 0 
1234567890

Sandbox

Expanded version

 function s($s){
    //loop upwards 0-10
    for(;$i<strlen($s);++$i) f($i,$s);
     //decrement so it's odd, from 9 loop downwards to 0
    for(--$i;--$i>=0;)f($i,$s);
 }
 //2nd function to save space
 function f($i,$s){
     //chunk it, split 1 char, insert $i number of spaces
     echo chunk_split($s,1,str_repeat(' ',$i))."
";}

Attempt 2, 92 bytes

after seeing @Titus answer I reduced mine to this:

for(;++$i<2*$e=strlen($s=$argn);)echo chunk_split($s,1,str_repeat(' ',~-$e-abs($i-$e)))."
";

I was trying to think of a way to use 1 loop, instead of 2... Believe it or not, I almost never use the for loop in "real" code. It was the ~ bitwise Not, that I was missing...

It's sill a tiny bit longer at 92 so I don't feel so bad. But I will put it in as a second attempt anyway.

$argn is the input from the command line

Run as pipe with -nR or try it online.

Sandbox

Answer 29

Bash, 115, 109, 105, 100, 97, 96, 92, 91, 90 bytes

-5 & -3 thanks to Kevin Cruissen

read s;for((c=f=1;f;c-=2*(f>=${#s}),f+=c))
{ printf '%-'${f}'.c' `grep -o .<<<"$s"`
echo
}

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---

Note that since the \ is a shell escape char, the test case )}/\ should be entered with an extra \ like this: )}/\\.

Answer 30

Perl 6, 43 bytes

{(0....comb-1...0)>>.&{join ' 'x$^a,.comb}}

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Returns a list of lines.

Explanation:

 {                                         }  # Anonymous code block
  (0....comb-1...0) # A list from
   0                  # 0
    ...               # to
       .comb-1        # the length of the input string -1
              ...     # back to
                 0    # 0
                   >>.&{                  }  # Map each number to
                        join        ,.comb   # Join the list of characters
                             ' 'x$^a         # With the number of spaces

Answer 31

Python 2, 67 bytes

s=input()
r=range(len(s))
for i in r+r[-2::-1]:print(' '*i).join(s)

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Answer 32

C (gcc), 135 133 129 112 bytes

#define L{for(k=0;s[k];)printf("%c%*s",s[k++],i,"");puts("");}
i;k;f(char*s){for(i=0;s[i];i++)L for(--i;~--i;)L}

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-2 bytes from Kevin Cruijssen

-4 bytes from ceilingcat

-17 bytes from ceilingcat

Ungolfed:

int i, k;
int f(char *s){
    for(i = 0; s[i] != '\x00'; i++) {
        for(k = 0; s[k] != '\x00'; k++) {
            printf("%c%*s", s[k], i, "");
            // print the character followed by the empty string padded with i spaces
        }
        putchar('\n');
    }
    for(i = i-2; i > -1; --i) {
        for(k = 0; s[k] != '\x00'; k++) {
            printf("%c%*s", s[k], i, "");
            // print the character followed by the empty string padded with i spaces
        }
        putchar('\n');
    }
}

Answer 33

Red, 86 bytes

func[s][repeat n l: 2 *(length? s)- 1[foreach c s[prin pad c min n l - n + 1]print""]]

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Answer 34

Clean, 87 81 bytes

-2 thanks to Kevin Cruijssen

import StdEnv,Text
$s#l=length s
=[concat[rpad{c}(l-abs i)' '\\c<-s]\\i<-[~l..l]]

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Answer 35

Attache, 26 bytes

Bounce@{Join[_,Iota@_*sp]}

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Explanation

Bounce@{Join[_,Iota@_*sp]}

       {                 }    anonymous lambda. input: _ (character array)
        Join[_,         ]     join each character by (vectorizes)
               Iota@_           the indices of _ (0 ... #_)
                     *sp        repeat a space by each index
Bounce@                       bounce the results (append reverse, but middle only once)

Answer 36

Brainbash, 142 bytes

-[-[-<]>>+<]>-<++++++++++>>*,+[~+~->,+]~[-*[.~>[-<<.>>>+<]>[<->+]<<~>]~>+<<<.>>]>--[->+<<+>]>[-<+>]<<+[-*[.~>[-<<.>>>+<]>[<->+]<<~>]~>-<<<.>>]

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In one block:

-[-[-<]>>+<]>-<++++++++++>>*,+[~+~->,+]~[-*[.~>[-<<.>>>+<]>[<->+]<<~>]~
>+<<<.>>]>--[->+<<+>]>[-<+>]<<+[-*[.~>[-<<.>>>+<]>[<->+]<<~>]~>-<<<.>>]

Explanation

-[-[-<]>>+<]>-          constant for 32
<++++++++++             constant for 10
>>                      move to counter
*                       swap tapes while retaining pointer
,+[~+~->,+]             take input in tape while keeping track of how many characters
~                       move to counter on other tape
[                       repeat counter times:
    -                       update counter
    *                       swap tapes
    [                       for each character:
        .                       output it
        ~>[                     repeat secondary counter times:
            -                       update secondary counter
            <<.                     output a space
            >>>+<                   make a copy of the secondary counter
        ]
        >[<->+]                 restore secondary counter    
        <<~>                return to counter
    ]
    ~>+<<<.>>           update ternary counter and output a newline
]

>--                     fix offset

[->+<<+>]>[-<+>]<<+     various counter restoring

    [-*[.~>[-<
    <.>>>+<]>[
    <->+]<<~>]
    ~>-<<<.>>]          same as above but subtracting instead of adding

Answer 37

T-SQL, 215 214 bytes

DECLARE @v CHAR(32),@p VARCHAR(999),@ INT,@j INT,@k INT
SELECT @v=v,@=LEN(v),@j=-@+1FROM t
r:SET @p=''SET @k=1c:SET @p+=SUBSTRING(@v,@k,1)+SPACE(@+~ABS(@j))SET @k+=1
IF @k!>@ GOTO c
PRINT @p
SET @j+=1IF @j<@ GOTO r

Per our IO rules, input is taken from a pre-existing table t with varchar field v. Max size I've allowed is 32 characters, which tops out with the middle line being 32*31=992 characters long.

I've used a pure brute force nested-loop (using GOTO which is shorter than WHILE) with manual string construction, not very SQL-like at all. Still the best I could do (MS T-SQL has no native support for REGEX, except using CLR assemblies and manually importing System.Text.RegularExpressions).

EDIT: Here's the output for input "test":

test
t e s t 
t  e  s  t  
t   e   s   t   
t  e  s  t  
t e s t 
test

And here's a partial screenshot of the output for input "abcdefghijklmnopqrstuvwxyz":

Answer 38

Perl 5 + -M5.010 -nlF, 34 bytes

$,=$"x($#F-abs),say@F for-$#F..$#F

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Answer 39

Pip -l, 14 9 bytes

aJsXPZ,#a

Takes the input string as a command-line argument. Try it online!

Note: the PZ operator is newer than this question.

Explanation

WIth example input abc:

           a is 1st cmdline arg; s is space (implicit)
      ,#a  Range(length(a))
           [0; 1; 2]
    PZ     Palindromize (append the reverse, but without doubling the center item)
           [0; 1; 2; 1; 0]
  sX       Repeat space that many times (vectorized)
           [""; " "; "  "; " "; ""]
aJ         Join a on those strings (vectorized)
           ["abc"; "a b c"; "a  b  c"; "a b c"; "abc"]
           Print (implicit)
           Each list element is printed on its own line, due to -l flag

Answer 40

JavaScript (Node.js), 102 100 98 96 bytes

f=(s,n=s.length,m=n+--n)=>[...Array(m)].map((_,i)=>[...s].join(` `.repeat(i<n?i:2*n-i))).join`

-2 by using [...]
-2 from @Kevin
-2 by tweak @Kevin

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Answer 41

Lua: 132 characters

a=io.read()s=' 'l=function(o,n,z)for j=o,n,z do c=''for _,i in ipairs(a)do 
c=c..i..s:rep(j)end print(c)end end l(0,#a,1)l(#a-1,0,-1)

Long form:

a=io.read() -- using the input as a table, lua's version of arrays (and 
-- using it like an array anyway) Not 100% sure this is how the input goes
space=' ' -- need to declare this it seems so we can repeat it a number of times 
later
l = function(initialNumSpaces,maxNumSpaces,increment) 
for j=initialNumSpaces, maxNumSpaces, increment do 
  collector=''
  for _,i in ipairs(a)do  -- loop through the inputted string char by char
     collector=collector..i..space:rep(j) -- concat the char and spaces
  end 
  print(collector) -- print the collector
end 
end
l(0,#a,1) -- call the first half of the spaceship
l(#a-1,0,-1) -- call the second half of the spaceship